Discover how a simple idea can make finding anything lightning fast!
Why HashMap Implementation from Scratch in DSA C#?
Imagine you have a huge phone book written on paper. To find a friend's number, you have to flip through every page until you find their name.
This manual search takes a lot of time and effort, especially if the phone book is very big. You might lose your place or make mistakes while searching.
A HashMap acts like a magic index that instantly tells you where your friend's number is, so you don't have to flip through all the pages.
string FindNumber(string name) {
foreach (var entry in phoneBook) {
if (entry.Name == name) return entry.Number;
}
return null;
}string FindNumber(string name) {
return hashMap.Get(name);
}It lets you store and find data super fast, even when you have thousands or millions of items.
Online stores use HashMaps to quickly find product details when you search by product name or ID.
Manual search is slow and error-prone for large data.
HashMaps use keys to jump directly to data.
This makes data lookup very fast and efficient.
Practice
HashMap in data structures?Solution
Step 1: Understand the role of HashMap
A HashMap stores data as key-value pairs, allowing quick access to values using keys.Step 2: Compare with other data structures
Unlike lists or arrays, HashMaps do not store data sequentially or sorted but focus on fast lookup.Final Answer:
To store key-value pairs for fast data retrieval -> Option BQuick Check:
HashMap = key-value fast access [OK]
- Confusing HashMap with sorted structures
- Thinking HashMap stores data sequentially
- Assuming HashMap is for calculations
Solution
Step 1: Recall C# standard HashMap equivalent
In C#,Dictionary<K,V>is the built-in generic collection similar to HashMap.Step 2: Check syntax correctness
Dictionary map = new Dictionary(); correctly declares a Dictionary with int keys and string values.Final Answer:
Dictionary map = new Dictionary(); -> Option DQuick Check:
C# HashMap = Dictionary [OK]
- Using non-existent HashMap class in C#
- Confusing Hashtable with generic Dictionary
- Wrong generic syntax
class SimpleHashMap {
private int[] keys = new int[5];
private string[] values = new string[5];
public void Put(int key, string value) {
int index = key % 5;
keys[index] = key;
values[index] = value;
}
public string Get(int key) {
int index = key % 5;
if (keys[index] == key) return values[index];
return null;
}
}
SimpleHashMap map = new SimpleHashMap();
map.Put(1, "One");
map.Put(6, "Six");
string result = map.Get(1);
What is the value of result after this code runs?Solution
Step 1: Calculate index for key 1
Index = 1 % 5 = 1. So keys[1] = 1, values[1] = "One".Step 2: Calculate index for key 6
Index = 6 % 5 = 1. This overwrites keys[1] = 6, values[1] = "Six".Step 3: Get value for key 1
Index = 1 % 5 = 1. keys[1] is now 6, not 1, soGetreturns null.Final Answer:
null -> Option AQuick Check:
Collision overwrites key 1, so Get(1) = null [OK]
- Ignoring key collision overwrite
- Assuming values are stored separately
- Expecting 'One' despite collision
Put method and choose the correct fix:
public void Put(int key, string value) {
int index = key % 5;
if (keys[index] != key) {
keys[index] = key;
values[index] = value;
}
}Solution
Step 1: Understand current behavior
Theif (keys[index] != key)inserts only if the existing key differs: overwrites on collisions (data loss for previous keys) and skips updates for matching keys.Step 2: Identify collision handling
Without collision handling like linear probing, new keys that hash to occupied slots overwrite existing data.Step 3: Fix by adding linear probing
Linear probing searches next slots to find an empty or matching key slot, preventing overwrites.Final Answer:
Add linear probing to handle collisions -> Option CQuick Check:
Collision fix = linear probing [OK]
- Removing if causes overwrites
- Changing modulus without resizing array
- Wrong if condition logic
class MyHashMap {
private List>[] buckets;
private int size = 10;
public MyHashMap() {
buckets = new List>[size];
for (int i = 0; i < size; i++) buckets[i] = new List>();
}
private int GetBucketIndex(string key) {
return Math.Abs(key.GetHashCode()) % size;
}
public void Put(string key, int value) {
int index = GetBucketIndex(key);
var bucket = buckets[index];
for (int i = 0; i < bucket.Count; i++) {
if (bucket[i].Key == key) {
bucket[i] = new KeyValuePair(key, value);
return;
}
}
bucket.Add(new KeyValuePair(key, value));
}
public int? Get(string key) {
int index = GetBucketIndex(key);
var bucket = buckets[index];
foreach (var kvp in bucket) {
if (kvp.Key == key) return kvp.Value;
}
return null;
}
}
MyHashMap map = new MyHashMap();
map.Put("apple", 5);
map.Put("banana", 3);
map.Put("apple", 10);
int? val = map.Get("apple");
What is the value of val after this code runs?Solution
Step 1: Understand Put method behavior
When inserting "apple" the second time, the code finds the existing key and updates its value to 10.Step 2: Understand Get method behavior
Get("apple") searches the bucket and returns the updated value 10.Final Answer:
10 -> Option AQuick Check:
Updated value for "apple" = 10 [OK]
- Returning old value instead of updated
- Ignoring collision handling with buckets
- Returning null if key exists
Ready to prove it?
Pass the test and this pattern moves unknown
