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DSA Javascriptprogramming~10 mins

Peek Front Element of Queue in DSA Javascript - Build from Scratch

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Peek Front Element of Queue
📖 Scenario: You are managing a line of customers waiting to buy tickets at a movie theater. You want to check who is at the front of the line without removing them.
🎯 Goal: Build a simple queue using an array and write code to peek at the front element (the first customer in line) without removing them.
📋 What You'll Learn
Create a queue array with exact customers in order
Create a variable to hold the front element
Write code to peek at the front element without removing it
Print the front element
💡 Why This Matters
🌍 Real World
Queues are used in real life to manage lines, like customers waiting for service or tasks waiting to be processed.
💼 Career
Understanding queues is important for software developers to manage data flow, scheduling, and resource management efficiently.
Progress0 / 4 steps
1
Create the queue array
Create an array called queue with these exact customers in order: 'Alice', 'Bob', 'Charlie', 'Diana'.
DSA Javascript
Hint

Use square brackets [] to create an array and separate names with commas.

2
Create a variable for the front element
Create a variable called front and set it to null for now.
DSA Javascript
Hint

Use let to create a variable that can change later.

3
Peek the front element of the queue
Set the variable front to the first element of the queue array without removing it.
DSA Javascript
Hint

Use queue[0] to access the first element of the array.

4
Print the front element
Print the value of the variable front using console.log.
DSA Javascript
Hint

Use console.log(front); to print the front element.

Practice

(1/5)
1. What does the peek operation do in a queue?
easy
A. Returns the front element without removing it
B. Removes the front element from the queue
C. Adds a new element to the back of the queue
D. Checks if the queue is empty

Solution

  1. Step 1: Understand the peek operation

    The peek operation looks at the front element of the queue but does not remove it.
  2. Step 2: Compare with other queue operations

    Removing is done by dequeue, adding by enqueue, and checking empty is a separate check.
  3. Final Answer:

    Returns the front element without removing it -> Option A
  4. Quick Check:

    Peek = front element without removal [OK]
Hint: Peek shows front without changing queue [OK]
Common Mistakes:
  • Confusing peek with dequeue
  • Thinking peek adds elements
  • Assuming peek checks emptiness
2. Which of the following is the correct syntax to peek the front element of a queue named myQueue in JavaScript if it is implemented as an array?
easy
A. myQueue.peek()
B. myQueue[0]
C. myQueue.front()
D. myQueue.getFront()

Solution

  1. Step 1: Understand array-based queue front access

    In JavaScript, arrays use index 0 for the first element, so myQueue[0] accesses the front.
  2. Step 2: Check other options for validity

    Methods like peek(), front(), or getFront() are not standard array methods.
  3. Final Answer:

    myQueue[0] -> Option B
  4. Quick Check:

    Array front element = index 0 [OK]
Hint: Use index 0 to peek front in array queue [OK]
Common Mistakes:
  • Using non-existent methods on arrays
  • Using wrong index like myQueue[1]
  • Confusing peek with dequeue method
3. What will be the output of the following code?
const queue = [];
queue.push(10);
queue.push(20);
queue.push(30);
console.log(queue[0]);
medium
A. 10
B. 20
C. 30
D. undefined

Solution

  1. Step 1: Understand queue insertion using push

    Elements 10, 20, 30 are added to the end of the array, so queue = [10, 20, 30].
  2. Step 2: Access front element using index 0

    queue[0] returns the first element, which is 10.
  3. Final Answer:

    10 -> Option A
  4. Quick Check:

    Front element after pushes = 10 [OK]
Hint: Front element is first pushed value at index 0 [OK]
Common Mistakes:
  • Thinking last pushed element is front
  • Using queue.pop() instead of queue[0]
  • Confusing index 0 with index 1
4. Identify the error in the following code that tries to peek the front element of a queue implemented as an array:
const queue = [5, 15, 25];
function peek() {
  return queue.pop();
}
console.log(peek());
medium
A. queue is not defined inside peek()
B. pop() returns undefined for non-empty arrays
C. peek() should use queue.push() instead
D. Using pop() removes the last element instead of peeking the front

Solution

  1. Step 1: Understand pop() behavior on arrays

    pop() removes and returns the last element, not the front.
  2. Step 2: Correct way to peek front element

    To peek front, access queue[0] without removing it.
  3. Final Answer:

    Using pop() removes the last element instead of peeking the front -> Option D
  4. Quick Check:

    pop() removes last, not front [OK]
Hint: pop() removes last; peek front uses index 0 [OK]
Common Mistakes:
  • Using pop() to peek front
  • Confusing pop() with shift()
  • Trying to push in peek function
5. You have a queue implemented as an array: let q = [100, 200, 300]. You want to peek the front element safely, but the queue might be empty sometimes. Which code snippet correctly peeks the front element without causing an error?
hard
A. console.log(q.pop());
B. console.log(q[0]);
C. console.log(q.length > 0 ? q[0] : 'Queue is empty');
D. console.log(q.shift());

Solution

  1. Step 1: Check for empty queue before peeking

    Accessing q[0] when empty returns undefined but may be unclear; better to check length.
  2. Step 2: Use conditional to safely peek front

    Using q.length > 0 ? q[0] : 'Queue is empty' returns front if exists, else message.
  3. Final Answer:

    console.log(q.length > 0 ? q[0] : 'Queue is empty'); -> Option C
  4. Quick Check:

    Safe peek uses length check before access [OK]
Hint: Check length before peek to avoid errors [OK]
Common Mistakes:
  • Peeking without checking empty queue
  • Using pop() or shift() which remove elements
  • Assuming q[0] always exists
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