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DSA Javascriptprogramming~5 mins

Peek Front Element of Queue in DSA Javascript - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What does the 'peek' operation do in a queue?
It shows the front element of the queue without removing it, so you can see who is next without changing the queue.
Click to reveal answer
beginner
Why is peek useful in a queue?
Peek lets you check the next item to be processed without changing the order or removing it, like looking at the first person in line without letting them go.
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beginner
In a queue implemented with an array, how do you peek the front element?
You look at the element at index 0, because the front of the queue is always the first element in the array.
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beginner
What happens if you peek an empty queue?
Usually, you get a special value like null or undefined to show the queue is empty and there is no front element.
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beginner
Show the JavaScript code to peek the front element of a queue stored as an array named 'queue'.
const front = queue.length > 0 ? queue[0] : null;
console.log(front);
Click to reveal answer
What does the peek operation return in a queue?
AAdds a new element at the front
BThe last element and removes it
CRemoves all elements
DThe front element without removing it
If a queue is empty, what should peek return?
Anull or undefined
BThe first element
CAn error always
DThe last element
In a queue implemented as an array, which index holds the front element?
Alength - 1
B0
C1
Dlength / 2
What is the difference between peek and dequeue in a queue?
ADequeue removes the front element, peek does not
BBoth add elements
CBoth remove the front element
DPeek removes the front element, dequeue does not
Which of these is a correct JavaScript code to peek the front element of a queue array named 'queue'?
Aconst front = queue[queue.length - 1];
Bconst front = queue.pop();
Cconst front = queue[0];
Dconst front = queue.push();
Explain how to peek the front element of a queue and why it is useful.
Think about looking at the first person in line without letting them go.
You got /4 concepts.
    Write a simple JavaScript code snippet to peek the front element of a queue stored as an array.
    Use a conditional (ternary) operator to handle empty queue.
    You got /4 concepts.

      Practice

      (1/5)
      1. What does the peek operation do in a queue?
      easy
      A. Returns the front element without removing it
      B. Removes the front element from the queue
      C. Adds a new element to the back of the queue
      D. Checks if the queue is empty

      Solution

      1. Step 1: Understand the peek operation

        The peek operation looks at the front element of the queue but does not remove it.
      2. Step 2: Compare with other queue operations

        Removing is done by dequeue, adding by enqueue, and checking empty is a separate check.
      3. Final Answer:

        Returns the front element without removing it -> Option A
      4. Quick Check:

        Peek = front element without removal [OK]
      Hint: Peek shows front without changing queue [OK]
      Common Mistakes:
      • Confusing peek with dequeue
      • Thinking peek adds elements
      • Assuming peek checks emptiness
      2. Which of the following is the correct syntax to peek the front element of a queue named myQueue in JavaScript if it is implemented as an array?
      easy
      A. myQueue.peek()
      B. myQueue[0]
      C. myQueue.front()
      D. myQueue.getFront()

      Solution

      1. Step 1: Understand array-based queue front access

        In JavaScript, arrays use index 0 for the first element, so myQueue[0] accesses the front.
      2. Step 2: Check other options for validity

        Methods like peek(), front(), or getFront() are not standard array methods.
      3. Final Answer:

        myQueue[0] -> Option B
      4. Quick Check:

        Array front element = index 0 [OK]
      Hint: Use index 0 to peek front in array queue [OK]
      Common Mistakes:
      • Using non-existent methods on arrays
      • Using wrong index like myQueue[1]
      • Confusing peek with dequeue method
      3. What will be the output of the following code?
      const queue = [];
      queue.push(10);
      queue.push(20);
      queue.push(30);
      console.log(queue[0]);
      medium
      A. 10
      B. 20
      C. 30
      D. undefined

      Solution

      1. Step 1: Understand queue insertion using push

        Elements 10, 20, 30 are added to the end of the array, so queue = [10, 20, 30].
      2. Step 2: Access front element using index 0

        queue[0] returns the first element, which is 10.
      3. Final Answer:

        10 -> Option A
      4. Quick Check:

        Front element after pushes = 10 [OK]
      Hint: Front element is first pushed value at index 0 [OK]
      Common Mistakes:
      • Thinking last pushed element is front
      • Using queue.pop() instead of queue[0]
      • Confusing index 0 with index 1
      4. Identify the error in the following code that tries to peek the front element of a queue implemented as an array:
      const queue = [5, 15, 25];
      function peek() {
        return queue.pop();
      }
      console.log(peek());
      medium
      A. queue is not defined inside peek()
      B. pop() returns undefined for non-empty arrays
      C. peek() should use queue.push() instead
      D. Using pop() removes the last element instead of peeking the front

      Solution

      1. Step 1: Understand pop() behavior on arrays

        pop() removes and returns the last element, not the front.
      2. Step 2: Correct way to peek front element

        To peek front, access queue[0] without removing it.
      3. Final Answer:

        Using pop() removes the last element instead of peeking the front -> Option D
      4. Quick Check:

        pop() removes last, not front [OK]
      Hint: pop() removes last; peek front uses index 0 [OK]
      Common Mistakes:
      • Using pop() to peek front
      • Confusing pop() with shift()
      • Trying to push in peek function
      5. You have a queue implemented as an array: let q = [100, 200, 300]. You want to peek the front element safely, but the queue might be empty sometimes. Which code snippet correctly peeks the front element without causing an error?
      hard
      A. console.log(q.pop());
      B. console.log(q[0]);
      C. console.log(q.length > 0 ? q[0] : 'Queue is empty');
      D. console.log(q.shift());

      Solution

      1. Step 1: Check for empty queue before peeking

        Accessing q[0] when empty returns undefined but may be unclear; better to check length.
      2. Step 2: Use conditional to safely peek front

        Using q.length > 0 ? q[0] : 'Queue is empty' returns front if exists, else message.
      3. Final Answer:

        console.log(q.length > 0 ? q[0] : 'Queue is empty'); -> Option C
      4. Quick Check:

        Safe peek uses length check before access [OK]
      Hint: Check length before peek to avoid errors [OK]
      Common Mistakes:
      • Peeking without checking empty queue
      • Using pop() or shift() which remove elements
      • Assuming q[0] always exists
      Recommended

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