Why Doubly Linked List Over Singly Linked List in DSA C++ - See It Work

Why Doubly Linked List Over Singly Linked List

📖 Scenario: Imagine you are managing a playlist of songs where you want to move forward and backward easily between songs.

🎯 Goal: You will build a simple doubly linked list to understand why it is better than a singly linked list for moving both forward and backward.

📋 What You'll Learn

Create a doubly linked list with three nodes containing values 10, 20, and 30

Add a pointer variable to track the current node

Move the current pointer forward and backward using the doubly linked list

Print the values of the nodes as you move forward and backward

💡 Why This Matters

🌍 Real World

Doubly linked lists are used in music players, web browsers (back and forward buttons), and undo-redo features where moving both directions is needed.

💼 Career

Understanding doubly linked lists helps in software development roles that require efficient data navigation and manipulation, such as game development, UI programming, and systems programming.

1

Create a doubly linked list with three nodes

Create a struct called Node with int data, Node* next, and Node* prev. Then create three nodes named node1, node2, and node3 with data values 10, 20, and 30 respectively. Link them so that node1.next = &node2, node2.next = &node3, node2.prev = &node1, and node3.prev = &node2.

DSA C++

// Define Node struct and create three linked nodes
// Your code here

Hint

Start by defining the Node structure with data and two pointers. Then create three nodes and link their next and prev pointers accordingly.

2

Add a pointer to track the current node

Create a pointer variable called current and set it to point to &node1.

DSA C++

struct Node {
    int data;
    Node* next;
    Node* prev;
};

Node node1 = {10, nullptr, nullptr};
Node node2 = {20, nullptr, nullptr};
Node node3 = {30, nullptr, nullptr};

node1.next = &node2;
node2.prev = &node1;
node2.next = &node3;
node3.prev = &node2;

// Create a pointer called current and set it to &node1
// Your code here

Hint

Use a pointer variable to keep track of the current node you are on in the list.

3

Move the current pointer forward and backward

Move the current pointer forward to the next node by setting current = current->next. Then move it backward to the previous node by setting current = current->prev.

DSA C++

struct Node {
    int data;
    Node* next;
    Node* prev;
};

Node node1 = {10, nullptr, nullptr};
Node node2 = {20, nullptr, nullptr};
Node node3 = {30, nullptr, nullptr};

node1.next = &node2;
node2.prev = &node1;
node2.next = &node3;
node3.prev = &node2;

Node* current = &node1;

// Move current forward to next node
// Move current backward to previous node
// Your code here

Hint

Use the next pointer to move forward and the prev pointer to move backward in the list.

4

Print the values while moving forward and backward

Print the data of the current node after moving forward and then after moving backward using std::cout. Use std::endl to print each value on a new line.

DSA C++

struct Node {
    int data;
    Node* next;
    Node* prev;
};

Node node1 = {10, nullptr, nullptr};
Node node2 = {20, nullptr, nullptr};
Node node3 = {30, nullptr, nullptr};

node1.next = &node2;
node2.prev = &node1;
node2.next = &node3;
node3.prev = &node2;

Node* current = &node1;

current = current->next;
// Print current data
// Move current backward
// Print current data
// Your code here

Hint

Print the data after moving forward and then after moving backward to see how doubly linked list allows easy navigation both ways.

Practice

1. Why is a doubly linked list preferred over a singly linked list when you need to traverse the list backwards?

easy

A. Because doubly linked lists use less memory than singly linked lists.

B. Because singly linked lists have pointers to previous nodes only.

C. Because doubly linked lists have pointers to both next and previous nodes, allowing backward traversal.

D. Because singly linked lists can only store integer data.

Solution

1. Step 1: Understand pointer directions in linked lists

   Singly linked lists have pointers only to the next node, so you cannot move backwards easily. Doubly linked lists have pointers to both next and previous nodes.

2. Step 2: Identify traversal capability

   Because doubly linked lists have previous pointers, they allow traversal in both directions, including backwards.

3. Final Answer:

   Because doubly linked lists have pointers to both next and previous nodes, allowing backward traversal. -> Option C

4. Quick Check:

   Backward traversal needs previous pointers = A [OK]

Hint: Backward traversal needs previous pointers in nodes [OK]

Common Mistakes:

• Thinking singly linked lists have previous pointers
• Confusing memory usage with traversal ability
• Assuming singly linked lists can traverse backwards

2. Which of the following is the correct way to declare a node structure for a doubly linked list in C++?

easy

A. struct Node { int data; Node* prev; Node* next; };

B. struct Node { int data; Node* prev; };

C. struct Node { int data; Node* next; };

D. struct Node { int data; Node* next; Node* next; };

Solution

1. Step 1: Identify required pointers for doubly linked list node

   A doubly linked list node must have pointers to both the previous and next nodes.

2. Step 2: Match the structure declaration

   struct Node { int data; Node* prev; Node* next; }; declares both Node* prev and Node* next, which is correct. Others miss one pointer or have duplicate pointers.

3. Final Answer:

   struct Node { int data; Node* prev; Node* next; }; -> Option A

4. Quick Check:

   Doubly linked list node needs prev and next pointers = C [OK]

Hint: Doubly linked list nodes have prev and next pointers [OK]

Common Mistakes:

• Missing prev pointer in node structure
• Duplicating next pointer instead of prev
• Confusing singly linked list node with doubly linked list node

3. You need to implement a feature that allows moving both forward and backward through a list of songs in a music player. Why is a doubly linked list a better choice than a singly linked list for this feature?

easy

A. Because singly linked lists use less memory and are faster for this feature.

B. Because singly linked lists automatically reverse the list when needed.

C. Because doubly linked lists can store song metadata directly in nodes.

D. Because doubly linked lists allow efficient backward and forward traversal.

Solution

1. Step 1: Understand traversal needs in music player

   The feature requires moving forward and backward through songs, so traversal in both directions is needed.

2. Step 2: Compare singly and doubly linked lists for traversal

   Singly linked lists only allow forward traversal easily, while doubly linked lists have pointers to previous nodes, enabling backward traversal efficiently.

3. Final Answer:

   Because doubly linked lists allow efficient backward and forward traversal. -> Option D

4. Quick Check:

   Bidirectional traversal needs doubly linked list = B [OK]

Hint: Bidirectional traversal needs doubly linked list [OK]

Common Mistakes:

• Assuming singly linked lists can traverse backward easily
• Confusing memory usage with traversal capability
• Thinking doubly linked lists store metadata differently

4. Consider the following C++ code snippet for a doubly linked list insertion at the end. What will be the output after inserting nodes with values 10 and 20?

medium

A. 10 <-> 20 <-> null

B. 20 <-> 10 <-> null

C. 10 -> 20 -> null

D. null <- 10 <- 20

Solution

1. Step 1: Understand insertion at end in doubly linked list

   Inserting 10 first creates a node with data 10. Inserting 20 next adds it after 10, linking 10's next to 20 and 20's prev to 10.

2. Step 2: Visualize the list after insertions

   The list looks like: 10 <-> 20 <-> null, showing bidirectional links and null at the end.

3. Final Answer:

   10 <-> 20 <-> null -> Option A

4. Quick Check:

   Insertion at end keeps order 10 then 20 = D [OK]

Hint: Insertion at end appends nodes in order [OK]

Common Mistakes:

• Reversing node order after insertion
• Using singly linked list arrow notation
• Ignoring prev pointer links

5. The following code attempts to delete a node from a doubly linked list but causes a runtime error. What is the main issue?

void deleteNode(Node* del) {
  if (del == nullptr) return;
  if (del->prev != nullptr) del->prev->next = del->next;
  if (del->next != nullptr) del->next->prev = del->prev;
  delete del;
}

medium

A. It deletes the node before updating pointers.

B. It does not update the head pointer if the deleted node is the head.

C. It does not check if del is the tail node.

D. It uses incorrect pointer syntax.

Solution

1. Step 1: Analyze pointer updates in deletion

   The code updates previous and next nodes' pointers correctly but does not handle the case when the node to delete is the head (no prev).

2. Step 2: Identify missing head update

   If the node is head, the external head pointer must be updated to del->next, which is missing, causing dangling head pointer and runtime errors.

3. Final Answer:

   It does not update the head pointer if the deleted node is the head. -> Option B

4. Quick Check:

   Head node deletion needs head pointer update = A [OK]

Hint: Always update head if deleting the first node [OK]

Common Mistakes:

• Deleting node before fixing pointers
• Ignoring head pointer update
• Confusing tail node handling with head node