Complete the code to create a circular linked list by linking the last node back to the head.
Node* head = new Node(1); Node* second = new Node(2); head->next = second; second->next = [1];
In a circular linked list, the last node points back to the head node, making the list circular.
Complete the code to traverse a circular linked list starting from head and stop after one full cycle.
Node* current = head;
do {
std::cout << current->data << " -> ";
current = [1];
} while (current != head);
std::cout << "null";To move through the list, we update current to current->next each time.
Fix the error in the code to insert a new node after the head in a circular linked list.
Node* newNode = new Node(5); newNode->next = head->next; head->next = [1];
We must link head's next to the new node to insert it after head.
Fill both blanks to create a function that checks if a circular linked list contains a value.
bool contains(Node* head, int value) {
if (!head) return false;
Node* current = head;
do {
if (current->data [1] value) return true;
current = [2];
} while (current != head);
return false;
}We compare current data to value using == and move current to current->next.
Fill all three blanks to create a function that counts nodes in a circular linked list.
int countNodes(Node* head) {
if (!head) return 0;
int count = 0;
Node* current = [1];
do {
count [2] 1;
current = [3];
} while (current != head);
return count;
}Start from head, increment count by 1 each step, and move to next node until back to head.
