Bird
Raised Fist0
DSA Javascriptprogramming~20 mins

Hash Map vs Array vs Linked List for Lookup in DSA Javascript - Compare & Choose

Choose your learning style10 modes available
Challenge - 5 Problems
🎖️
Lookup Mastery
Get all challenges correct to earn this badge!
Test your skills under time pressure!
❓ Predict Output
intermediate
2:00remaining
Lookup Time Complexity in Different Data Structures
Consider the following JavaScript code snippets that perform lookup operations. Which option correctly shows the output time complexity for each data structure?
DSA Javascript
const array = [1, 2, 3, 4, 5];
const linkedList = { head: { value: 1, next: { value: 2, next: null } } };
const hashMap = new Map([[1, 'a'], [2, 'b'], [3, 'c']]);
AArray: O(n), Linked List: O(n), Hash Map: O(1)
BArray: O(1), Linked List: O(1), Hash Map: O(n)
CArray: O(n), Linked List: O(1), Hash Map: O(n)
DArray: O(1), Linked List: O(n), Hash Map: O(1)
Attempts:
2 left
💡 Hint
Think about how each data structure stores and accesses elements.
🧠 Conceptual
intermediate
1:30remaining
Best Data Structure for Fast Lookup by Key
Which data structure is best suited for fast lookup by a unique key in JavaScript?
ALinked List
BArray
CHash Map
DStack
Attempts:
2 left
💡 Hint
Consider which structure uses keys to access values directly.
❓ Predict Output
advanced
2:00remaining
Output of Lookup in Linked List vs Array
What will be the output of the following JavaScript code?
DSA Javascript
const array = [10, 20, 30, 40];
const linkedList = { value: 10, next: { value: 20, next: { value: 30, next: null } } };

function lookupArray(arr, target) {
  return arr.includes(target);
}

function lookupLinkedList(node, target) {
  while (node !== null) {
    if (node.value === target) return true;
    node = node.next;
  }
  return false;
}

console.log(lookupArray(array, 30));
console.log(lookupLinkedList(linkedList, 40));
Afalse\ntrue
Btrue\nfalse
Ctrue\ntrue
Dfalse\nfalse
Attempts:
2 left
💡 Hint
Check if the target exists in each data structure.
🔧 Debug
advanced
1:30remaining
Identify the Error in Hash Map Lookup Code
What error will the following JavaScript code produce when trying to lookup a key in a hash map?
DSA Javascript
const hashMap = new Map([[1, 'one'], [2, 'two']]);

function getValue(key) {
  return hashMap[key];
}

console.log(getValue(1));
AReturns 'one'
BTypeError
CReferenceError
Dundefined
Attempts:
2 left
💡 Hint
How do you access values in a Map object?
🧠 Conceptual
expert
2:00remaining
Why Linked List Lookup is Slower than Hash Map Lookup
Why is lookup in a linked list generally slower than lookup in a hash map?
ALinked list stores elements sequentially and requires traversal; hash map uses hashing for direct access.
BLinked list uses hashing internally; hash map uses sequential search.
CLinked list lookup is faster because it uses pointers; hash map lookup requires scanning all keys.
DLinked list stores elements in a tree structure; hash map stores elements in an array.
Attempts:
2 left
💡 Hint
Think about how each data structure finds an element.

Practice

(1/5)
1. Which data structure provides the fastest average lookup time for finding an element by key?
easy
A. Hash Map
B. Array
C. Linked List
D. Stack

Solution

  1. Step 1: Understand lookup times for each data structure

    Hash Maps use keys to directly access values, giving average O(1) time. Arrays require scanning or index access, O(n) or O(1) if index known. Linked Lists require scanning, O(n).
  2. Step 2: Compare average lookup speeds

    Hash Map is fastest for key-based lookup because it uses hashing. Arrays and Linked Lists are slower for key lookup.
  3. Final Answer:

    Hash Map -> Option A
  4. Quick Check:

    Fastest lookup by key = Hash Map [OK]
Hint: Hash Map uses keys for O(1) lookup, arrays and lists do not [OK]
Common Mistakes:
  • Thinking arrays are always fastest because of index access
  • Confusing linked list traversal with direct access
  • Assuming stack is a lookup structure
2. Which of the following is the correct way to check if a key exists in a JavaScript Map?
easy
A. map.includes(key)
B. key in map
C. map.contains(key)
D. map.has(key)

Solution

  1. Step 1: Recall JavaScript Map methods

    JavaScript Map has a method called has() to check if a key exists.
  2. Step 2: Evaluate each option

    map.has(key) uses map.has(key) which is correct. 'key in map' works for objects, not Map. 'contains' and 'includes' are not Map methods.
  3. Final Answer:

    map.has(key) -> Option D
  4. Quick Check:

    Check key in Map = map.has(key) [OK]
Hint: Use map.has(key) to check keys in JavaScript Map [OK]
Common Mistakes:
  • Using 'in' operator on Map instead of Object
  • Using non-existent methods like contains or includes on Map
  • Confusing array methods with Map methods
3. What will be the output of the following code?
const arr = [10, 20, 30, 40];
const map = new Map();
map.set('a', 1);
map.set('b', 2);

console.log(arr.indexOf(30));
console.log(map.has('b'));
console.log(map.get('c'));
medium
A. 2 true null
B. -1 false undefined
C. 2 true undefined
D. 3 true undefined

Solution

  1. Step 1: Analyze array indexOf(30)

    Array arr is [10,20,30,40]. indexOf(30) returns 2 because 30 is at index 2.
  2. Step 2: Check map.has('b') and map.get('c')

    map.has('b') is true because 'b' exists. map.get('c') returns undefined because 'c' key does not exist.
  3. Final Answer:

    2 true undefined -> Option C
  4. Quick Check:

    indexOf(30)=2, has('b')=true, get('c')=undefined [OK]
Hint: indexOf returns index or -1; Map.get returns undefined if key missing [OK]
Common Mistakes:
  • Assuming map.get returns null for missing keys
  • Confusing array index with value
  • Thinking map.has returns value instead of boolean
4. The following code tries to find if a value exists in a linked list. What is the bug?
class Node {
  constructor(value) {
    this.value = value;
    this.next = null;
  }
}

function contains(head, target) {
  if (head === null) return false;
  while (head.next !== null) {
    if (head.value === target) return true;
    head = head.next;
  }
  return false;
}
medium
A. It misses checking the last node's value
B. It causes infinite loop
C. It throws an error on empty list
D. It incorrectly compares values

Solution

  1. Step 1: Understand the loop condition

    The loop runs while head.next !== null, so it stops before the last node.
  2. Step 2: Check if last node is checked

    Because loop stops before last node, last node's value is never checked, so target in last node is missed.
  3. Final Answer:

    It misses checking the last node's value -> Option A
  4. Quick Check:

    Loop condition excludes last node check [OK]
Hint: Loop until node is null, not node.next [OK]
Common Mistakes:
  • Using head.next !== null instead of head !== null
  • Assuming last node is checked inside loop
5. You need to frequently check if a user ID exists and also maintain the order of insertion. Which data structure is best suited for this in JavaScript?
hard
A. Array
B. Map
C. Linked List
D. Set

Solution

  1. Step 1: Understand requirements

    We need fast existence check and order preservation of user IDs.
  2. Step 2: Compare data structures

    Array preserves order but slow lookup (O(n)). Linked List preserves order but slow lookup (O(n)). Map preserves order and fast lookup by key and stores key-value pairs. Set preserves insertion order and fast lookup for unique values but does not store key-value pairs.
  3. Step 3: Choose best fit

    Map stores key-value pairs, preserves insertion order, and offers O(1) lookup, making it ideal for checking existence and maintaining order.
  4. Final Answer:

    Map -> Option B
  5. Quick Check:

    Fast lookup + order + key-value = Map [OK]
Hint: Use Map for key-value pairs with order and fast lookup [OK]
Common Mistakes:
  • Choosing Set when key-value pairs are needed
  • Using Array and expecting fast lookup
  • Confusing Linked List order with lookup speed
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard