Why Subarray Sum Equals K Using Hash Map in DSA C++?

The Big Idea

What if you could instantly spot any group of days adding up to your exact target without checking each one?

The Scenario

Imagine you have a long list of daily expenses and want to find if any continuous days add up exactly to your budget.

Doing this by checking every possible group of days one by one is like counting every grain of sand on a beach--it takes forever!

The Problem

Manually checking all possible continuous groups means trying every start and end day combination.

This is very slow and tiresome, especially if the list is long.

You might also lose track and make mistakes counting sums repeatedly.

The Solution

Using a hash map, we keep track of sums we've seen so far.

This lets us quickly find if a previous sum matches the current sum minus the target, meaning a subarray adds up to the target.

It's like having a smart assistant who remembers all your partial totals and points out the right group instantly.

Before vs After

✗ Before

for (int start = 0; start < n; ++start) {
  int sum = 0;
  for (int end = start; end < n; ++end) {
    sum += nums[end];
    if (sum == k) count++;
  }
}

✓ After

unordered_map<int, int> sum_counts;
sum_counts[0] = 1;
int current_sum = 0;
for (int num : nums) {
  current_sum += num;
  if (sum_counts.count(current_sum - k)) count += sum_counts[current_sum - k];
  sum_counts[current_sum]++;
}

What It Enables

This method lets you find all continuous groups summing to a target in just one pass, saving time and effort.

Real Life Example

Tracking your calorie intake daily, you want to find if any consecutive days add up exactly to your diet goal.

This helps you spot patterns quickly without tedious calculations.

Key Takeaways

Manual checking of all subarrays is slow and error-prone.

Hash map remembers sums to find matching subarrays fast.

Enables quick detection of continuous sums equal to target in one pass.

Practice

1. What is the main purpose of using a hash map in the Subarray Sum Equals K problem?

easy

A. To keep track of the maximum subarray length

B. To sort the array elements before processing

C. To store the original array elements as keys

D. To store cumulative sums and their frequencies for quick lookup

Solution

1. Step 1: Understand the problem goal

   The problem requires finding subarrays whose sums equal a target value k.

2. Step 2: Role of hash map in solution

   The hash map stores cumulative sums and their counts to quickly check if a previous sum exists that forms a subarray summing to k.

3. Final Answer:

   To store cumulative sums and their frequencies for quick lookup -> Option D

4. Quick Check:

   Hash map stores sums = D [OK]

Hint: Hash map tracks sums to find subarrays fast [OK]

Common Mistakes:

• Using hash map to sort elements
• Storing array elements as keys instead of sums
• Trying to track max length instead of counts

2. Which of the following is the correct C++ syntax to declare a hash map for storing int keys and values?

easy

A. std::unordered_map map;

B. std::map<int> map;

C. unordered_map map;

D. std::hash_map map;

Solution

1. Step 1: Identify correct hash map declaration

   In C++, std::unordered_map<Key, Value> is used for hash maps.

2. Step 2: Check syntax correctness

   std::unordered_map map; uses correct template syntax and namespace. Others have syntax errors or wrong types.

3. Final Answer:

   std::unordered_map map; -> Option A

4. Quick Check:

   Correct unordered_map syntax = A [OK]

Hint: Use std::unordered_map for hash maps [OK]

Common Mistakes:

• Missing template brackets <>
• Using std::map instead of unordered_map for hash map
• Wrong order of template parameters

3. What will be the output of the following C++ code snippet?

std::vector<int> nums = {1, 2, 3};
int k = 3;
int count = 0;
std::unordered_map prefixSumCount;
prefixSumCount[0] = 1;
int sum = 0;
for (int num : nums) {
    sum += num;
    if (prefixSumCount.find(sum - k) != prefixSumCount.end()) {
        count += prefixSumCount[sum - k];
    }
    prefixSumCount[sum]++;
}
std::cout << count << std::endl;

medium

A. 2

B. 1

C. 3

D. 0

Solution

1. Step 1: Calculate prefix sums and counts

   Prefix sums: 1, 3, 6. Check if (sum - k) exists in map: - sum=1: 1-3=-2 not found - sum=3: 3-3=0 found, count=1 - sum=6: 6-3=3 found, count=1+1=2

2. Step 2: Final count of subarrays with sum k

   Count is 2 because subarrays [1,2] and [3] sum to 3.

3. Final Answer:

   2 -> Option A

4. Quick Check:

   Subarrays summing to 3 = 2 [OK]

Hint: Track prefix sums and check sum-k in map [OK]

Common Mistakes:

• Not initializing prefixSumCount[0] = 1
• Incorrectly updating count
• Confusing sum and sum-k keys

4. Identify the bug in the following code snippet for counting subarrays summing to k:

int subarraySum(std::vector<int>& nums, int k) {
    std::unordered_map map;
    int count = 0, sum = 0;
    for (int num : nums) {
        sum += num;
        if (map.find(sum - k) != map.end()) {
            count += map[sum - k];
        }
        map[sum] = 1;
    }
    return count;
}

medium

A. count should be incremented by 1 only

B. sum should be reset to 0 inside the loop

C. map[sum] should be incremented, not set to 1

D. map should be a vector instead of unordered_map

Solution

1. Step 1: Analyze map update logic

   Setting map[sum] = 1 overwrites previous counts, losing frequency data.

2. Step 2: Correct way to update map

   We must increment map[sum] to count all occurrences of the prefix sum.

3. Final Answer:

   map[sum] should be incremented, not set to 1 -> Option C

4. Quick Check:

   Increment map[sum] to track frequencies [OK]

Hint: Increment map[sum] to count frequencies, not overwrite [OK]

Common Mistakes:

• Overwriting map[sum] instead of incrementing
• Resetting sum inside loop incorrectly
• Using wrong data structure for map

5. Given an array nums = {3, 4, 7, 2, -3, 1, 4, 2} and k = 7, how many subarrays sum to k? Use the hash map approach to find the count.

hard

A. 3

B. 5

C. 4

D. 6

Solution

1. Step 1: Calculate prefix sums and track counts

   Prefix sums: 3,7,14,16,13,14,18,20.
   Map checks (sum-k found):
   - sum=7: 0 (+1) -> count=1
   - sum=14: 7 (+1) -> count=2
   - sum=14 (2nd): 7 (+1) -> count=3
   - sum=20: 13 (+1) -> count=4
   - sum=18: 11 (+1) -> count=5 (Note: 11 is sum-k for k=7 at sum=18, check if 11 exists in map)

2. Step 2: Final count of subarrays

   Total 5 subarrays: [3,4], [7], [7,2,-3,1], [1,4,2], and [4,7,2,-3,-3].

3. Final Answer:

   5 -> Option B

4. Quick Check:

   Count of subarrays with sum 7 = 5 [OK]

Hint: Track prefix sums and count matches for sum-k [OK]

Common Mistakes:

• Not incrementing count for multiple occurrences
• Missing negative numbers effect on sums
• Incorrect prefix sum updates