Why Prefix Sum Array in DSA Go?

The Big Idea

What if you could answer any sum question instantly without adding numbers again and again?

The Scenario

Imagine you have a long list of daily sales numbers and you want to quickly find the total sales between any two days. Doing this by adding numbers one by one every time can be tiring and slow.

The Problem

Manually adding numbers for each query means repeating the same additions many times. This wastes time and can cause mistakes, especially if the list is very long or if you have many queries.

The Solution

A prefix sum array keeps track of running totals so you can find the sum between any two points instantly by subtracting two values. This saves time and reduces errors.

Before vs After

✗ Before

func sumRange(arr []int, start int, end int) int {
    total := 0
    for i := start; i <= end; i++ {
        total += arr[i]
    }
    return total
}

✓ After

func buildPrefixSum(arr []int) []int {
    prefix := make([]int, len(arr)+1)
    for i := 1; i <= len(arr); i++ {
        prefix[i] = prefix[i-1] + arr[i-1]
    }
    return prefix
}

func sumRange(prefix []int, start int, end int) int {
    return prefix[end+1] - prefix[start]
}

What It Enables

It enables lightning-fast queries for sums over any range, making your programs much faster and more efficient.

Real Life Example

Online shopping sites use prefix sums to quickly calculate total sales or discounts over different periods without recalculating everything each time.

Key Takeaways

Manual summing is slow and error-prone for repeated queries.

Prefix sum arrays store running totals to answer sum queries instantly.

This technique speeds up programs and reduces mistakes.

Practice

1. What is the main purpose of a prefix sum array in algorithms?

easy

A. To find the maximum element in the array

B. To sort the array elements in ascending order

C. To reverse the array elements efficiently

D. To quickly find the sum of elements in any subarray

Solution

1. Step 1: Understand prefix sum array concept

   A prefix sum array stores cumulative sums of elements from the start to each position.

2. Step 2: Use prefix sums for subarray sums

   Using prefix sums, sum of any subarray can be found quickly by subtracting two prefix sums.

3. Final Answer:

   To quickly find the sum of elements in any subarray -> Option D

4. Quick Check:

   Prefix sum array helps fast subarray sums [OK]

Hint: Prefix sums store cumulative sums for fast subarray queries [OK]

Common Mistakes:

• Confusing prefix sum with sorting
• Thinking prefix sum reverses array
• Assuming prefix sum finds max element

2. Which of the following Go code snippets correctly initializes a prefix sum array prefix from an integer slice arr?

easy

A. prefix := make([]int, len(arr))
for i := 0; i < len(arr); i++ {
prefix[i] = prefix[i-1] + arr[i]
}

B. prefix := make([]int, len(arr)+1)
for i := 1; i <= len(arr); i++ {
prefix[i] = prefix[i-1] + arr[i-1]
}

C. prefix := make([]int, len(arr)+1)
for i := 0; i < len(arr); i++ {
prefix[i] = prefix[i-1] + arr[i]
}

D. prefix := make([]int, len(arr))
for i := 1; i < len(arr); i++ {
prefix[i] = prefix[i-1] + arr[i]
}

Solution

1. Step 1: Check prefix array size and indexing

   Prefix sum array usually has length one more than original to handle zero prefix sum at start.

2. Step 2: Verify loop and indexing logic

   Loop from 1 to len(arr), prefix[i] = prefix[i-1] + arr[i-1] correctly accumulates sums.

3. Final Answer:

   prefix := make([]int, len(arr)+1) for i := 1; i <= len(arr); i++ { prefix[i] = prefix[i-1] + arr[i-1] } -> Option B

4. Quick Check:

   Correct prefix sum initialization uses offset indexing [OK]

Hint: Prefix array length = original length + 1, loop starts at 1 [OK]

Common Mistakes:

• Using prefix array same length as original
• Starting loop at 0 and accessing prefix[-1]
• Incorrect indexing of arr inside loop

3. What is the output of the following Go code?

arr := []int{2, 4, 6, 8}
prefix := make([]int, len(arr)+1)
for i := 1; i <= len(arr); i++ {
  prefix[i] = prefix[i-1] + arr[i-1]
}
fmt.Println(prefix)

medium

A. [0 2 6 12 20]

B. [2 6 12 20 28]

C. [0 2 4 6 8]

D. [2 4 6 8 0]

Solution

1. Step 1: Calculate prefix sums step-by-step

   prefix[0]=0
   prefix[1]=0+2=2
   prefix[2]=2+4=6
   prefix[3]=6+6=12
   prefix[4]=12+8=20

2. Step 2: Write final prefix array

   The prefix array is [0, 2, 6, 12, 20]

3. Final Answer:

   [0 2 6 12 20] -> Option A

4. Quick Check:

   Sum accumulates correctly in prefix array [OK]

Hint: Start prefix with 0, add elements cumulatively [OK]

Common Mistakes:

• Forgetting initial zero in prefix array
• Adding wrong elements at each step
• Confusing prefix array length

4. Identify the error in this Go code that tries to build a prefix sum array:

arr := []int{1, 3, 5}
prefix := make([]int, len(arr))
for i := 1; i < len(arr); i++ {
  prefix[i] = prefix[i-1] + arr[i]
}
fmt.Println(prefix)

medium

A. prefix array size should be len(arr)+1

B. Loop should start from i=0 instead of i=1

C. prefix[0] is not initialized before use

D. arr indexing is out of range

Solution

1. Step 1: Check prefix array initialization

   Prefix array is size len(arr), which can work but prefix[0] must be set before use.

2. Step 2: Analyze loop and prefix[0]

   Loop starts at i=1, prefix[1] = prefix[0] + arr[1]. prefix[0] is zero by default in Go, but it should be explicitly set to arr[0] before the loop.

3. Step 3: Check correctness of prefix sums

   prefix[0] is zero, but arr[0] is never added, so prefix sums are incomplete.

4. Final Answer:

   prefix[0] is not initialized before use -> Option C

5. Quick Check:

   Missing prefix[0] initialization causes wrong sums [OK]

Hint: Initialize prefix[0] before loop to avoid wrong sums [OK]

Common Mistakes:

• Not initializing prefix[0]
• Wrong prefix array size
• Incorrect loop start index

5. Given an integer slice arr, how can you use a prefix sum array to find the sum of elements between indices l and r (inclusive) efficiently?

hard

A. sum = prefix[r+1] - prefix[l]

B. sum = prefix[r] - prefix[l-1]

C. sum = prefix[r] + prefix[l]

D. sum = prefix[r+1] + prefix[l-1]

Solution

1. Step 1: Understand prefix sum indexing

   Prefix sum array usually has length len(arr)+1 with prefix[0]=0, prefix[i] = sum of arr[0..i-1].

2. Step 2: Calculate subarray sum using prefix sums

   Sum from l to r = prefix[r+1] - prefix[l] because prefix[r+1] sums up to arr[r].

3. Final Answer:

   sum = prefix[r+1] - prefix[l] -> Option A

4. Quick Check:

   Subarray sum = prefix[r+1] - prefix[l] [OK]

Hint: Use prefix[r+1] - prefix[l] for sum between l and r [OK]

Common Mistakes:

• Using prefix[r] - prefix[l-1] without offset
• Adding prefix sums instead of subtracting
• Confusing indices by 1