Complete the code to sort the input array before processing.
Array.[1](nums);Sorting the array helps to efficiently find quadruplets and avoid duplicates.
Complete the code to skip duplicate values for the first pointer i.
if (i > 0 && nums[i] == nums[i - 1]) [1];
Using 'continue' skips the current iteration to avoid duplicate quadruplets starting with the same number.
Fix the error in the while loop condition to move the left pointer correctly.
while (left < right && nums[left] == nums[left [1] 1]) left++;
We check the next element by adding 1 to left, so '+' is correct.
Fill both blanks to correctly move the right pointer and skip duplicates.
while (left < right && nums[right] == nums[right [1] 1]) right[2];
We check the previous element by subtracting 1, and decrement right using '--'.
Fill all three blanks to add the quadruplet to the result list correctly.
result.Add(new List<int> { nums[[1]], nums[[2]], nums[[3]], nums[right] });The quadruplet consists of nums[i], nums[j], nums[left], and nums[right].
