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DSA Goprogramming~10 mins

Queue vs Stack When to Use Which in DSA Go - Interactive Comparison Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to add an element to the end of a queue.

DSA Go
queue := []int{}
queue = append(queue, [1])
Drag options to blanks, or click blank then click option'
Aelement
B10
C5
Ditem
Attempts:
3 left
💡 Hint
Common Mistakes
Using a number instead of the variable name for the element.
Trying to add to the front of the queue instead of the end.
2fill in blank
medium

Complete the code to remove the last element from a stack.

DSA Go
stack = stack[:len(stack) [1] 1]
Drag options to blanks, or click blank then click option'
A-
B+
C*
D/
Attempts:
3 left
💡 Hint
Common Mistakes
Using addition instead of subtraction.
Using multiplication or division which are incorrect here.
3fill in blank
hard

Fix the error in the code to check if a queue is empty.

DSA Go
if len(queue) [1] 0 {
    fmt.Println("Queue is empty")
}
Drag options to blanks, or click blank then click option'
A!=
B==
C>
D<
Attempts:
3 left
💡 Hint
Common Mistakes
Using != which checks for non-empty.
Using > or < which do not correctly check emptiness.
4fill in blank
hard

Fill both blanks to implement pushing an element onto a stack and then popping it.

DSA Go
stack = append(stack, [1])
last := stack[len(stack) [2] 1]
Drag options to blanks, or click blank then click option'
Aelement
B+
C-
Ditem
Attempts:
3 left
💡 Hint
Common Mistakes
Using '+' instead of '-' when accessing the last element.
Using 'item' instead of 'element' for pushing.
5fill in blank
hard

Fill all three blanks to create a queue, enqueue an element, and dequeue it.

DSA Go
queue := []int{}
queue = append(queue, [1])
dequeued := queue[[2]]
queue = queue[[3]:]
Drag options to blanks, or click blank then click option'
Aelement
B0
C1
Ditem
Attempts:
3 left
💡 Hint
Common Mistakes
Using wrong indices for dequeue.
Using 'item' instead of 'element' for enqueue.

Practice

(1/5)
1. Which data structure should you use when you need to process items in the exact order they arrive, like customers waiting in line?
easy
A. Queue, because it processes items in First-In-First-Out order
B. Stack, because it processes items in Last-In-First-Out order
C. Array, because it allows random access
D. Tree, because it organizes data hierarchically

Solution

  1. Step 1: Understand the order requirement

    Processing items in the exact order they arrive means First-In-First-Out (FIFO).
  2. Step 2: Match data structure to FIFO

    Queue follows FIFO, so it fits the requirement perfectly.
  3. Final Answer:

    Queue, because it processes items in First-In-First-Out order -> Option A
  4. Quick Check:

    FIFO = Queue [OK]
Hint: FIFO means use Queue, like a line at a store [OK]
Common Mistakes:
  • Confusing FIFO with LIFO
  • Choosing Stack for order-sensitive tasks
  • Thinking arrays maintain insertion order automatically
2. Which of the following is the correct way to push an element onto a stack in Go using a slice named stack?
easy
A. stack = append(element, stack...)
B. stack = stack[:len(stack)-1]
C. stack = stack + element
D. stack = append(stack, element)

Solution

  1. Step 1: Recall how to add elements to a slice

    In Go, append(slice, value) adds value to the end of slice.
  2. Step 2: Identify correct push operation

    Pushing onto a stack means adding to the top, which is the end of the slice, so stack = append(stack, element) is correct.
  3. Final Answer:

    stack = append(stack, element) -> Option D
  4. Quick Check:

    Push = append to slice end [OK]
Hint: Use append to add on top of stack slice [OK]
Common Mistakes:
  • Using slicing to add elements instead of append
  • Trying to add element at the front incorrectly
  • Using + operator which is invalid for slices
3. What will be the output of the following Go code snippet?
queue := []int{1, 2, 3}
// Dequeue operation
queue = queue[1:]
fmt.Println(queue)
medium
A. [2 3]
B. []
C. [3]
D. [1 2 3]

Solution

  1. Step 1: Understand the dequeue operation

    Dequeue removes the first element, so slicing from index 1 removes the first element.
  2. Step 2: Apply slicing to queue

    Original queue is [1 2 3], after queue = queue[1:], queue becomes [2 3].
  3. Final Answer:

    [2 3] -> Option A
  4. Quick Check:

    queue[1:] removes first element [OK]
Hint: queue = queue[1:] removes front element [OK]
Common Mistakes:
  • Thinking queue[1:] removes last element
  • Confusing slice syntax with pop operation
  • Expecting original queue unchanged
4. The following Go code intends to pop an element from a stack implemented as a slice. What is the error?
stack := []int{10, 20, 30}
popped := stack[len(stack)]
stack = stack[:len(stack)-1]
fmt.Println(popped, stack)
medium
A. Syntax error due to missing parentheses
B. Index out of range error when accessing stack[len(stack)]
C. Popped element is always zero
D. Stack slice is not updated correctly

Solution

  1. Step 1: Check index used for popping

    Indexing in Go slices is zero-based, so last element is at len(stack)-1, not len(stack).
  2. Step 2: Identify error cause

    Accessing stack[len(stack)] causes index out of range error because it is beyond last index.
  3. Final Answer:

    Index out of range error when accessing stack[len(stack)] -> Option B
  4. Quick Check:

    Last index = len(stack)-1, not len(stack) [OK]
Hint: Last element index is len(slice)-1, not len(slice) [OK]
Common Mistakes:
  • Using len(slice) as index instead of len(slice)-1
  • Not updating slice after pop
  • Confusing pop with dequeue operation
5. You need to design a system that tracks the most recent 5 user actions to allow undo functionality. Which data structure is best and why?
hard
A. Array, because it allows random access to any action
B. Queue, because it keeps actions in order and removes oldest first
C. Stack, because it allows undo by removing the most recent action first
D. Linked list, because it allows fast insertion anywhere

Solution

  1. Step 1: Understand undo functionality

    Undo removes the most recent action first, which is Last-In-First-Out (LIFO) behavior.
  2. Step 2: Match data structure to LIFO

    Stack follows LIFO, so it is best to track recent actions and undo them in reverse order.
  3. Final Answer:

    Stack, because it allows undo by removing the most recent action first -> Option C
  4. Quick Check:

    Undo = LIFO = Stack [OK]
Hint: Undo needs LIFO, so use Stack [OK]
Common Mistakes:
  • Choosing Queue which removes oldest first
  • Thinking array random access helps undo
  • Ignoring order of undo operations
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