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DSA C++programming~10 mins

Why Circular Linked List and Real World Use Cases in DSA C++ - Test Your Knowledge

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to create a circular linked list by linking the last node back to the head.

DSA C++
Node* head = new Node(1);
Node* second = new Node(2);
head->next = second;
second->next = [1];
Drag options to blanks, or click blank then click option'
Asecond
Bnullptr
Chead
Dnew Node(3)
Attempts:
3 left
💡 Hint
Common Mistakes
Setting the last node's next to nullptr breaks the circular link.
Pointing last node to itself creates a single-node loop, not the intended list.
2fill in blank
medium

Complete the code to traverse a circular linked list starting from head and stop after one full cycle.

DSA C++
Node* current = head;
do {
    std::cout << current->data << " -> ";
    current = [1];
} while (current != head);
std::cout << "null";
Drag options to blanks, or click blank then click option'
Acurrent->next
Bhead
Cnullptr
Dcurrent
Attempts:
3 left
💡 Hint
Common Mistakes
Using head traverses only the first node.
Using nullptr causes a null pointer dereference.
3fill in blank
hard

Fix the error in the code to insert a new node after the head in a circular linked list.

DSA C++
Node* newNode = new Node(5);
newNode->next = head->next;
head->next = [1];
Drag options to blanks, or click blank then click option'
AnewNode
Bhead->next
Cnullptr
Dhead
Attempts:
3 left
💡 Hint
Common Mistakes
Assigning head->next to head causes a loop.
Assigning head->next to nullptr breaks the list.
4fill in blank
hard

Fill both blanks to create a function that checks if a circular linked list contains a value.

DSA C++
bool contains(Node* head, int value) {
    if (!head) return false;
    Node* current = head;
    do {
        if (current->data [1] value) return true;
        current = [2];
    } while (current != head);
    return false;
}
Drag options to blanks, or click blank then click option'
A==
B!=
Ccurrent->next
Dhead
Attempts:
3 left
💡 Hint
Common Mistakes
Using != instead of == causes wrong condition.
Moving current to head checks only the first node.
5fill in blank
hard

Fill all three blanks to create a function that counts nodes in a circular linked list.

DSA C++
int countNodes(Node* head) {
    if (!head) return 0;
    int count = 0;
    Node* current = [1];
    do {
        count [2] 1;
        current = [3];
    } while (current != head);
    return count;
}
Drag options to blanks, or click blank then click option'
Ahead
B+=
Ccurrent->next
Dnullptr
Attempts:
3 left
💡 Hint
Common Mistakes
Starting current at nullptr causes no counting.
Using = instead of += does not increment count properly.

Practice

(1/5)
1. What is a key advantage of using a circular linked list over a singly linked list?
easy
A. It prevents duplicate elements
B. It uses less memory than a singly linked list
C. It automatically sorts the elements
D. It allows continuous traversal from any node without stopping

Solution

  1. Step 1: Understand traversal in singly linked list

    A singly linked list ends at the last node which points to null, so traversal stops there.
  2. Step 2: Understand traversal in circular linked list

    In a circular linked list, the last node points back to the first node, allowing continuous traversal from any node.
  3. Final Answer:

    It allows continuous traversal from any node without stopping -> Option D
  4. Quick Check:

    Continuous traversal = Advantage of circular linked list [OK]
Hint: Circular lists loop back to start, enabling endless traversal [OK]
Common Mistakes:
  • Thinking circular lists use less memory
  • Assuming circular lists sort elements automatically
  • Believing circular lists prevent duplicates
2. Which of the following is the correct way to make a singly linked list node point to itself in C++ to form a circular linked list?
easy
A. node->next = node;
B. node->next = nullptr;
C. node->next = head;
D. node->next = NULL;

Solution

  1. Step 1: Understand node pointing in circular linked list

    For a single node circular list, the node's next pointer must point to itself to form a loop.
  2. Step 2: Check the options

    node->next = node; sets node->next = node, correctly making the node point to itself.
  3. Final Answer:

    node->next = node; -> Option A
  4. Quick Check:

    Self-pointing node = node->next = node [OK]
Hint: Self-loop means node points to itself with node->next = node [OK]
Common Mistakes:
  • Using nullptr or NULL breaks the circular link
  • Setting next to head without defining head
  • Confusing NULL and node pointer
3. Consider the following C++ code snippet for a circular linked list traversal:
struct Node {
  int data;
  Node* next;
};

void printList(Node* head) {
  Node* temp = head;
  if (head != nullptr) {
    do {
      std::cout << temp->data << " -> ";
      temp = temp->next;
    } while (temp != head);
  }
  std::cout << "null" << std::endl;
}

If the list has nodes with data 10, 20, 30 linked circularly, what will be the output of printList(head)?
medium
A. 10 -> 20 -> 30 -> 30 -> null
B. 10 -> 20 -> 30 -> null
C. 10 -> 20 -> 30 -> 10 -> 20 -> 30 -> null
D. null

Solution

  1. Step 1: Understand the traversal loop

    The do-while loop prints current node data, then moves to next node, stopping when it reaches head again.
  2. Step 2: Trace the output for nodes 10, 20, 30

    It prints 10, then 20, then 30, then stops because next is head again.
  3. Final Answer:

    10 -> 20 -> 30 -> null -> Option B
  4. Quick Check:

    One full cycle print = 10 -> 20 -> 30 -> null [OK]
Hint: do-while prints once per node until back to head [OK]
Common Mistakes:
  • Thinking it prints infinitely
  • Confusing do-while with while loop
  • Missing the stopping condition temp == head
4. The following code attempts to insert a new node at the end of a circular linked list but causes an infinite loop. What is the error?
void insertEnd(Node*& head, int val) {
  Node* newNode = new Node{val, nullptr};
  if (!head) {
    head = newNode;
    return;
  }
  Node* temp = head;
  while (temp->next != nullptr) {
    temp = temp->next;
  }
  temp->next = newNode;
  newNode->next = head;
}
medium
A. The newNode is not allocated with new keyword
B. The newNode->next should be nullptr, not head
C. The while loop condition should check for temp->next != head, not nullptr
D. The head pointer is not updated after insertion

Solution

  1. Step 1: Analyze the while loop condition

    In a circular linked list, last node's next points to head, not nullptr, so checking for nullptr causes infinite loop.
  2. Step 2: Correct the condition to stop at last node

    The condition should be temp->next != head to stop at the last node before insertion.
  3. Final Answer:

    The while loop condition should check for temp->next != head, not nullptr -> Option C
  4. Quick Check:

    Loop stops at last node by checking next != head [OK]
Hint: In circular list, last node points to head, not nullptr [OK]
Common Mistakes:
  • Using nullptr in loop condition for circular list
  • Setting newNode->next to nullptr breaking circularity
  • Not updating head when list is empty
5. Which real-world scenario best fits the use of a circular linked list?
hard
A. Implementing a music playlist that loops songs continuously
B. Storing a sorted list of unique user IDs
C. Managing a stack of undo operations
D. Representing a binary search tree for fast lookup

Solution

  1. Step 1: Understand circular linked list use cases

    Circular linked lists are ideal for scenarios needing continuous looping through elements without stopping.
  2. Step 2: Match options to use cases

    A music playlist that loops songs continuously fits perfectly because after the last song, it returns to the first.
  3. Final Answer:

    Implementing a music playlist that loops songs continuously -> Option A
  4. Quick Check:

    Continuous looping = music playlist use case [OK]
Hint: Continuous looping fits circular linked list use cases [OK]
Common Mistakes:
  • Choosing sorted list which needs order, not circularity
  • Confusing stack with linked list type
  • Mixing tree structures with linked lists
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10 questions~5 mineasy hard