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DSA Goprogramming~30 mins

GCD and LCM Euclidean Algorithm in DSA Go - Build from Scratch

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GCD and LCM Euclidean Algorithm
📖 Scenario: You are helping a friend who wants to find the greatest common divisor (GCD) and least common multiple (LCM) of two numbers. These are useful in many real-life situations like sharing items equally or scheduling events.
🎯 Goal: Build a Go program that calculates the GCD and LCM of two given numbers using the Euclidean algorithm.
📋 What You'll Learn
Create two integer variables named a and b with exact values 48 and 18
Create a variable originalA and originalB to store the original values of a and b
Use a for loop to implement the Euclidean algorithm to find the GCD of a and b
Calculate the LCM using the formula: (originalA * originalB) / gcd
Print the GCD and LCM in the format: GCD: 6 and LCM: 144
💡 Why This Matters
🌍 Real World
Finding GCD and LCM helps in tasks like dividing items into equal groups, scheduling repeating events, or simplifying fractions.
💼 Career
Understanding algorithms like Euclidean algorithm is fundamental for software developers, especially in fields like cryptography, optimization, and systems programming.
Progress0 / 4 steps
1
Create variables for the two numbers
Create two integer variables called a and b and set them to 48 and 18 respectively.
DSA Go
Hint

Use := to declare and assign variables in Go.

2
Store original values for later use
Create two integer variables called originalA and originalB and set them to the current values of a and b.
DSA Go
Hint

Assign originalA to a and originalB to b.

3
Calculate the GCD using Euclidean algorithm
Use a for loop with the condition b != 0 to repeatedly calculate the remainder of a divided by b. Inside the loop, update a to b and b to the remainder. This will find the GCD stored in a.
DSA Go
Hint

The Euclidean algorithm uses the remainder to find the GCD.

4
Calculate and print the GCD and LCM
Create an integer variable called lcm and set it to the product of originalA and originalB divided by a (the GCD). Then print the GCD and LCM using fmt.Println in the format: GCD: 6 and LCM: 144. Remember to import fmt.
DSA Go
Hint

Use fmt.Println("GCD:", a) and fmt.Println("LCM:", lcm) to print results.

Practice

(1/5)
1. What does the Euclidean algorithm primarily calculate between two numbers a and b?
easy
A. The sum of the numbers
B. The Least Common Multiple (LCM)
C. The Greatest Common Divisor (GCD)
D. The difference between the numbers

Solution

  1. Step 1: Understand the Euclidean algorithm purpose

    The Euclidean algorithm is a method to find the greatest common divisor (GCD) of two integers by repeatedly applying the remainder operation.
  2. Step 2: Differentiate GCD from LCM

    While GCD finds the largest number dividing both, LCM finds the smallest number divisible by both. Euclidean algorithm is for GCD.
  3. Final Answer:

    The Greatest Common Divisor (GCD) -> Option C
  4. Quick Check:

    Euclidean algorithm = GCD [OK]
Hint: Euclidean algorithm always finds GCD, not LCM [OK]
Common Mistakes:
  • Confusing GCD with LCM
  • Thinking it calculates sum or difference
  • Assuming it finds prime factors directly
2. Which of the following Go code snippets correctly implements the Euclidean algorithm to find the GCD of two integers a and b?
easy
A. func gcd(a, b int) int { if b == 0 { return a } return gcd(b, a % b) }
B. func gcd(a, b int) int { return a + b }
C. func gcd(a, b int) int { for i := 1; i <= a && i <= b; i++ { if a%i == 0 && b%i == 0 { return i } } return 1 }
D. func gcd(a, b int) int { return a * b }

Solution

  1. Step 1: Check recursive Euclidean algorithm syntax

    func gcd(a, b int) int { if b == 0 { return a } return gcd(b, a % b) } uses recursion and modulo operation correctly: if b is zero, return a; else call gcd(b, a % b).
  2. Step 2: Verify other options for correctness

    func gcd(a, b int) int { return a + b } returns sum, C returns first divisor found (incorrect logic), D returns product. Only A is correct.
  3. Final Answer:

    func gcd(a, b int) int { if b == 0 { return a } return gcd(b, a % b) } -> Option A
  4. Quick Check:

    Correct recursive gcd code = func gcd(a, b int) int { if b == 0 { return a } return gcd(b, a % b) } [OK]
Hint: Use recursion with modulo for Euclidean GCD [OK]
Common Mistakes:
  • Returning sum or product instead of GCD
  • Incorrect loop logic for GCD
  • Missing base case for recursion
3. What is the output of the following Go code?
package main
import "fmt"
func gcd(a, b int) int {
 if b == 0 {
  return a
 }
 return gcd(b, a % b)
}
func lcm(a, b int) int {
 return (a * b) / gcd(a, b)
}
func main() {
 fmt.Println(gcd(12, 18))
 fmt.Println(lcm(12, 18))
}
medium
A. 6 36
B. 3 72
C. 6 54
D. 12 18

Solution

  1. Step 1: Calculate gcd(12, 18) using Euclidean algorithm

    18 % 12 = 6, gcd(12, 6) -> 12 % 6 = 0, gcd(6, 0) = 6. So gcd is 6.
  2. Step 2: Calculate lcm(12, 18) using formula

    LCM = (12 * 18) / 6 = 216 / 6 = 36.
  3. Final Answer:

    6 36 -> Option A
  4. Quick Check:

    GCD=6, LCM=36 [OK]
Hint: LCM = (a*b)/GCD; find GCD first [OK]
Common Mistakes:
  • Mixing up GCD and LCM values
  • Incorrect modulo calculations
  • Forgetting integer division
4. Identify the bug in this Go function intended to compute the GCD using the Euclidean algorithm:
func gcd(a, b int) int {
 for b != 0 {
  a = b
  b = a % b
 }
 return a
}
medium
A. The function should return b instead of a
B. The loop condition should be a != 0 instead of b != 0
C. The function is correct and has no bugs
D. The order of assignments causes incorrect modulo calculation

Solution

  1. Step 1: Analyze the assignment order inside the loop

    Assigning a = b first changes a before calculating b = a % b, so a % b uses updated a, causing wrong result.
  2. Step 2: Correct approach for Euclidean algorithm

    Store a % b in a temp variable before updating a, or swap assignments to avoid overwriting needed values.
  3. Final Answer:

    The order of assignments causes incorrect modulo calculation -> Option D
  4. Quick Check:

    Assignment order matters in Euclidean GCD [OK]
Hint: Update b before a to keep correct modulo values [OK]
Common Mistakes:
  • Overwriting variables before modulo calculation
  • Wrong loop condition
  • Returning wrong variable
5. Given two positive integers a and b, which of the following Go functions correctly computes the LCM using the Euclidean algorithm for GCD, handling the edge case when either a or b is zero?
hard
A. func lcm(a, b int) int { if a == 0 || b == 0 { return 1 } return (a * b) / gcd(a, b) }
B. func lcm(a, b int) int { if a == 0 || b == 0 { return 0 } return (a * b) / gcd(a, b) }
C. func lcm(a, b int) int { if a == 0 && b == 0 { return 1 } return (a + b) / gcd(a, b) }
D. func lcm(a, b int) int { return (a * b) / gcd(a, b) }

Solution

  1. Step 1: Understand LCM edge cases

    If either a or b is zero, LCM should be zero because zero times any number is zero.
  2. Step 2: Check each option for correct edge handling

    func lcm(a, b int) int { if a == 0 || b == 0 { return 0 } return (a * b) / gcd(a, b) } returns 0 if either input is zero, then calculates LCM correctly. func lcm(a, b int) int { return (a * b) / gcd(a, b) } misses zero check. func lcm(a, b int) int { if a == 0 && b == 0 { return 1 } return (a + b) / gcd(a, b) } returns 1 incorrectly. func lcm(a, b int) int { if a == 0 || b == 0 { return 1 } return (a * b) / gcd(a, b) } returns 1 for zero inputs, which is wrong.
  3. Final Answer:

    func lcm(a, b int) int { if a == 0 || b == 0 { return 0 } return (a * b) / gcd(a, b) } -> Option B
  4. Quick Check:

    LCM zero if any input zero [OK]
Hint: LCM is zero if either number is zero [OK]
Common Mistakes:
  • Ignoring zero inputs in LCM calculation
  • Returning 1 instead of 0 for zero inputs
  • Using addition instead of multiplication
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