A. The function should return 's.top > len(s.items)' instead
B. The condition should be 's.top == len(s.items) - 1' to check full correctly
C. The function should check if 's.top == 0' to be full
D. No error, the code is correct
Solution
Step 1: Understand stack indexing for full condition
Stack top index starts at -1 and max valid index is length - 1.
Step 2: Identify correct full condition
Full means top equals last valid index, which is len(s.items) - 1, not len(s.items).
Final Answer:
The condition should be 's.top == len(s.items) - 1' to check full correctly -> Option B
Quick Check:
Full means top == max index (length - 1) [OK]
Hint: Full means top equals last index, not length [OK]
Common Mistakes:
Using length instead of length - 1
Checking top == 0 for full
Returning wrong boolean condition
5. You have a stack implemented with a fixed size array of length 3 and a top index starting at -1. After pushing two elements, you pop one element, then push two more elements. Which statement about the stack state is correct?
hard
A. The stack is empty and top index is -1
B. The stack is not full and top index is 1
C. The stack is full but top index is 3
D. The stack is full and top index is 2
Solution
Step 1: Track stack operations and top index changes
Start: top = -1 (empty). Push two elements: top = 1. Pop one element: top = 0. Push two elements: top = 2 (max index for length 3).
Step 2: Determine if stack is full
Since top = 2 and max index is 2 (length 3 - 1), stack is full.
Final Answer:
The stack is full and top index is 2 -> Option D
Quick Check:
Push/pop changes top; top 2 means full for size 3 [OK]
Hint: Track top index after each push/pop carefully [OK]
Common Mistakes:
Assuming top can be 3 for full
Forgetting pop decreases top
Confusing empty with full states
Recommended
Ready to prove it?
Pass the test and this pattern moves unknownstrongwhile earning +1 Grip toward your certificate.