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Two Sum Problem Classic Hash Solution in DSA Go - Time & Space Complexity

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Time Complexity: Two Sum Problem Classic Hash Solution
O(n)
Understanding Time Complexity

We want to understand how the time needed to find two numbers that add up to a target grows as the list gets bigger.

How does the solution's speed change when the input size increases?

Scenario Under Consideration

Analyze the time complexity of the following code snippet.

func twoSum(nums []int, target int) []int {
    seen := make(map[int]int)
    for i, num := range nums {
        complement := target - num
        if j, ok := seen[complement]; ok {
            return []int{j, i}
        }
        seen[num] = i
    }
    return nil
}

This code finds two numbers in the list that add up to the target using a hash map for quick lookups.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

  • Primary operation: Single loop through the list of numbers.
  • How many times: Exactly once for each number in the list.
  • Additional operation: Constant-time hash map lookups and insertions inside the loop.
How Execution Grows With Input

As the list grows, the number of steps grows roughly the same as the list size.

Input Size (n)Approx. Operations
10About 10 loop steps and 10 hash operations
100About 100 loop steps and 100 hash operations
1000About 1000 loop steps and 1000 hash operations

Pattern observation: The work grows linearly with the input size; doubling the list roughly doubles the work.

Final Time Complexity

Time Complexity: O(n)

This means the time to find the two numbers grows in direct proportion to the size of the input list.

Common Mistake

[X] Wrong: "Because there is a loop inside a loop, the time complexity is O(n²)."

[OK] Correct: The code uses a hash map for quick lookups, so it does not have a nested loop; each lookup is fast and does not depend on the list size.

Interview Connect

Understanding this solution shows you how to use extra space to speed up searching, a common and useful skill in coding problems.

Self-Check

"What if the input list was already sorted? How would that change the time complexity if we used a two-pointer approach instead?"

Practice

(1/5)
1. What is the main idea behind the Two Sum Problem Classic Hash Solution?
easy
A. Use a hash map to store numbers and their indices for quick lookup
B. Sort the array and use two pointers to find the sum
C. Use nested loops to check every pair of numbers
D. Use recursion to find pairs that add up to the target

Solution

  1. Step 1: Understand the problem goal

    The goal is to find two numbers in the array that add up to a target value.
  2. Step 2: Use a hash map for efficient lookup

    By storing each number and its index in a hash map, we can check if the complement (target - current number) exists quickly.
  3. Final Answer:

    Use a hash map to store numbers and their indices for quick lookup -> Option A
  4. Quick Check:

    Hash map lookup = fast pair finding [OK]
Hint: Use a hash map to find complements quickly [OK]
Common Mistakes:
  • Trying to use nested loops which is slower
  • Sorting the array which is unnecessary here
  • Not storing indices with numbers
2. Which of the following Go code snippets correctly initializes a hash map to store integers as keys and values?
easy
A. var m map[int]int
B. m := map[int]int
C. m := make(map[int]int)
D. m := map[int]int(make())

Solution

  1. Step 1: Recall Go map initialization syntax

    Maps in Go are initialized using the built-in make function like make(map[keyType]valueType).
  2. Step 2: Identify correct syntax

    m := make(map[int]int) uses make(map[int]int) which is the correct way to create an empty map with int keys and int values.
  3. Final Answer:

    m := make(map[int]int) -> Option C
  4. Quick Check:

    make(map[int]int) = correct map init [OK]
Hint: Use make(map[key]value) to create maps in Go [OK]
Common Mistakes:
  • Using var without make causes nil map
  • Incorrect syntax like map[int]int(make())
  • Using empty braces without make in some contexts
3. What will be the output of the following Go code snippet?
func twoSum(nums []int, target int) []int {
    m := make(map[int]int)
    for i, num := range nums {
        if j, ok := m[target-num]; ok {
            return []int{j, i}
        }
        m[num] = i
    }
    return nil
}

fmt.Println(twoSum([]int{2, 7, 11, 15}, 9))
medium
A. [1 0]
B. [0 1]
C. [2 3]
D. nil

Solution

  1. Step 1: Trace the loop and map updates

    At i=0, num=2, map is empty, so store m[2]=0.
    At i=1, num=7, check if m[9-7=2] exists, yes at index 0.
    Return [0,1].
  2. Step 2: Confirm returned indices

    The function returns indices of numbers 2 and 7 which sum to 9, so output is [0 1].
  3. Final Answer:

    [0 1] -> Option B
  4. Quick Check:

    Indices of 2 and 7 = [0 1] [OK]
Hint: Check map for complement before inserting current number [OK]
Common Mistakes:
  • Returning indices in wrong order
  • Not checking map before insertion
  • Returning nil when pair exists
4. Identify the error in the following Go code for the Two Sum problem:
func twoSum(nums []int, target int) []int {
    m := make(map[int]int)
    for i, num := range nums {
        if j, ok := m[num-target]; ok {
            return []int{j, i}
        }
        m[num] = i
    }
    return nil
}
medium
A. The complement calculation should be target - num, not num - target
B. The map should store num + target as key
C. The map initialization is incorrect
D. The return statement should return nil earlier

Solution

  1. Step 1: Analyze complement calculation

    The complement to find is target - current number, not num - target, because we want a number that adds with num to target.
  2. Step 2: Identify the fix

    Change m[num-target] to m[target-num] to correctly check for the complement in the map.
  3. Final Answer:

    The complement calculation should be target - num, not num - target -> Option A
  4. Quick Check:

    Complement = target - num [OK]
Hint: Complement = target minus current number [OK]
Common Mistakes:
  • Swapping target and num in complement
  • Incorrect map initialization
  • Returning nil too early
5. Given the input array nums = [3, 3, 4, 2] and target 6, what will the Two Sum Classic Hash Solution return?
Consider the code below:
func twoSum(nums []int, target int) []int {
    m := make(map[int]int)
    for i, num := range nums {
        if j, ok := m[target-num]; ok {
            return []int{j, i}
        }
        m[num] = i
    }
    return nil
}
medium
A. nil
B. [1 2]
C. [2 3]
D. [0 1]

Solution

  1. Step 1: Trace the loop with given input

    i=0, num=3, map empty, store m[3]=0.
    i=1, num=3, check m[6-3=3], found at index 0, return [0,1].
  2. Step 2: Confirm returned indices

    Indices 0 and 1 correspond to values 3 and 3 which sum to 6, so output is [0 1].
  3. Final Answer:

    [0 1] -> Option D
  4. Quick Check:

    3 + 3 = 6 at indices [0 1] [OK]
Hint: Check map for complement before inserting current number [OK]
Common Mistakes:
  • Assuming different pairs without checking map
  • Returning nil when pair exists
  • Confusing indices order
Recommended

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