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DSA Goprogramming~10 mins

Implement Stack Using Queue in DSA Go - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to initialize a new queue for the stack.

DSA Go
type Stack struct {
    queue []int
}

func NewStack() *Stack {
    return &Stack{queue: [1]
}
Drag options to blanks, or click blank then click option'
Amake([]int, 1)
B[]int{0}
Cnil
Dmake([]int, 0)
Attempts:
3 left
💡 Hint
Common Mistakes
Using nil slice which can cause issues when appending.
Initializing slice with length 1 which adds an unwanted element.
2fill in blank
medium

Complete the code to push an element onto the stack using the queue.

DSA Go
func (s *Stack) Push(x int) {
    s.queue = append(s.queue, x)
    for i := 0; i < [1]; i++ {
        s.queue = append(s.queue, s.queue[0])
        s.queue = s.queue[1:]
    }
}
Drag options to blanks, or click blank then click option'
Alen(s.queue) - 1
Blen(s.queue)
Clen(s.queue) + 1
D0
Attempts:
3 left
💡 Hint
Common Mistakes
Rotating the queue the full length causing extra rotations.
Not rotating at all, which breaks stack order.
3fill in blank
hard

Fix the error in the Pop method to correctly remove and return the top element.

DSA Go
func (s *Stack) Pop() int {
    if len(s.queue) == 0 {
        return -1
    }
    top := s.queue[[1]]
    s.queue = s.queue[1:]
    return top
}
Drag options to blanks, or click blank then click option'
A1
Blen(s.queue) - 1
C0
D-1
Attempts:
3 left
💡 Hint
Common Mistakes
Trying to pop from the end of the slice which is incorrect here.
Using an invalid index causing runtime errors.
4fill in blank
hard

Fill both blanks to implement the Top method that returns the top element without removing it.

DSA Go
func (s *Stack) Top() int {
    if len(s.queue) == 0 {
        return -1
    }
    return s.queue[[1]] // top element
}
Drag options to blanks, or click blank then click option'
A0
Blen(s.queue) - 1
C1
D-1
Attempts:
3 left
💡 Hint
Common Mistakes
Returning the last element instead of the first.
Returning -1 incorrectly when stack is not empty.
5fill in blank
hard

Fill all three blanks to implement the IsEmpty method that checks if the stack is empty.

DSA Go
func (s *Stack) IsEmpty() bool {
    return [1] == [2]
}

// Usage example:
// stack := NewStack()
// empty := stack.IsEmpty() // returns [3] when stack is empty
Drag options to blanks, or click blank then click option'
Alen(s.queue)
B0
Ctrue
Dfalse
Attempts:
3 left
💡 Hint
Common Mistakes
Comparing queue length to 1 instead of 0.
Returning false when stack is empty.

Practice

(1/5)
1. What is the main idea behind implementing a stack using a queue?
easy
A. Use one or two queues to simulate Last-In-First-Out (LIFO) behavior
B. Use a queue to store elements in sorted order
C. Use a stack to simulate First-In-First-Out (FIFO) behavior
D. Use two stacks to implement a queue

Solution

  1. Step 1: Understand stack and queue behaviors

    A stack follows Last-In-First-Out (LIFO), while a queue follows First-In-First-Out (FIFO).
  2. Step 2: Simulate stack using queue(s)

    To implement a stack using queue(s), we use one or two queues to reorder elements so the last pushed element is always dequeued first.
  3. Final Answer:

    Use one or two queues to simulate Last-In-First-Out (LIFO) behavior -> Option A
  4. Quick Check:

    Stack = LIFO simulated by queue(s) [OK]
Hint: Remember stack is LIFO; queue is FIFO, reorder to simulate stack [OK]
Common Mistakes:
  • Confusing stack and queue order
  • Trying to sort elements instead of reordering
  • Using stack to implement queue instead
2. Which of the following is the correct Go syntax to declare a queue using a slice of integers?
easy
A. var queue []int
B. queue := make(map[int]int)
C. queue := []string{}
D. var queue int

Solution

  1. Step 1: Identify queue data structure type

    A queue can be implemented using a slice of integers for integer elements.
  2. Step 2: Check Go syntax for slice declaration

    "var queue []int" declares a slice of integers, suitable for queue implementation.
  3. Final Answer:

    var queue []int -> Option A
  4. Quick Check:

    Slice of int = queue [OK]
Hint: Use slice []int for queue of integers in Go [OK]
Common Mistakes:
  • Using map instead of slice for queue
  • Declaring wrong data type for queue
  • Using string slice for integer queue
3. Consider this Go code snippet implementing push operation of stack using one queue:
func (s *Stack) Push(x int) {
    s.q = append(s.q, x)
    for i := 0; i < len(s.q)-1; i++ {
        s.q = append(s.q, s.q[0])
        s.q = s.q[1:]
    }
}
If initially s.q = [1, 2], what is s.q after calling Push(3)?
medium
A. [3, 2, 1]
B. [1, 2, 3]
C. [3, 1, 2]
D. [2, 1, 3]

Solution

  1. Step 1: Append new element 3 to queue

    Initial queue: [1, 2]. After append: [1, 2, 3].
  2. Step 2: Rotate queue elements to move 3 to front

    Loop runs len(s.q)-1 = 2 times: - Iteration 1: append s.q[0]=1, queue becomes [1, 2, 3, 1], then remove first element: [2, 3, 1] - Iteration 2: append s.q[0]=2, queue becomes [2, 3, 1, 2], then remove first element: [3, 1, 2]
  3. Final Answer:

    [3, 1, 2] -> Option C
  4. Quick Check:

    Push moves new element front: [3,1,2] [OK]
Hint: New push rotates queue to front [OK]
Common Mistakes:
  • Not rotating queue after append
  • Removing wrong elements during rotation
  • Confusing order of elements after push
4. This Go code tries to implement Pop operation for stack using one queue:
func (s *Stack) Pop() int {
    if len(s.q) == 0 {
        return -1
    }
    val := s.q[0]
    s.q = s.q[1:]
    return val
}
What is the bug in this Pop method?
medium
A. It returns -1 when queue is empty, should panic instead
B. It removes the last element instead of the first
C. It does not check if queue is nil before accessing
D. It removes the front element, but stack pop should remove the last pushed element

Solution

  1. Step 1: Understand Pop operation in stack

    Pop removes the last pushed element (top of stack).
  2. Step 2: Analyze given Pop code

    Code removes s.q[0], the front of queue, which is incorrect because stack top is at front only if queue is rotated properly.
  3. Final Answer:

    It removes the front element, but stack pop should remove the last pushed element -> Option D
  4. Quick Check:

    Pop must remove last pushed, not front [OK]
Hint: Pop must remove top, not front element [OK]
Common Mistakes:
  • Removing front element without rotation
  • Ignoring empty queue check
  • Returning wrong default value
5. You want to implement a stack using two queues q1 and q2 in Go. Which approach correctly implements the Push operation to keep the stack order?
hard
A. Dequeue all elements from q1 to q2, then enqueue new element to q1
B. Enqueue new element to q2, then dequeue all from q1 to q2, swap q1 and q2
C. Enqueue new element to q1 only, no other operations
D. Enqueue new element to q1, then dequeue one element from q2

Solution

  1. Step 1: Understand two-queue stack push logic

    To keep stack order, new element must be at front of main queue after push.
  2. Step 2: Push by enqueue to empty q2, move all from q1 to q2, then swap

    Enqueue new element to q2, move all q1 elements to q2, then swap q1 and q2 so q1 has new order with new element front.
  3. Final Answer:

    Enqueue new element to q2, then dequeue all from q1 to q2, swap q1 and q2 -> Option B
  4. Quick Check:

    Push uses q2 enqueue + q1 transfer + swap [OK]
Hint: Push to empty q2, move q1 to q2, swap queues [OK]
Common Mistakes:
  • Not swapping queues after transfer
  • Enqueueing new element to wrong queue
  • Forgetting to move all elements
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