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DSA Goprogramming~10 mins

Memory Layout Comparison Array vs Linked List in DSA Go - Interactive Comparison Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to declare an array of integers with 5 elements in Go.

DSA Go
var numbers [[1]]int
Drag options to blanks, or click blank then click option'
A0
B1
C10
D5
Attempts:
3 left
💡 Hint
Common Mistakes
Using 0 or 1 as array size when 5 is needed.
Confusing array size with slice length.
2fill in blank
medium

Complete the code to define a linked list node struct with an integer value and a pointer to the next node.

DSA Go
type Node struct {
    value int
    next *[1]
}
Drag options to blanks, or click blank then click option'
ANode
Bint
CList
DPointer
Attempts:
3 left
💡 Hint
Common Mistakes
Using int or unrelated types for next pointer.
Forgetting the pointer symbol *.
3fill in blank
hard

Fix the error in the code to append a new node to the end of a linked list.

DSA Go
func appendNode(head *Node, val int) *Node {
    newNode := &Node{value: val}
    if head == nil {
        return newNode
    }
    current := head
    for current.next [1] nil {
        current = current.next
    }
    current.next = newNode
    return head
}
Drag options to blanks, or click blank then click option'
A<
B==
C!=
D>
Attempts:
3 left
💡 Hint
Common Mistakes
Using '==' causes loop to stop immediately.
Using comparison operators like '<' or '>' on pointers.
4fill in blank
hard

Fill both blanks to create a slice from an array and iterate over it.

DSA Go
arr := [5]int{1, 2, 3, 4, 5}
slice := arr[[1]:[2]]
for i, v := range slice {
    fmt.Println(i, v)
}
Drag options to blanks, or click blank then click option'
A1
B0
C3
D5
Attempts:
3 left
💡 Hint
Common Mistakes
Using 1 as start index misses the first element.
Using 5 as end index includes all elements.
5fill in blank
hard

Fill all three blanks to create a map from string to int with a condition.

DSA Go
words := []string{"go", "code", "list", "array"}
lengths := map[string]int{}
for _, word := range words {
    if len(word) [1] [2] {
        lengths[[3]] = len(word)
    }
}
Drag options to blanks, or click blank then click option'
A>
B3
Cword
D<
Attempts:
3 left
💡 Hint
Common Mistakes
Using '<' instead of '>' changes the condition.
Using a number or wrong variable as map key.

Practice

(1/5)
1. Which of the following best describes the memory layout of an array compared to a linked list?
easy
A. Both array and linked list elements are scattered randomly in memory.
B. Both array and linked list elements are stored contiguously in memory.
C. Linked list elements are stored contiguously, but array elements are scattered in memory.
D. Array elements are stored in contiguous memory locations, while linked list nodes are scattered in memory.

Solution

  1. Step 1: Understand array memory layout

    Arrays store elements in a continuous block of memory, one after another.
  2. Step 2: Understand linked list memory layout

    Linked list nodes are allocated separately and linked via pointers, so they are scattered.
  3. Final Answer:

    Array elements are stored in contiguous memory locations, while linked list nodes are scattered in memory. -> Option D
  4. Quick Check:

    Array = contiguous, Linked list = scattered [OK]
Hint: Arrays are continuous; linked lists use pointers to scattered nodes [OK]
Common Mistakes:
  • Thinking linked list nodes are stored contiguously
  • Confusing array and linked list memory layouts
  • Assuming both have same memory layout
2. Which Go syntax correctly declares an array of 5 integers?
easy
A. var arr []int = [5]
B. arr := []int{5}
C. var arr [5]int
D. arr := [5]int

Solution

  1. Step 1: Recall Go array declaration syntax

    Arrays are declared with fixed size inside square brackets before the type, e.g., [5]int.
  2. Step 2: Check each option

    A: var arr [5]int uses correct syntax. B: arr := []int{5} creates a slice with one element. C: var arr []int = [5] is invalid syntax. D: arr := [5]int is invalid syntax - missing composite literal {}.
  3. Final Answer:

    var arr [5]int -> Option C
  4. Quick Check:

    Array declaration = var arr [5]int [OK]
Hint: Array size goes inside brackets before type in Go [OK]
Common Mistakes:
  • Using slice syntax instead of array syntax
  • Placing size after type
  • Incorrect initialization syntax
3. Consider this Go code snippet:
package main

import "fmt"

type Node struct {
    value int
    next  *Node
}

func main() {
    var head *Node
    head = &Node{value: 1}
    head.next = &Node{value: 2}
    head.next.next = &Node{value: 3}
    
    arr := [3]int{1, 2, 3}
    
    fmt.Println(arr)
    fmt.Println(head.value, head.next.value, head.next.next.value)
}
What will be the output?
medium
A. [1 2 3] 3 2 1
B. [1 2 3] 1 2 3
C. [1 2 3] 1 3 2
D. Compilation error

Solution

  1. Step 1: Understand array print output

    Array arr contains [1, 2, 3], so fmt.Println(arr) prints [1 2 3].
  2. Step 2: Understand linked list traversal print

    head.value = 1, head.next.value = 2, head.next.next.value = 3, so printing them in order prints '1 2 3'.
  3. Final Answer:

    [1 2 3] 1 2 3 -> Option B
  4. Quick Check:

    Array and linked list values match printed order [OK]
Hint: Print array and linked list values in order to verify [OK]
Common Mistakes:
  • Confusing linked list node order
  • Expecting commas in array print
  • Assuming compilation error due to pointers
4. The following Go code attempts to create a linked list but has an error:
type Node struct {
    value int
    next  *Node
}

func main() {
    var head *Node
    head.value = 10
    head.next = nil
}
What is the error and how to fix it?
medium
A. head is nil pointer; initialize head before assigning fields
B. next field should be value, not pointer
C. value field must be a pointer type
D. No error; code runs fine

Solution

  1. Step 1: Identify pointer initialization issue

    head is declared as *Node but not initialized, so it is nil (no memory allocated).
  2. Step 2: Fix by allocating memory for head

    Use head = &Node{} before assigning head.value and head.next to avoid nil pointer dereference.
  3. Final Answer:

    head is nil pointer; initialize head before assigning fields -> Option A
  4. Quick Check:

    Nil pointer must be initialized before use [OK]
Hint: Always allocate memory for pointer before field access [OK]
Common Mistakes:
  • Assigning fields on nil pointer
  • Changing field types unnecessarily
  • Ignoring runtime panic from nil dereference
5. You want to store 1 million integers and frequently insert and delete elements in the middle. Considering memory layout and performance, which data structure is better and why?
  1. Array
  2. Linked List
hard
A. Linked List, because scattered nodes make insertions and deletions faster despite poor cache usage
B. Linked List, because arrays cannot store large data
C. Array, because insertions and deletions are always faster in arrays
D. Array, because contiguous memory improves cache performance despite costly insertions

Solution

  1. Step 1: Analyze insertion/deletion cost in arrays

    Arrays store data contiguously, so inserting or deleting in the middle requires shifting many elements, which is slow.
  2. Step 2: Analyze linked list insertion/deletion

    Linked lists store nodes scattered but allow fast insert/delete by changing pointers without shifting elements.
  3. Step 3: Consider memory and cache trade-offs

    Arrays have better cache performance due to contiguous memory, but linked lists are better for frequent middle insertions/deletions.
  4. Final Answer:

    Linked List, because scattered nodes make insertions and deletions faster despite poor cache usage -> Option A
  5. Quick Check:

    Frequent middle insert/delete favors linked list [OK]
Hint: Frequent middle insert/delete? Choose linked list despite cache cost [OK]
Common Mistakes:
  • Assuming arrays always faster for insert/delete
  • Ignoring shifting cost in arrays
  • Thinking arrays can't store large data
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