String to Integer atoi in DSA Go - Time & Space Complexity
We want to understand how the time to convert a string to an integer grows as the string gets longer.
How does the number of steps change when the input string size increases?
Analyze the time complexity of the following code snippet.
func myAtoi(s string) int {
i, n := 0, len(s)
sign := 1
result := 0
// Skip spaces
for i < n && s[i] == ' ' {
i++
}
// Check sign
if i < n {
if s[i] == '-' {
sign = -1
i++
} else if s[i] == '+' {
i++
}
}
// Convert digits
for i < n && s[i] >= '0' && s[i] <= '9' {
result = result*10 + int(s[i]-'0')
i++
}
return sign * result
}
This code converts a string to an integer by skipping spaces, checking the sign, and then reading digits one by one.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: The loops that scan characters in the string.
- How many times: Each loop runs at most once over the string characters, moving forward without going back.
As the input string gets longer, the code checks each character once until it finishes or stops at a non-digit.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | About 10 character checks |
| 100 | About 100 character checks |
| 1000 | About 1000 character checks |
Pattern observation: The number of steps grows roughly in direct proportion to the string length.
Time Complexity: O(n)
This means the time to convert grows linearly with the length of the input string.
[X] Wrong: "The conversion takes constant time because it just reads the number."
[OK] Correct: The code must check each character to decide if it is a digit and to build the number, so time depends on input length.
Understanding this linear time behavior helps you explain how string parsing scales and shows you can analyze simple loops clearly.
"What if the input string was guaranteed to have only digits and no spaces or signs? How would the time complexity change?"
Practice
atoi function do in the context of strings and integers?Solution
Step 1: Understand the purpose of atoi
The function atoi stands for ASCII to integer, meaning it converts a string of digits into an integer number.Step 2: Compare options with definition
Only Converts a string representing a number into an integer value correctly describes converting a numeric string to an integer value.Final Answer:
Converts a string representing a number into an integer value -> Option BQuick Check:
atoi converts string to int [OK]
- Confusing atoi with integer to string conversion
- Thinking atoi splits strings
- Assuming atoi validates string digits only
"1234" to an integer using strconv.Atoi?Solution
Step 1: Check function signature of strconv.Atoi
It returns two values: an integer and an error, so both must be captured.Step 2: Verify argument type
The argument must be a string, so "1234" is correct, not 1234 (int).Final Answer:
num, err := strconv.Atoi("1234") -> Option AQuick Check:
Correct syntax captures int and error [OK]
- Not capturing the error return value
- Passing an integer instead of a string
- Using single return variable for two returns
package main
import (
"fmt"
"strconv"
)
func main() {
s := "-42"
num, err := strconv.Atoi(s)
if err != nil {
fmt.Println("Error")
} else {
fmt.Println(num)
}
}Solution
Step 1: Understand input string and conversion
The string "-42" is a valid integer representation including a negative sign.Step 2: Check error handling and output
Since "-42" is valid, err will be nil and num will be -42, so it prints -42.Final Answer:
-42 -> Option AQuick Check:
Valid negative string converts to negative int [OK]
- Assuming negative sign causes error
- Expecting absolute value output
- Ignoring error check
strconv.Atoi:
package main
import (
"fmt"
"strconv"
)
func main() {
s := "12a4"
num, _ := strconv.Atoi(s)
fmt.Println(num)
}Solution
Step 1: Analyze input string validity
The string "12a4" contains a letter 'a', so it is not a valid integer string.Step 2: Check error handling in code
The code ignores the error by using underscore _, so it prints zero value 0 without warning.Final Answer:
Ignoring the error returned by strconv.Atoi -> Option DQuick Check:
Always check error when converting strings [OK]
- Assuming invalid strings convert to partial numbers
- Ignoring error causes silent wrong output
- Thinking fmt.Println usage is wrong
["10", "-5", "abc", "20"] to integers using strconv.Atoi. Which approach correctly handles invalid strings and collects only valid integers?Solution
Step 1: Understand the problem requirements
We must convert multiple strings to integers and skip invalid ones safely.Step 2: Evaluate each option's correctness
Loop over strings, convert each with strconv.Atoi, append to result only if error is nil correctly loops, converts, checks error, and appends valid integers only.Final Answer:
Loop over strings, convert each with strconv.Atoi, append to result only if error is nil -> Option CQuick Check:
Check error for each conversion before appending [OK]
- Appending invalid conversions without error check
- Using strconv.Itoa which converts int to string
- Ignoring invalid strings completely
Ready to prove it?
Pass the test and this pattern moves unknown
