Create and Initialize Doubly Linked List in DSA Java - Time & Space Complexity

Time Complexity: Create and Initialize Doubly Linked List

O(n^2)

Understanding Time Complexity

When we create and initialize a doubly linked list, we want to know how the time needed grows as we add more elements.

We ask: How much work does it take to build this list as it gets bigger?

Scenario Under Consideration

Analyze the time complexity of the following code snippet.

class Node {
  int data;
  Node prev, next;
  Node(int d) { data = d; prev = next = null; }
}

class DoublyLinkedList {
  Node head;
  void add(int data) {
    Node newNode = new Node(data);
    if (head == null) {
      head = newNode;
    } else {
      Node temp = head;
      while (temp.next != null) temp = temp.next;
      temp.next = newNode;
      newNode.prev = temp;
    }
  }
}
    

This code creates a doubly linked list and adds new nodes at the end one by one.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

• Primary operation: The while loop that moves to the end of the list to add a new node.
• How many times: For each add, it may traverse all existing nodes to find the end.

How Execution Grows With Input

Each new node added requires walking through the list to find the end, so the work grows as the list grows.

Input Size (n)	Approx. Operations
10	About 1+2+...+10 = 55 steps
100	About 5050 steps
1000	About 500,500 steps

Pattern observation: The total steps grow roughly like the square of the number of nodes.

Final Time Complexity

Time Complexity: O(n2)

This means adding n nodes one by one at the end takes time proportional to n squared, because each add walks through the list.

Common Mistake

[X] Wrong: "Adding each node is always a quick constant time operation."

[OK] Correct: Without keeping track of the tail, each add must find the end by walking through the list, which takes longer as the list grows.

Interview Connect

Understanding how adding nodes affects time helps you design better data structures and shows you can spot inefficiencies in code.

Self-Check

"What if we kept a reference to the tail node? How would the time complexity change when adding nodes?"

Practice

1. What is the main difference between a singly linked list and a doubly linked list?

easy

A. A doubly linked list does not allow traversal in reverse order.

B. A doubly linked list has nodes with pointers to both previous and next nodes.

C. A doubly linked list stores data in arrays instead of nodes.

D. A doubly linked list only has a pointer to the next node.

Solution

1. Step 1: Understand node pointers in linked lists

   A singly linked list node has one pointer to the next node only.

2. Step 2: Identify doubly linked list node pointers

   A doubly linked list node has two pointers: one to the next node and one to the previous node.

3. Final Answer:

   A doubly linked list has nodes with pointers to both previous and next nodes. -> Option B

4. Quick Check:

   Doubly linked list = two pointers per node [OK]

Hint: Remember: doubly linked means two directions [OK]

Common Mistakes:

• Confusing singly and doubly linked list pointers
• Thinking doubly linked lists use arrays
• Assuming doubly linked lists cannot go backward

2. Which of the following is the correct way to declare a node class for a doubly linked list in Java?

easy

A. class Node { int data; Node next; Node prev; }

B. class Node { int data; Node next; }

C. class Node { int data; Node prev; }

D. class Node { int data; Node next; Node previous; }

Solution

1. Step 1: Check node fields for doubly linked list

   A doubly linked list node must have data, next pointer, and previous pointer.

2. Step 2: Match correct field names

   class Node { int data; Node next; Node prev; } uses 'next' and 'prev' which are standard and consistent.

3. Final Answer:

   class Node { int data; Node next; Node prev; } -> Option A

4. Quick Check:

   Node has data, next, and prev [OK]

Hint: Node needs both next and prev pointers [OK]

Common Mistakes:

• Omitting prev pointer in node class
• Using inconsistent pointer names
• Confusing singly linked list node with doubly linked

3. What will be the output of the following Java code that creates a doubly linked list with nodes 10, 20, 30 and prints it forward?

class Node {
  int data;
  Node next;
  Node prev;
  Node(int d) { data = d; next = null; prev = null; }
}

public class Main {
  public static void main(String[] args) {
    Node head = new Node(10);
    Node second = new Node(20);
    Node third = new Node(30);
    head.next = second; second.prev = head;
    second.next = third; third.prev = second;

    Node current = head;
    while(current != null) {
      System.out.print(current.data + " -> ");
      current = current.next;
    }
    System.out.print("null");
  }
}

medium

A. 30 -> 20 -> 10 -> null

B. null -> 10 -> 20 -> 30

C. 10 -> 20 -> 30 -> null

D. 10 -> 20 -> null

Solution

1. Step 1: Understand list creation and linking

   Nodes 10, 20, 30 are linked forward: 10.next=20, 20.next=30.

2. Step 2: Trace the print loop

   Starting at head (10), print data then move to next until null: prints 10 -> 20 -> 30 -> null.

3. Final Answer:

   10 -> 20 -> 30 -> null -> Option C

4. Quick Check:

   Forward traversal prints nodes in insertion order [OK]

Hint: Follow next pointers from head to null [OK]

Common Mistakes:

• Printing in reverse order by mistake
• Missing last node in output
• Confusing prev and next pointers

4. Identify the error in the following code snippet that tries to create a doubly linked list with nodes 1 and 2:

class Node {
  int data;
  Node next;
  Node prev;
  Node(int d) { data = d; next = null; prev = null; }
}

public class Main {
  public static void main(String[] args) {
    Node head = new Node(1);
    Node second = new Node(2);
    head.next = second;
    // Missing line here
    System.out.println(head.next.data);
  }
}

medium

A. Missing assignment of second.prev to head

B. Node constructor is missing initialization

C. head.next should be assigned to null

D. Cannot print data without a loop

Solution

1. Step 1: Check linking between nodes

   head.next is assigned second, but second.prev is not set to head.

2. Step 2: Identify missing backward link

   For doubly linked list, second.prev must point back to head to maintain two-way links.

3. Final Answer:

   Missing assignment of second.prev to head -> Option A

4. Quick Check:

   Both next and prev must be linked [OK]

Hint: Check both next and prev pointers after linking nodes [OK]

Common Mistakes:

• Forgetting to link prev pointer
• Assuming next pointer is enough
• Ignoring bidirectional links in doubly linked list

5. You want to create a doubly linked list from an array of integers [5, 10, 15] in Java. Which approach correctly initializes the list with proper next and prev links?

hard

A. Create nodes in a loop, link each node's next to the previous node, and set previous node's prev to current node.

B. Create nodes in a loop, link each node's prev to the next node, and set next node's next to current node.

C. Create nodes in a loop, link each node's prev to null, and next to null.

D. Create nodes in a loop, link each node's next to the next node, and set next node's prev to current node.

Solution

1. Step 1: Create nodes from array elements

   For each integer, create a new node with data set to that integer.

2. Step 2: Link nodes forward and backward

   Set current node's next to next node, and next node's prev to current node to maintain doubly linked structure.

3. Final Answer:

   Create nodes in a loop, link each node's next to the next node, and set next node's prev to current node. -> Option D

4. Quick Check:

   Proper doubly linked list needs next and prev links set correctly [OK]

Hint: Link next forward and prev backward in loop [OK]

Common Mistakes:

• Mixing up next and prev pointers
• Not setting prev pointer at all
• Setting prev pointer incorrectly to next node