Four Sum Problem All Unique Quadruplets in DSA C# - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is the Four Sum problem?

The Four Sum problem asks to find all unique groups of four numbers in an array that add up to a given target sum.

beginner

Why do we sort the array before solving the Four Sum problem?

Sorting helps to avoid duplicates easily and allows using two pointers to find pairs efficiently.

intermediate

What technique is commonly used to solve the Four Sum problem efficiently?

We use nested loops for the first two numbers and then two pointers for the remaining two numbers to find quadruplets.

intermediate

How do we ensure the quadruplets are unique in the Four Sum problem?

We skip duplicate numbers during iteration and after finding a quadruplet to avoid repeating the same group.

intermediate

What is the time complexity of the common Four Sum solution?

The time complexity is O(n^3) because of two nested loops and a two-pointer scan inside.

What is the first step in solving the Four Sum problem?

A Remove duplicates

B Use a hash map

C Reverse the array

D Sort the array

Sorting the array helps to efficiently find quadruplets and avoid duplicates.

Which technique helps find pairs after fixing two numbers in Four Sum?

A Binary search

B Recursion

C Two pointers

D Stack

Two pointers move inward to find pairs that sum to the remaining target.

How do we avoid duplicate quadruplets?

A Skip duplicates during iteration

B All of the above

C Sort quadruplets before adding

D Use a set to store results

All these methods help ensure uniqueness of quadruplets.

What is the main reason for using nested loops in Four Sum?

A To fix the first two numbers

B To sort the array

C To remove duplicates

D To reverse the array

Nested loops fix the first two numbers so the two pointers can find the other two.

What is the overall time complexity of the Four Sum solution?

A O(n^3)

B O(n^2)

C O(n^4)

D O(n log n)

The solution uses two nested loops and a two-pointer scan, resulting in O(n^3) time.

Explain step-by-step how to find all unique quadruplets that sum to a target in an array.

Think about sorting, loops, two pointers, and skipping duplicates.

Describe how skipping duplicates works in the Four Sum problem and why it is important.

Focus on how duplicates appear and how skipping them helps.

Practice

1. What is the main goal of the Four Sum Problem in data structures and algorithms?

easy

A. Sort the array in ascending order

B. Count the number of pairs with a given sum

C. Find the maximum element in the array

D. Find all unique quadruplets in an array that sum up to a target value

Solution

1. Step 1: Understand the problem statement

   The Four Sum Problem asks to find all unique sets of four numbers in an array that add up to a specific target sum.

2. Step 2: Differentiate from other problems

   Unlike sorting or finding maximum, this problem focuses on quadruplets and their sums, not individual elements or pairs.

3. Final Answer:

   Find all unique quadruplets in an array that sum up to a target value -> Option D

4. Quick Check:

   Four Sum Problem = Find quadruplets with target sum [OK]

Hint: Look for four numbers adding to target, not sorting or max [OK]

Common Mistakes:

• Confusing with sorting or max element problems
• Looking for pairs instead of quadruplets
• Ignoring uniqueness of quadruplets

2. Which of the following C# code snippets correctly initializes a list to store quadruplets for the Four Sum Problem?

easy

A. var quadruplets = new List<List<int>>();

B. var quadruplets = new List<int>();

C. var quadruplets = new Dictionary<int, int>();

D. var quadruplets = new int[4];

Solution

1. Step 1: Identify the data structure for storing quadruplets

   Each quadruplet is a list of 4 integers, so a list of lists is needed to store multiple quadruplets.

2. Step 2: Match with C# syntax

   Using List<List<int>> correctly represents multiple quadruplets, unlike a single list or dictionary.

3. Final Answer:

   var quadruplets = new List<List<int>>(); -> Option A

4. Quick Check:

   Use List of List for quadruplets [OK]

Hint: Use List<List<int>> to store multiple quadruplets [OK]

Common Mistakes:

• Using List<int> for multiple quadruplets
• Using Dictionary instead of List
• Using fixed-size array for dynamic quadruplets

3. For the input array nums = [1, 0, -1, 0, -2, 2] and target 0, what does FourSum(nums, 0) return?
Assuming FourSum returns all unique quadruplets that sum to target.

medium

A. []

B. [[1, 0, -1, 0]]

C. [[-2, -1, 1, 2], [-2, 0, 0, 2], [-1, 0, 0, 1]]

D. [[0, 0, 0, 0]]

Solution

1. Step 1: Sort and find quadruplets summing to 0

   Sorting nums gives [-2, -1, 0, 0, 1, 2]. The unique quadruplets summing to 0 are [-2, -1, 1, 2], [-2, 0, 0, 2], and [-1, 0, 0, 1].

2. Step 2: Verify uniqueness and completeness

   All quadruplets are unique and sum exactly to 0, matching the expected output.

3. Final Answer:

   [[-2, -1, 1, 2], [-2, 0, 0, 2], [-1, 0, 0, 1]] -> Option C

4. Quick Check:

   Unique quadruplets sum to 0 = [[-2, -1, 1, 2], [-2, 0, 0, 2], [-1, 0, 0, 1]] [OK]

Hint: Sort array first, then find quadruplets with two pointers [OK]

Common Mistakes:

• Not sorting array before processing
• Including duplicate quadruplets
• Missing some valid quadruplets

4. Identify the bug in this C# snippet for the Four Sum Problem:

for (int i = 0; i < nums.Length - 3; i++) {
    for (int j = i + 1; j < nums.Length - 2; j++) {
        int left = j + 1, right = nums.Length - 1;
        while (left < right) {
            int sum = nums[i] + nums[j] + nums[left] + nums[right];
            if (sum == target) {
                result.Add(new List<int> { nums[i], nums[j], nums[left], nums[right] });
                left++;
                right--;
            } else if (sum < target) {
                left++;
            } else {
                right--;
            }
        }
    }
}

medium

A. No check to skip duplicate quadruplets causing duplicates in result

B. Incorrect initialization of left and right pointers

C. Wrong loop ranges for i and j causing index out of range

D. Missing sorting of the input array before processing

Solution

1. Step 1: Analyze duplicate handling

   The code adds quadruplets without skipping duplicates, so repeated quadruplets can appear in the result.

2. Step 2: Check other parts

   Left and right pointers are correctly initialized; loop ranges are valid; sorting is assumed done before this snippet.

3. Final Answer:

   No check to skip duplicate quadruplets causing duplicates in result -> Option A

4. Quick Check:

   Missing duplicate skip = No check to skip duplicate quadruplets causing duplicates in result [OK]

Hint: Always skip duplicates after finding quadruplets [OK]

Common Mistakes:

• Not skipping duplicates for i, j, left, right
• Assuming sorting is done inside the loop
• Incorrect pointer updates causing infinite loops

5. Given the array nums = [2, 2, 2, 2, 2] and target 8, what is the correct output of the Four Sum Problem algorithm that finds all unique quadruplets?

medium

A. [[2, 2, 2, 2], [2, 2, 2, 2]]

B. [[2, 2, 2, 2]]

C. []

D. [[2, 2, 2]]

Solution

1. Step 1: Understand the input and target

   All elements are 2, and target is 8, so quadruplets of four 2's sum to 8.

2. Step 2: Identify unique quadruplets

   Only one unique quadruplet [2, 2, 2, 2] exists despite duplicates in input.

3. Final Answer:

   [[2, 2, 2, 2]] -> Option B

4. Quick Check:

   Only one unique quadruplet sums to 8 [OK]

Hint: Duplicates form one unique quadruplet if sum matches target [OK]

Common Mistakes:

• Counting duplicate quadruplets multiple times
• Returning empty list when quadruplet exists
• Returning triplets instead of quadruplets