String Reversal Approaches in DSA Go - Time & Space Complexity

Time Complexity: String Reversal Approaches

O(n)

Understanding Time Complexity

We want to understand how the time needed to reverse a string changes as the string gets longer.

How does the work grow when the input string size increases?

Scenario Under Consideration

Analyze the time complexity of the following code snippet.

package main

func reverseString(s string) string {
    runes := []rune(s)
    for i, j := 0, len(runes)-1; i < j; i, j = i+1, j-1 {
        runes[i], runes[j] = runes[j], runes[i]
    }
    return string(runes)
}

This code reverses a string by swapping characters from the start and end moving towards the center.

Identify Repeating Operations

Identify the loops, recursion, array traversals that repeat.

• Primary operation: The for loop swaps characters from both ends moving inward.
• How many times: It runs about half the length of the string (n/2 times).

How Execution Grows With Input

As the string gets longer, the number of swaps grows roughly in direct proportion to its length.

Input Size (n)	Approx. Operations
10	5 swaps
100	50 swaps
1000	500 swaps

Pattern observation: Doubling the string length roughly doubles the number of swaps needed.

Final Time Complexity

Time Complexity: O(n)

This means the time to reverse the string grows linearly with the string length.

Common Mistake

[X] Wrong: "Reversing a string takes constant time because we just swap characters."

[OK] Correct: Each character must be visited and swapped, so the time grows with string length, not fixed.

Interview Connect

Understanding how string reversal scales helps you reason about similar problems involving arrays or strings, a common skill interviewers look for.

Self-Check

"What if we used recursion to reverse the string? How would the time complexity change?"

Practice

1. What does the strings.Reverse function do in Go if it existed? (Assume it reverses the string.)

easy

A. It converts the string to uppercase.

B. It returns the input string with characters in reverse order.

C. It removes all vowels from the string.

D. It splits the string into words.

Solution

1. Step 1: Understand the function name and purpose

   The function name Reverse suggests it changes the order of characters.

2. Step 2: Interpret the expected behavior

   Reversing a string means the last character becomes first, and so on.

3. Final Answer:

   It returns the input string with characters in reverse order. -> Option B

4. Quick Check:

   Reverse means flip order [OK]

Hint: Reverse means flip the order of characters [OK]

Common Mistakes:

• Confusing reverse with uppercase conversion
• Thinking reverse removes characters
• Assuming reverse splits words

2. Which of the following Go code snippets correctly reverses a string s?

easy

A. var reversed string
for i := len(s)-1; i >= 0; i-- {
reversed += string(s[i])
}

B. for i := 0; i < len(s); i++ {
reversed += string(s[i])
}

C. reversed := strings.ToUpper(s)

D. reversed := strings.Split(s, " ")

Solution

1. Step 1: Analyze the loop direction

   var reversed string for i := len(s)-1; i >= 0; i-- { reversed += string(s[i]) } loops from the last character to the first, building reversed string.

2. Step 2: Check other options

   for i := 0; i < len(s); i++ { reversed += string(s[i]) } loops forward, so no reversal. reversed := strings.ToUpper(s) changes case, reversed := strings.Split(s, " ") splits words.

3. Final Answer:

   Option A correctly reverses the string. -> Option A

4. Quick Check:

   Loop backward to reverse [OK]

Hint: Loop backward from end to start to reverse [OK]

Common Mistakes:

• Looping forward instead of backward
• Using string functions that don't reverse
• Confusing splitting with reversing

3. What is the output of this Go code?

func main() {
  s := "hello"
  reversed := ""
  for i := len(s) - 1; i >= 0; i-- {
    reversed += string(s[i])
  }
  fmt.Println(reversed)
}

medium

A. olleh

B. hello

C. h

D. error

Solution

1. Step 1: Trace the loop from end to start

   The loop starts at index 4 ('o') and goes to 0 ('h'), appending characters in reverse order.

2. Step 2: Build the reversed string

   Characters appended: 'o', 'l', 'l', 'e', 'h' forming "olleh".

3. Final Answer:

   olleh -> Option A

4. Quick Check:

   Reverse of "hello" is "olleh" [OK]

Hint: Reverse string by appending chars from end to start [OK]

Common Mistakes:

• Reading string forward instead of backward
• Printing original string by mistake
• Expecting error due to string indexing

4. Find the error in this Go code that tries to reverse a string s:

func reverse(s string) string {
  var reversed string
  for i := 0; i <= len(s); i++ {
    reversed += string(s[len(s)-i])
  }
  return reversed
}

medium

A. The function should return reversed as a byte slice.

B. The string concatenation should use +=.

C. The loop condition should be i < len(s), not <=.

D. The loop should start from len(s) and go down to 0.

Solution

1. Step 1: Check loop bounds

   The loop runs from 0 to len(s) inclusive, but string indices go from 0 to len(s)-1.

2. Step 2: Identify out-of-range index

   Accessing s[len(s)-i] when i=0 is s[len(s)], which is out of range and causes runtime error.

3. Final Answer:

   The loop condition should be i < len(s), not <=. -> Option C

4. Quick Check:

   Index must be within 0 to len(s)-1 [OK]

Hint: Loop index must stay inside string length bounds [OK]

Common Mistakes:

• Using <= instead of < in loop condition
• Accessing index len(s) which is invalid
• Confusing string and byte slice types

5. Given a string with Unicode characters like "Go语言", which approach correctly reverses it preserving characters properly in Go?

hard

A. Split string by spaces and reverse the words.

B. Use a byte slice and reverse bytes directly.

C. Use strings.ToUpper and then reverse.

D. Convert string to []rune, reverse the rune slice, then convert back to string.

Solution

1. Step 1: Understand Unicode in Go strings

   Go strings are byte sequences; Unicode characters may be multiple bytes.

2. Step 2: Use rune slice to handle Unicode characters

   Converting to []rune treats each Unicode character as one element, safe to reverse.

3. Step 3: Reverse rune slice and convert back

   Reversing []rune reverses characters correctly, then convert back to string.

4. Final Answer:

   Convert string to []rune, reverse runes, then back to string. -> Option D

5. Quick Check:

   Use runes for Unicode-safe reversal [OK]

Hint: Use []rune to reverse Unicode strings safely [OK]

Common Mistakes:

• Reversing bytes breaks Unicode characters
• Using uppercase conversion instead of reversing
• Reversing words instead of characters