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DSA Goprogramming~20 mins

Dequeue Operation in DSA Go - Practice Problems & Challenges

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Challenge - 5 Problems
🎖️
Dequeue Mastery
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Test your skills under time pressure!
❓ Predict Output
intermediate
2:00remaining
Output of Dequeue Push and Pop Operations
What is the printed state of the dequeue after the following operations?
DSA Go
package main

import (
	"container/list"
	"fmt"
)

func main() {
	dq := list.New()
	dq.PushBack(10)
	dq.PushFront(20)
	dq.PushBack(30)
	dq.Remove(dq.Front())

	for e := dq.Front(); e != nil; e = e.Next() {
		fmt.Print(e.Value, " -> ")
	}
	fmt.Print("null")
}
A20 -> 30 -> null
B20 -> 10 -> 30 -> null
C30 -> 10 -> null
D10 -> 30 -> null
Attempts:
2 left
💡 Hint

Remember that PushFront adds to the front and Remove removes the element passed.

❓ Predict Output
intermediate
2:00remaining
Result of Removing from Empty Dequeue
What happens when you try to remove an element from an empty dequeue using Go's container/list?
DSA Go
package main

import (
	"container/list"
	"fmt"
)

func main() {
	dq := list.New()
	removed := dq.Remove(dq.Front())
	fmt.Println(removed)
}
A<nil>
Bempty string
C0
Dpanic: runtime error: invalid memory address or nil pointer dereference
Attempts:
2 left
💡 Hint

Check what dq.Front() returns when the list is empty.

🔧 Debug
advanced
2:00remaining
Identify the Bug in Dequeue Push and Remove
What error does the following code produce when run?
DSA Go
package main

import (
	"container/list"
	"fmt"
)

func main() {
	dq := list.New()
	dq.PushBack(1)
	dq.PushBack(2)
	dq.PushFront(3)
	dq.Remove(dq.Back())
	dq.Remove(dq.Back())
	dq.Remove(dq.Back())
	dq.Remove(dq.Back())

	for e := dq.Front(); e != nil; e = e.Next() {
		fmt.Print(e.Value, " -> ")
	}
	fmt.Print("null")
}
Anull
B0 -> null
C3 -> 1 -> null
Dpanic: runtime error: invalid memory address or nil pointer dereference
Attempts:
2 left
💡 Hint

Consider what happens when you remove elements more times than the dequeue has.

🧠 Conceptual
advanced
2:00remaining
Time Complexity of Dequeue Operations
What is the time complexity of adding or removing an element from either end of a dequeue implemented with Go's container/list?
AO(n) for adding at front, O(1) for removing at back
BO(1) for both adding and removing at either end
CO(log n) for adding and removing at either end
DO(n) for both adding and removing at either end
Attempts:
2 left
💡 Hint

Think about how linked lists work for insertions and deletions at ends.

🚀 Application
expert
3:00remaining
Final State of Dequeue After Mixed Operations
Given the following sequence of operations on a dequeue, what is the final printed state?
DSA Go
package main

import (
	"container/list"
	"fmt"
)

func main() {
	dq := list.New()
	dq.PushBack(5)
	dq.PushFront(10)
	dq.PushBack(15)
	dq.Remove(dq.Front())
	dq.PushFront(20)
	dq.Remove(dq.Back())
	dq.PushBack(25)

	for e := dq.Front(); e != nil; e = e.Next() {
		fmt.Print(e.Value, " -> ")
	}
	fmt.Print("null")
}
A20 -> 15 -> 25 -> null
B10 -> 5 -> 25 -> null
C20 -> 5 -> 25 -> null
D5 -> 15 -> 25 -> null
Attempts:
2 left
💡 Hint

Track each operation step-by-step to see how the dequeue changes.

Practice

(1/5)
1. What is a dequeue in data structures?
easy
A. A double-ended queue allowing insertion and deletion at both ends
B. A queue that only allows insertion at the rear and deletion at the front
C. A stack that allows insertion and deletion only at one end
D. A list that only supports random access

Solution

  1. Step 1: Understand the definition of dequeue

    A dequeue is a data structure where elements can be added or removed from both the front and the rear ends.
  2. Step 2: Compare with other data structures

    Unlike a queue or stack, which restrict operations to one end, dequeue supports both ends.
  3. Final Answer:

    A double-ended queue allowing insertion and deletion at both ends -> Option A
  4. Quick Check:

    Dequeue = double-ended queue [OK]
Hint: Remember: Dequeue means double-ended queue [OK]
Common Mistakes:
  • Confusing dequeue with stack or simple queue
  • Thinking dequeue only allows operations at one end
  • Mixing dequeue with random access lists
2. Which of the following is the correct Go syntax to create an empty dequeue using a slice?
easy
A. var dq []int = make([]int, 0)
B. dq := []int{nil}
C. var dq int = []{}
D. dq := make([]int, -1)

Solution

  1. Step 1: Understand slice creation in Go

    To create an empty slice, use make with length 0, like make([]int, 0).
  2. Step 2: Check each option

    var dq []int = make([]int, 0) correctly creates an empty int slice. dq := []int{nil} uses nil inside slice literal which is invalid. var dq int = []{} has wrong type assignment. dq := make([]int, -1) tries negative length which is invalid.
  3. Final Answer:

    var dq []int = make([]int, 0) -> Option A
  4. Quick Check:

    Empty slice = make([]int, 0) [OK]
Hint: Use make([]type, 0) for empty slices in Go [OK]
Common Mistakes:
  • Using nil inside slice literal
  • Assigning wrong types
  • Using negative length in make
3. What will be the output of the following Go code snippet simulating dequeue operations?
package main
import "fmt"
func main() {
  dq := []int{10, 20, 30}
  // Remove from front
  dq = dq[1:]
  // Add 40 at rear
  dq = append(dq, 40)
  fmt.Println(dq)
}
medium
A. [40 20 30]
B. [10 20 30 40]
C. [20 30 40]
D. [30 40]

Solution

  1. Step 1: Remove element from front

    dq = dq[1:] removes the first element (10), so dq becomes [20, 30].
  2. Step 2: Add element at rear

    append(dq, 40) adds 40 at the end, so dq becomes [20, 30, 40].
  3. Final Answer:

    [20 30 40] -> Option C
  4. Quick Check:

    Remove front + append rear = [20 30 40] [OK]
Hint: Slice from 1 removes front; append adds rear [OK]
Common Mistakes:
  • Forgetting slice removes front element
  • Appending at wrong position
  • Misreading slice syntax
4. Identify the error in the following Go code that tries to remove an element from the rear of a dequeue represented by a slice:
package main
import "fmt"
func main() {
  dq := []int{5, 10, 15}
  dq = dq[:len(dq)]
  fmt.Println(dq)
}
medium
A. No error; code correctly removes rear element
B. Runtime panic due to invalid slice bounds
C. Syntax error in slice expression
D. Slice operation does not remove last element; length unchanged

Solution

  1. Step 1: Analyze slice operation dq[:len(dq)]

    This slice keeps all elements from start to length, so no element is removed.
  2. Step 2: Understand how to remove last element

    To remove last element, slice should be dq[:len(dq)-1].
  3. Final Answer:

    Slice operation does not remove last element; length unchanged -> Option D
  4. Quick Check:

    dq[:len(dq)] keeps all elements [OK]
Hint: Use dq[:len(dq)-1] to remove last element [OK]
Common Mistakes:
  • Using dq[:len(dq)] expecting removal
  • Off-by-one errors in slicing
  • Confusing slice length with index
5. Given a dequeue implemented as a slice in Go, which sequence of operations will correctly remove an element from the front and add an element at the front, resulting in [99 30 40] from initial [20 30 40]? Choose the correct code snippet:
package main
import "fmt"
func main() {
  dq := []int{20, 30, 40}
  // Your code here
  fmt.Println(dq)
}
hard
A. dq = append(dq, 99) dq = dq[1:]
B. dq = dq[1:] dq = append([]int{99}, dq...)
C. dq = append(dq, 99) dq = append([]int{99}, dq...)
D. dq = dq[:len(dq)-1] dq = append([]int{99}, dq...)

Solution

  1. Step 1: Remove element from front

    dq = dq[1:] removes the first element (20), so dq becomes [30, 40].
  2. Step 2: Add 99 at front

    dq = append([]int{99}, dq...) adds 99 at the front, resulting in [99, 30, 40].
  3. Step 3: Verify final slice

    After these operations, dq is [99, 30, 40], which matches the expected result.
  4. Final Answer:

    dq = dq[1:] dq = append([]int{99}, dq...) -> Option B
  5. Quick Check:

    Remove front + add front = dq = dq[1:] dq = append([]int{99}, dq...) [OK]
Hint: Add front with append([]int{val}, dq...) [OK]
Common Mistakes:
  • Removing wrong element before adding front
  • Appending at rear instead of front
  • Confusing slice operations order
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