Peek Front Element of Queue in DSA Go - Build from Scratch

Peek Front Element of Queue

📖 Scenario: You are managing a line of customers waiting to buy tickets at a counter. You want to check who is the first customer in line without removing them.

🎯 Goal: Build a simple queue using a slice and write code to peek at the front element (the first customer) without removing it.

📋 What You'll Learn

Create a queue as a slice of strings with exact customer names

Create a variable to hold the front element

Write code to peek at the front element of the queue

Print the front element

💡 Why This Matters

🌍 Real World

Queues are used in real life to manage lines, like customers waiting for service or tasks waiting to be processed.

💼 Career

Understanding queues and how to peek at elements is important for software developers working with data processing, task scheduling, and user interface event handling.

1

Create the queue with customers

Create a slice of strings called queue with these exact customers in order: "Alice", "Bob", "Charlie", "Diana".

DSA Go

# Create the queue slice with the customers
# Your code here

Hint

Use a slice literal with the exact names in order.

2

Create a variable to hold the front element

Create a variable called front of type string to hold the first element of the queue slice.

DSA Go

package main

func main() {
    queue := []string{"Alice", "Bob", "Charlie", "Diana"}
    // Create variable front to hold the first element
    // Your code here
}

Hint

Initialize front as an empty string first.

3

Peek the front element of the queue

Assign the first element of the queue slice to the variable front using index 0.

DSA Go

package main

func main() {
    queue := []string{"Alice", "Bob", "Charlie", "Diana"}
    var front string
    // Assign the first element of queue to front
    // Your code here
}

Hint

Use queue[0] to get the first element.

4

Print the front element

Use fmt.Println(front) to print the value of the front variable.

DSA Go

package main

import "fmt"

func main() {
    queue := []string{"Alice", "Bob", "Charlie", "Diana"}
    var front string
    front = queue[0]
    // Print the front element
    // Your code here
}

Hint

Use fmt.Println(front) to display the first customer.

Practice

1. What does the Peek operation do in a queue?

easy

A. Returns the front element without removing it

B. Removes the front element from the queue

C. Adds an element to the back of the queue

D. Checks if the queue is empty

Solution

1. Step 1: Understand the queue operations

   A queue supports adding elements at the back and removing from the front.

2. Step 2: Define Peek operation

   Peek returns the front element without removing it, unlike dequeue which removes it.

3. Final Answer:

   Returns the front element without removing it -> Option A

4. Quick Check:

   Peek = front element without removal [OK]

Hint: Peek shows front without removal, unlike dequeue [OK]

Common Mistakes:

• Confusing peek with dequeue
• Thinking peek adds elements
• Assuming peek checks emptiness

2. Which of the following is the correct Go syntax to peek the front element of a queue implemented as a slice named queue?

easy

A. front := queue[len(queue)-1]

B. front := queue[len(queue)]

C. front := queue[0]

D. front := queue.pop()

Solution

1. Step 1: Understand Go slice indexing

   Go slices are zero-indexed, so the first element is at index 0.

2. Step 2: Identify front element access

   The front element of a queue is the first element, so queue[0] gives it.

3. Final Answer:

   front := queue[0] -> Option C

4. Quick Check:

   First element index = 0 [OK]

Hint: Front element is always at index 0 in slice queue [OK]

Common Mistakes:

• Using len(queue) which is out of range
• Using last element instead of first
• Using pop() which is not a Go slice method

3. What will be the output of the following Go code snippet?

queue := []int{10, 20, 30}
front := queue[0]
fmt.Println(front)

medium

A. runtime error

B. 10

C. 30

D. 20

Solution

1. Step 1: Initialize queue slice

   The queue slice contains elements [10, 20, 30].

2. Step 2: Access front element

   front := queue[0] assigns 10 to front.

3. Step 3: Print front

   fmt.Println(front) prints 10.

4. Final Answer:

   10 -> Option B

5. Quick Check:

   queue[0] = 10 [OK]

Hint: queue[0] gives first element value [OK]

Common Mistakes:

• Printing queue[1] instead of queue[0]
• Expecting last element output
• Thinking it causes runtime error

4. Identify the error in this Go code that tries to peek the front element of a queue:

var queue []int
front := queue[0]
fmt.Println(front)

medium

A. No error, prints 0

B. Prints nil

C. Compile-time syntax error

D. Runtime panic: index out of range

Solution

1. Step 1: Check queue initialization

   queue is declared but not initialized, so length is 0.

2. Step 2: Accessing queue[0]

   Accessing queue[0] causes runtime panic because slice is empty.

3. Final Answer:

   Runtime panic: index out of range -> Option D

4. Quick Check:

   Empty slice access causes panic [OK]

Hint: Empty slice access causes runtime panic [OK]

Common Mistakes:

• Assuming default zero value is returned
• Expecting compile-time error
• Thinking it prints nil

5. Given a queue implemented as a slice queue := []int{5, 10, 15}, write the correct Go code snippet to safely peek the front element and handle the empty queue case by printing "Empty" if no elements exist.

hard

A. if len(queue) > 0 {
fmt.Println(queue[0])
} else {
fmt.Println("Empty")
}

B. fmt.Println(queue[0])

C. if queue != nil {
fmt.Println(queue[0])
} else {
fmt.Println("Empty")
}

D. if len(queue) == 0 {
fmt.Println(queue[0])
} else {
fmt.Println("Empty")
}

Solution

1. Step 1: Check queue length before access

   Use len(queue) > 0 to ensure queue has elements.

2. Step 2: Print front or "Empty"

   If queue has elements, print queue[0]; else print "Empty".

3. Final Answer:

   if len(queue) > 0 { fmt.Println(queue[0]) } else { fmt.Println("Empty") } -> Option A

4. Quick Check:

   Check length before access to avoid panic [OK]

Hint: Always check length before peeking front [OK]

Common Mistakes:

• Not checking length before access
• Checking nil instead of length
• Reversing if-else logic