What is the main idea behind Floyd's Cycle Detection Algorithm in a linked list?
It uses two pointers moving at different speeds (slow and fast). If there is a cycle, the fast pointer will eventually meet the slow pointer inside the loop.
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beginner
In Floyd's Algorithm, what speeds do the two pointers move at?
The slow pointer moves one step at a time, and the fast pointer moves two steps at a time.
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intermediate
Why does the fast pointer eventually meet the slow pointer if a cycle exists?
Because the fast pointer moves faster, it will loop around and catch up to the slow pointer inside the cycle.
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beginner
What does it mean if the fast pointer reaches the end (null) in Floyd's Algorithm?
It means there is no cycle in the linked list because the fast pointer reached the end without meeting the slow pointer.
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intermediate
How can you find the starting node of the cycle after detecting a cycle using Floyd's Algorithm?
Reset one pointer to the head of the list and move both pointers one step at a time. The node where they meet is the start of the cycle.
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In Floyd's Cycle Detection Algorithm, what happens if the fast pointer reaches null?
AA cycle is detected
BThe slow pointer moves faster
CThere is no cycle in the linked list
DThe algorithm restarts
✗ Incorrect
If the fast pointer reaches null, it means the list ends and no cycle exists.
What is the speed of the slow pointer in Floyd's Algorithm?
AOne step at a time
BTwo steps at a time
CThree steps at a time
DVariable speed
✗ Incorrect
The slow pointer moves one step at a time.
Why does Floyd's Algorithm use two pointers with different speeds?
ATo detect if the fast pointer catches the slow pointer inside a cycle
BTo sort the linked list
CTo reverse the linked list
DTo count the number of nodes
✗ Incorrect
The fast pointer catching the slow pointer indicates a cycle.
After detecting a cycle, how do you find the cycle's starting node?
ACount the nodes in the cycle
BMove both pointers two steps at a time
CReverse the linked list
DMove one pointer to head and advance both one step until they meet
✗ Incorrect
Resetting one pointer to head and moving both one step at a time finds the cycle start.
What data structure is Floyd's Cycle Detection Algorithm used on?
AArray
BLinked List
CStack
DQueue
✗ Incorrect
Floyd's Algorithm is specifically designed for linked lists.
Explain how Floyd's Cycle Detection Algorithm works step-by-step.
Think about how the pointers move and meet.
You got /5 concepts.
Describe how to find the starting node of a cycle after detecting it with Floyd's Algorithm.
Focus on pointer movement after cycle detection.
You got /3 concepts.
Practice
(1/5)
1. What is the main idea behind Floyd's Cycle Detection Algorithm in a linked list?
easy
A. Reverse the linked list and check if it matches the original
B. Count the number of nodes and check if it exceeds a limit
C. Use two pointers moving at different speeds to detect a cycle
D. Use a hash map to store visited nodes
Solution
Step 1: Understand Floyd's Algorithm concept
It uses two pointers, one moving one step at a time (slow), and another moving two steps at a time (fast).
Step 2: Detect cycle by pointer meeting
If the fast pointer meets the slow pointer, it means there is a cycle in the linked list.
Final Answer:
Use two pointers moving at different speeds to detect a cycle -> Option C
Quick Check:
Two pointers at different speeds = cycle detection [OK]
Hint: Two pointers at different speeds detect cycle fast [OK]
Common Mistakes:
Thinking counting nodes detects cycle
Assuming reversing list helps detect cycle
Using extra memory like hash map is not Floyd's method
2. Which of the following Go code snippets correctly initializes the two pointers for Floyd's cycle detection in a linked list named head?
easy
A. slow, fast := head, head
B. slow, fast := head.next, head.next.next
C. slow, fast := head, head.next
D. slow, fast := nil, head
Solution
Step 1: Initialize both pointers at head
Floyd's algorithm starts both slow and fast pointers at the head node.
Step 2: Move pointers inside loop, not at initialization
Moving fast or slow pointer ahead at initialization can skip nodes or cause errors.
Final Answer:
slow, fast := head, head -> Option A
Quick Check:
Both pointers start at head [OK]
Hint: Start both pointers at head before loop [OK]
Common Mistakes:
Starting fast pointer ahead causing nil pointer errors
Initializing slow pointer ahead skipping first node
Setting slow pointer to nil initially
3. What will be the output of the following Go code snippet detecting a cycle in a linked list?
type Node struct {
val int
next *Node
}
func hasCycle(head *Node) bool {
slow, fast := head, head
for fast != nil && fast.next != nil {
slow = slow.next
fast = fast.next.next
if slow == fast {
return true
}
}
return false
}
// Linked list setup
n1 := &Node{val: 1}
n2 := &Node{val: 2}
n3 := &Node{val: 3}
n4 := &Node{val: 4}
n1.next = n2
n2.next = n3
n3.next = n4
n4.next = n2 // cycle here
fmt.Println(hasCycle(n1))
medium
A. true
B. false
C. runtime error
D. infinite loop
Solution
Step 1: Analyze linked list structure
The list nodes are connected 1->2->3->4, and 4 points back to 2, creating a cycle.
Step 2: Trace Floyd's algorithm behavior
Slow and fast pointers will eventually meet inside the cycle, so function returns true.
Final Answer:
true -> Option A
Quick Check:
Cycle exists, so output is true [OK]
Hint: Cycle means pointers meet, so return true [OK]
Common Mistakes:
Assuming no cycle because list looks linear
Expecting false without tracing pointers
Confusing cycle detection with list length
4. Identify the bug in this Go code snippet for detecting a cycle in a linked list:
func hasCycle(head *Node) bool {
slow, fast := head, head
for fast != nil {
slow = slow.next
fast = fast.next.next
if slow == fast {
return true
}
}
return false
}
medium
A. The slow pointer should move two steps instead of one
B. The loop condition should check fast.next != nil to avoid nil pointer dereference
C. The fast pointer should move one step instead of two
D. The function should return false inside the loop when pointers don't meet
Solution
Step 1: Check loop condition safety
The loop only checks fast != nil, but fast.next could be nil causing fast.next.next to panic.
Step 2: Correct loop condition
Loop should check both fast != nil and fast.next != nil to safely move fast pointer two steps.
Final Answer:
The loop condition should check fast.next != nil to avoid nil pointer dereference -> Option B
Quick Check:
Check fast and fast.next != nil before moving fast [OK]
Hint: Always check fast.next != nil before fast.next.next [OK]
5. Given a linked list where the cycle starts at node with value 3, how can Floyd's algorithm be extended to find the exact node where the cycle begins?
hard
A. Count nodes until pointers meet and return the count as cycle start position
B. Reverse the linked list and check where reversal breaks to find cycle start
C. Use a hash map to store nodes and find the first repeated node
D. After detecting the cycle, reset one pointer to head and move both one step until they meet at cycle start
Solution
Step 1: Detect cycle using Floyd's algorithm
First, detect if a cycle exists by moving slow and fast pointers until they meet.
Step 2: Find cycle start node
Reset one pointer to head, then move both pointers one step at a time; the node where they meet is the cycle start.
Final Answer:
After detecting the cycle, reset one pointer to head and move both one step until they meet at cycle start -> Option D
Quick Check:
Reset pointer + move one step = cycle start [OK]
Hint: Reset pointer to head after cycle detection to find start [OK]
Common Mistakes:
Trying to count nodes instead of resetting pointer
Using extra memory instead of pointer method
Reversing list which breaks structure
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