Create and Initialize Doubly Linked List in DSA Java - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare the head of a doubly linked list.

DSA Java

Node [1];

Drag options to blanks, or click blank then click option'

Ahead

Btail

Cnext

Dprev

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'next' or 'prev' as the list head variable.

Using 'tail' instead of 'head' for the start of the list.

The head is the starting node of a doubly linked list, so we declare it as 'head'.

2fill in blank

medium

Complete the constructor to initialize a new node with given data.

DSA Java

public Node(int data) {
    this.data = data;
    this.[1] = null;
    this.prev = null;
}

Drag options to blanks, or click blank then click option'

Anext

Bprev

Chead

Dtail

Attempts:

3 left

💡 Hint

Common Mistakes

Initializing 'prev' twice instead of 'next'.

Using 'head' or 'tail' inside the node constructor.

The 'next' pointer should be initialized to null in the node constructor.

3fill in blank

hard

Fix the error in the method that adds a new node at the beginning of the doubly linked list.

DSA Java

public void addFirst(int data) {
    Node newNode = new Node(data);
    newNode.next = head;
    if (head != null) {
        head.[1] = newNode;
    }
    head = newNode;
}

Drag options to blanks, or click blank then click option'

Ahead

Bnext

Cprev

Dtail

Attempts:

3 left

💡 Hint

Common Mistakes

Setting 'next' instead of 'prev' for the old head.

Forgetting to update the old head's pointer.

When adding at the front, the old head's 'prev' should point back to the new node.

4fill in blank

hard

Fill both blanks to complete the method that adds a new node at the end of the doubly linked list.

DSA Java

public void addLast(int data) {
    Node newNode = new Node(data);
    if (head == null) {
        head = newNode;
        return;
    }
    Node temp = head;
    while (temp.[1] != null) {
        temp = temp.[2];
    }
    temp.next = newNode;
    newNode.prev = temp;
}

Drag options to blanks, or click blank then click option'

Anext

Bprev

Chead

Dtail

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'prev' to traverse forward, which is incorrect.

Using 'head' or 'tail' inside the loop incorrectly.

To reach the last node, we follow 'next' pointers until null is found.

5fill in blank

hard

Fill both blanks to complete the method that prints the doubly linked list from head to tail.

DSA Java

public void printList() {
    Node temp = head;
    while (temp != null) {
        System.out.print(temp.[1] + " <-> ");
        temp = temp.[2];
    }
    System.out.println("null");
}

Drag options to blanks, or click blank then click option'

Adata

Bnext

Cprev

Dhead

Attempts:

3 left

💡 Hint

Common Mistakes

Printing 'next' or 'prev' instead of 'data'.

Moving backward using 'prev' instead of forward using 'next'.

We print the 'data' of each node and move forward using 'next'.

Practice

1. What is the main difference between a singly linked list and a doubly linked list?

easy

A. A doubly linked list does not allow traversal in reverse order.

B. A doubly linked list has nodes with pointers to both previous and next nodes.

C. A doubly linked list stores data in arrays instead of nodes.

D. A doubly linked list only has a pointer to the next node.

Solution

1. Step 1: Understand node pointers in linked lists

   A singly linked list node has one pointer to the next node only.

2. Step 2: Identify doubly linked list node pointers

   A doubly linked list node has two pointers: one to the next node and one to the previous node.

3. Final Answer:

   A doubly linked list has nodes with pointers to both previous and next nodes. -> Option B

4. Quick Check:

   Doubly linked list = two pointers per node [OK]

Hint: Remember: doubly linked means two directions [OK]

Common Mistakes:

• Confusing singly and doubly linked list pointers
• Thinking doubly linked lists use arrays
• Assuming doubly linked lists cannot go backward

2. Which of the following is the correct way to declare a node class for a doubly linked list in Java?

easy

A. class Node { int data; Node next; Node prev; }

B. class Node { int data; Node next; }

C. class Node { int data; Node prev; }

D. class Node { int data; Node next; Node previous; }

Solution

1. Step 1: Check node fields for doubly linked list

   A doubly linked list node must have data, next pointer, and previous pointer.

2. Step 2: Match correct field names

   class Node { int data; Node next; Node prev; } uses 'next' and 'prev' which are standard and consistent.

3. Final Answer:

   class Node { int data; Node next; Node prev; } -> Option A

4. Quick Check:

   Node has data, next, and prev [OK]

Hint: Node needs both next and prev pointers [OK]

Common Mistakes:

• Omitting prev pointer in node class
• Using inconsistent pointer names
• Confusing singly linked list node with doubly linked

3. What will be the output of the following Java code that creates a doubly linked list with nodes 10, 20, 30 and prints it forward?

class Node {
  int data;
  Node next;
  Node prev;
  Node(int d) { data = d; next = null; prev = null; }
}

public class Main {
  public static void main(String[] args) {
    Node head = new Node(10);
    Node second = new Node(20);
    Node third = new Node(30);
    head.next = second; second.prev = head;
    second.next = third; third.prev = second;

    Node current = head;
    while(current != null) {
      System.out.print(current.data + " -> ");
      current = current.next;
    }
    System.out.print("null");
  }
}

medium

A. 30 -> 20 -> 10 -> null

B. null -> 10 -> 20 -> 30

C. 10 -> 20 -> 30 -> null

D. 10 -> 20 -> null

Solution

1. Step 1: Understand list creation and linking

   Nodes 10, 20, 30 are linked forward: 10.next=20, 20.next=30.

2. Step 2: Trace the print loop

   Starting at head (10), print data then move to next until null: prints 10 -> 20 -> 30 -> null.

3. Final Answer:

   10 -> 20 -> 30 -> null -> Option C

4. Quick Check:

   Forward traversal prints nodes in insertion order [OK]

Hint: Follow next pointers from head to null [OK]

Common Mistakes:

• Printing in reverse order by mistake
• Missing last node in output
• Confusing prev and next pointers

4. Identify the error in the following code snippet that tries to create a doubly linked list with nodes 1 and 2:

class Node {
  int data;
  Node next;
  Node prev;
  Node(int d) { data = d; next = null; prev = null; }
}

public class Main {
  public static void main(String[] args) {
    Node head = new Node(1);
    Node second = new Node(2);
    head.next = second;
    // Missing line here
    System.out.println(head.next.data);
  }
}

medium

A. Missing assignment of second.prev to head

B. Node constructor is missing initialization

C. head.next should be assigned to null

D. Cannot print data without a loop

Solution

1. Step 1: Check linking between nodes

   head.next is assigned second, but second.prev is not set to head.

2. Step 2: Identify missing backward link

   For doubly linked list, second.prev must point back to head to maintain two-way links.

3. Final Answer:

   Missing assignment of second.prev to head -> Option A

4. Quick Check:

   Both next and prev must be linked [OK]

Hint: Check both next and prev pointers after linking nodes [OK]

Common Mistakes:

• Forgetting to link prev pointer
• Assuming next pointer is enough
• Ignoring bidirectional links in doubly linked list

5. You want to create a doubly linked list from an array of integers [5, 10, 15] in Java. Which approach correctly initializes the list with proper next and prev links?

hard

A. Create nodes in a loop, link each node's next to the previous node, and set previous node's prev to current node.

B. Create nodes in a loop, link each node's prev to the next node, and set next node's next to current node.

C. Create nodes in a loop, link each node's prev to null, and next to null.

D. Create nodes in a loop, link each node's next to the next node, and set next node's prev to current node.

Solution

1. Step 1: Create nodes from array elements

   For each integer, create a new node with data set to that integer.

2. Step 2: Link nodes forward and backward

   Set current node's next to next node, and next node's prev to current node to maintain doubly linked structure.

3. Final Answer:

   Create nodes in a loop, link each node's next to the next node, and set next node's prev to current node. -> Option D

4. Quick Check:

   Proper doubly linked list needs next and prev links set correctly [OK]

Hint: Link next forward and prev backward in loop [OK]

Common Mistakes:

• Mixing up next and prev pointers
• Not setting prev pointer at all
• Setting prev pointer incorrectly to next node