DP on Trees Maximum Path Sum in DSA C# - Build from Scratch

DP on Trees Maximum Path Sum

📖 Scenario: You are working with a tree data structure representing a network of connected nodes. Each node has a value that can be positive or negative. You want to find the maximum sum of values along any path in the tree. A path can start and end at any nodes but must follow the tree connections.

🎯 Goal: Build a C# program that uses dynamic programming on trees to find the maximum path sum. You will create the tree nodes, set up a helper variable, implement the recursive logic to compute the maximum path sum, and finally print the result.

📋 What You'll Learn

Create a tree node class with integer value and left/right children

Build a specific tree with given node values

Use a helper variable to track the maximum path sum globally

Implement a recursive function to compute max path sums

Print the maximum path sum found in the tree

💡 Why This Matters

🌍 Real World

Finding maximum path sums in trees is useful in network analysis, decision trees, and optimizing routes where nodes represent values or costs.

💼 Career

Understanding dynamic programming on trees is important for software engineers working on algorithms, game development, and systems involving hierarchical data.

1

Create the Tree Node Class and Build the Tree

Create a class called TreeNode with an integer val and two TreeNode references left and right. Then create the following tree structure exactly:

Root node with val = 1
Root's left child with val = 2
Root's right child with val = 3
Left child's left child with val = 4
Left child's right child with val = 5

DSA C#

// Define TreeNode class and build the tree as described
// Your code here

Hint

Define a class with a constructor for value and children. Then create nodes and link them as left and right children.

2

Add a Helper Variable to Track Maximum Path Sum

Add a variable called maxSum of type int and initialize it to int.MinValue. This will keep track of the maximum path sum found during recursion.

DSA C#

public class TreeNode
{
    public int val;
    public TreeNode left;
    public TreeNode right;
    public TreeNode(int val=0, TreeNode left=null, TreeNode right=null)
    {
        this.val = val;
        this.left = left;
        this.right = right;
    }
}

TreeNode root = new TreeNode(1);
root.left = new TreeNode(2);
root.right = new TreeNode(3);
root.left.left = new TreeNode(4);
root.left.right = new TreeNode(5);

// Add maxSum variable below
// Your code here

Hint

Use int.MinValue to start with the smallest possible integer.

3

Implement Recursive Function to Compute Maximum Path Sum

Write a recursive function called MaxPathSumHelper that takes a TreeNode parameter node and returns an int. It should:
- Return 0 if node is null.
- Recursively get the max path sum from left and right children, but ignore negative sums by using Math.Max(0, ...).
- Calculate current path sum as node.val + left + right.
- Update maxSum if current path sum is greater.
- Return node.val + Math.Max(left, right) to parent.
Call this function with root to start the recursion.

DSA C#

public class TreeNode
{
    public int val;
    public TreeNode left;
    public TreeNode right;
    public TreeNode(int val=0, TreeNode left=null, TreeNode right=null)
    {
        this.val = val;
        this.left = left;
        this.right = right;
    }
}

TreeNode root = new TreeNode(1);
root.left = new TreeNode(2);
root.right = new TreeNode(3);
root.left.left = new TreeNode(4);
root.left.right = new TreeNode(5);

int maxSum = int.MinValue;

// Write MaxPathSumHelper function and call it with root
// Your code here

Hint

Use recursion to get max sums from children. Ignore negative sums by comparing with 0. Update global maxSum if current path is better.

4

Print the Maximum Path Sum

Write a Console.WriteLine statement to print the value of maxSum.

DSA C#

public class TreeNode
{
    public int val;
    public TreeNode left;
    public TreeNode right;
    public TreeNode(int val=0, TreeNode left=null, TreeNode right=null)
    {
        this.val = val;
        this.left = left;
        this.right = right;
    }
}

TreeNode root = new TreeNode(1);
root.left = new TreeNode(2);
root.right = new TreeNode(3);
root.left.left = new TreeNode(4);
root.left.right = new TreeNode(5);

int maxSum = int.MinValue;

int MaxPathSumHelper(TreeNode node)
{
    if (node == null) return 0;
    int left = Math.Max(0, MaxPathSumHelper(node.left));
    int right = Math.Max(0, MaxPathSumHelper(node.right));
    int currentSum = node.val + left + right;
    if (currentSum > maxSum) maxSum = currentSum;
    return node.val + Math.Max(left, right);
}

MaxPathSumHelper(root);

// Print maxSum below
// Your code here

Hint

Use Console.WriteLine(maxSum); to display the result.

Practice

1. What does the "maximum path sum" in a tree represent in the context of DP on Trees Maximum Path Sum?

easy

A. The sum of all node values in the tree

B. The largest sum of node values on any path between two nodes in the tree

C. The maximum value of a single node in the tree

D. The longest path length in terms of number of edges

Solution

1. Step 1: Understand the problem definition

   The maximum path sum means the highest total sum of node values collected along any path connecting two nodes in the tree, not necessarily passing through the root.

2. Step 2: Differentiate from other sums

   It is not the sum of all nodes or just the maximum single node value, but the sum along a path that can include multiple nodes.

3. Final Answer:

   The largest sum of node values on any path between two nodes in the tree -> Option B

4. Quick Check:

   Maximum path sum = largest node value sum on any path [OK]

Hint: Maximum path sum is about sums along paths, not single nodes [OK]

Common Mistakes:

• Confusing maximum path sum with sum of all nodes
• Thinking it is just the maximum node value
• Assuming path must start at root

2. Which of the following C# method signatures is correct for a recursive function that returns the maximum path sum starting from a given tree node?

easy

A. int MaxPathSum(TreeNode node)

B. void MaxPathSum(TreeNode node)

C. int MaxPathSum(int node)

D. TreeNode MaxPathSum(TreeNode node)

Solution

1. Step 1: Identify the return type needed

   The function should return an integer representing the maximum path sum starting from the given node.

2. Step 2: Check parameter type

   The parameter must be a TreeNode object to access node values and children.

3. Final Answer:

   int MaxPathSum(TreeNode node) -> Option A

4. Quick Check:

   Return type int and parameter TreeNode required [OK]

Hint: Return int for sums, input parameter must be TreeNode [OK]

Common Mistakes:

• Using void return type when int is needed
• Passing int instead of TreeNode as parameter
• Returning TreeNode instead of int

3. Consider the following C# code snippet for a binary tree node class and a method to find maximum path sum:

public class TreeNode {
    public int val;
    public TreeNode left, right;
    public TreeNode(int x) { val = x; }
}

int maxSum = int.MinValue;

int MaxPathSum(TreeNode node) {
    if (node == null) return 0;
    int left = Math.Max(0, MaxPathSum(node.left));
    int right = Math.Max(0, MaxPathSum(node.right));
    maxSum = Math.Max(maxSum, left + right + node.val);
    return Math.Max(left, right) + node.val;
}

// Tree structure:
//       1
//      / \
//     2   3

TreeNode root = new TreeNode(1);
root.left = new TreeNode(2);
root.right = new TreeNode(3);
MaxPathSum(root);
Console.WriteLine(maxSum);

What is the output printed?

medium

A. 1

B. 5

C. 3

D. 6

Solution

1. Step 1: Calculate max path sums for children

   For node 2 and 3, left and right children are null, so returns 0. Max path sum at node 2 and 3 is their own value (2 and 3).

2. Step 2: Calculate max path sum at root

   At root (1), left = max(0, 2) = 2, right = max(0, 3) = 3. maxSum updated to max(-∞, 2+3+1) = 6. Return max(2,3)+1=4.

3. Final Answer:

   6 -> Option D

4. Quick Check:

   Sum of path 2->1->3 = 6 [OK]

Hint: Add left + right + node.val for max path at each node [OK]

Common Mistakes:

• Ignoring max(0, child) and using negative sums
• Returning sum without updating maxSum
• Confusing return value with maxSum

4. The following C# code attempts to compute the maximum path sum in a binary tree but has a bug:

int maxSum = int.MinValue;

int MaxPathSum(TreeNode node) {
    if (node == null) return 0;
    int left = MaxPathSum(node.left);
    int right = MaxPathSum(node.right);
    maxSum = Math.Max(maxSum, left + right + node.val);
    return Math.Max(left, right) + node.val;
}

What is the bug in this code?

medium

A. It does not ignore negative sums from children

B. It returns the wrong value type

C. It does not update maxSum correctly

D. It does not handle null nodes

Solution

1. Step 1: Analyze child sums usage

   The code uses left and right sums directly without ignoring negative values, which can reduce the path sum.

2. Step 2: Identify fix for negative sums

   We must use Math.Max(0, left) and Math.Max(0, right) to ignore negative sums from children.

3. Final Answer:

   It does not ignore negative sums from children -> Option A

4. Quick Check:

   Negative child sums must be ignored [OK]

Hint: Use Math.Max(0, childSum) to ignore negatives [OK]

Common Mistakes:

• Not using Math.Max(0, child) causing wrong sums
• Assuming return type is wrong
• Missing null checks (which are present)

5. Given a binary tree where some nodes have negative values, which approach correctly computes the maximum path sum using DP on trees? A) At each node, compute max path sum including both children and update global max; return max path sum including one child plus node value. B) At each node, sum all child node values and return total sum. C) At each node, return the maximum child value only. D) At each node, ignore children and consider only node value.

hard

A. Return the maximum child value only

B. Sum all child node values and return total sum

C. Compute max path sum including both children and update global max; return max path sum including one child plus node value

D. Ignore children and consider only node value

Solution

1. Step 1: Understand the correct DP approach

   The correct approach is to consider the maximum path sum including both children and update a global max, returning the max path sum including one child plus node value.

2. Step 2: Identify the incorrect options

   The other options do not correctly handle the problem. They either sum all children, return only the maximum child value, or ignore children and consider only node value.

3. Final Answer:

   Compute max path sum including both children and update global max; return max path sum including one child plus node value -> Option C

4. Quick Check:

   Correct DP uses both children sums and global max update [OK]

Hint: Include both children sums and update global max [OK]

Common Mistakes:

• Ignoring children nodes in calculation
• Summing all children without max checks
• Returning only child values without node