Queue Concept and FIFO Principle in DSA Go - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to add an element to the end of the queue.

DSA Go

queue := []int{1, 2, 3}
queue = append(queue, [1])
fmt.Println(queue)

Drag options to blanks, or click blank then click option'

Aqueue[0]

B0

C4

Dlen(queue)

Attempts:

3 left

💡 Hint

Common Mistakes

Appending the first element again instead of a new one.

Using length of queue as element.

Appending 4 adds it to the end of the queue, following FIFO order.

2fill in blank

medium

Complete the code to remove the first element from the queue.

DSA Go

queue := []int{1, 2, 3, 4}
queue = queue[[1]:]
fmt.Println(queue)

Drag options to blanks, or click blank then click option'

A3

B0

C2

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0 which keeps the whole queue.

Using 2 or 3 which removes too many elements.

Removing the first element means slicing from index 1 onward.

3fill in blank

hard

Fix the error in the code to correctly enqueue an element.

DSA Go

queue := []int{5, 6}
queue = append([1], 7)
fmt.Println(queue)

Drag options to blanks, or click blank then click option'

Aqueue

B[]int{7}

Cappend

D7

Attempts:

3 left

💡 Hint

Common Mistakes

Using the value 7 as first argument.

Using append keyword incorrectly.

append needs the slice variable as first argument to add elements.

4fill in blank

hard

Fill both blanks to dequeue the first element and print it.

DSA Go

queue := []int{10, 20, 30}
first := queue[[1]]
queue = queue[[2]:]
fmt.Println(first, queue)

Drag options to blanks, or click blank then click option'

A0

B1

C2

D3

Attempts:

3 left

💡 Hint

Common Mistakes

Using index 1 to get first element.

Slicing from 0 which keeps all elements.

The first element is at index 0, and slicing from 1 removes it from the queue.

5fill in blank

hard

Fill all three blanks to enqueue 40, dequeue first element, and print both.

DSA Go

queue := []int{100, 200, 300}
queue = append(queue, [1])
first := queue[[2]]
queue = queue[[3]:]
fmt.Println(first, queue)

Drag options to blanks, or click blank then click option'

A30

B0

C1

D40

Attempts:

3 left

💡 Hint

Common Mistakes

Appending wrong value.

Using wrong indexes for first element or slicing.

Append 40 to enqueue, get first element at index 0, then slice from 1 to dequeue.

Practice

1. What does the FIFO principle mean in the context of a queue?

easy

A. First In, First Out - the last element added is the first removed

B. First In, First Out - the first element added is the first removed

C. Last In, First Out - the first element added is the last removed

D. Last In, First Out - the last element added is the last removed

Solution

1. Step 1: Understand FIFO meaning

   FIFO means the first element that enters the queue is the first to leave.

2. Step 2: Match FIFO to queue behavior

   Queues follow FIFO, so the first added element is removed first.

3. Final Answer:

   First In, First Out - the first element added is the first removed -> Option B

4. Quick Check:

   FIFO = First In, First Out [OK]

Hint: Remember queue = line; first come, first served [OK]

Common Mistakes:

• Confusing FIFO with LIFO
• Thinking last added is removed first
• Mixing stack behavior with queue

2. Which of the following is the correct way to declare a queue using a slice in Go?

easy

A. queue := []int{}

B. var queue []int

C. queue := make(map[int]int)

D. var queue int

Solution

1. Step 1: Identify slice declaration for queue

   In Go, a queue can be represented as a slice, initialized as empty with []int{}.

2. Step 2: Check options for correct slice syntax

   queue := []int{} uses slice literal syntax to create an empty int slice, suitable for queue.

3. Final Answer:

   queue := []int{} -> Option A

4. Quick Check:

   Slice queue declaration = queue := []int{} [OK]

Hint: Use slice literal []int{} for empty queue [OK]

Common Mistakes:

• Using map instead of slice
• Declaring queue as single int variable
• Using var without initialization for slice

3. What will be the output of the following Go code snippet?

package main
import "fmt"
func main() {
  queue := []int{10, 20, 30}
  // Dequeue operation
  first := queue[0]
  queue = queue[1:]
  fmt.Println(first)
  fmt.Println(queue)
}

medium

A. 10
[10 20 30]

B. 20
[10 30]

C. 10
[20 30]

D. 30
[10 20]

Solution

1. Step 1: Identify dequeue operation

   The first element 10 is stored in 'first', then queue is sliced from index 1 onward.

2. Step 2: Determine output values

   Printing 'first' outputs 10; printing 'queue' outputs remaining slice [20 30].

3. Final Answer:

   10 [20 30] -> Option C

4. Quick Check:

   Dequeue removes first element = 10, queue left = [20 30] [OK]

Hint: Dequeue removes first element, slice queue from index 1 [OK]

Common Mistakes:

• Printing old queue without slicing
• Confusing index positions
• Assuming queue unchanged after dequeue

4. Identify the error in the following Go code that tries to enqueue an element to a queue represented by a slice:

package main
func main() {
  queue := []int{1, 2, 3}
  queue[3] = 4
}

medium

A. Compile error because queue is not declared

B. Syntax error due to missing import statement

C. No error; element 4 is added correctly

D. Index out of range error because slice index 3 does not exist

Solution

1. Step 1: Analyze slice indexing

   Slice 'queue' has length 3 with indices 0,1,2; index 3 is out of range.

2. Step 2: Understand how to add elements

   To add elements, use append(queue, 4) instead of direct index assignment.

3. Final Answer:

   Index out of range error because slice index 3 does not exist -> Option D

4. Quick Check:

   Accessing queue[3] invalid for length 3 slice [OK]

Hint: Use append to add elements, not direct index assignment [OK]

Common Mistakes:

• Trying to assign beyond slice length
• Forgetting to use append for enqueue
• Assuming slice auto-expands on index assignment

5. Given a queue implemented as a slice in Go, how would you write a function to enqueue multiple elements at once while preserving FIFO order? Choose the correct code snippet.

func enqueueMultiple(queue []int, elements []int) []int {
  // Fill in
}

hard

A. return append(queue, elements...)

B. return append(elements, queue...)

C. for _, e := range elements { queue = append([]int{e}, queue...) } return queue

D. queue = elements; return queue

Solution

1. Step 1: Understand enqueue multiple elements

   To add multiple elements preserving order, append all new elements at the end of queue.

2. Step 2: Check code options for correct append usage

   return append(queue, elements...) uses append(queue, elements...) which adds all elements at the end in order.

3. Final Answer:

   return append(queue, elements...) -> Option A

4. Quick Check:

   Appending elements at end preserves FIFO enqueue order [OK]

Hint: Use append(queue, elements...) to add multiple items [OK]

Common Mistakes:

• Appending new elements before queue (wrong order)
• Replacing queue instead of appending
• Appending elements one by one at front