What if you could manage your tasks so easily that undoing mistakes feels like magic?
Why Stack Implementation Using Array in DSA C++?
Imagine you have a stack of plates on your kitchen counter. You can only add or remove the top plate. Now, think about trying to keep track of these plates using just a list of numbers without any order or rules.
Without a clear system, adding or removing plates becomes confusing and slow. You might accidentally remove the wrong plate or spend too much time searching for the top one. This manual way is error-prone and wastes time.
A stack using an array works like that neat stack of plates. It keeps track of the top plate with a simple number, so adding or removing plates is quick and safe. This system makes managing the plates easy and error-free.
int plates[100]; int count = 0; // To add a plate plates[count] = new_plate; count++; // To remove a plate count--; return plates[count];
class Stack { int arr[100]; int top = -1; public: void push(int x) { arr[++top] = x; } int pop() { return arr[top--]; } };
This lets you quickly add or remove items in a last-in, first-out order, perfect for undo actions, expression evaluation, and more.
Think about the undo button in a text editor. Each action you do is pushed onto a stack. When you press undo, the last action is popped off and reversed.
Manual tracking of last-in items is slow and error-prone.
Stack with array uses a simple top pointer to manage items efficiently.
Enables fast last-in, first-out operations useful in many real-world tasks.
Practice
Solution
Step 1: Understand stack storage
A stack stores elements in a linear order, last-in first-out (LIFO).Step 2: Role of array in stack
An array provides a fixed-size linear structure to hold stack elements efficiently.Final Answer:
To store elements in a fixed-size linear structure -> Option AQuick Check:
Stack uses array for fixed linear storage [OK]
- Confusing stack with queue or tree
- Thinking array sorts elements automatically
- Assuming stack allows random access
Solution
Step 1: Recall C++ array declaration syntax
In C++, arrays are declared as: type name[size];Step 2: Match with options
int stack[10]; matches correct syntax: int stack[10];Final Answer:
int stack[10]; -> Option BQuick Check:
C++ array declaration = int stack[10]; [OK]
- Using parentheses instead of brackets
- Wrong order of type and name
- Using non-existent 'array' keyword
int stack[5]; int top = -1; // Push 10 stack[++top] = 10; // Push 20 stack[++top] = 20; // Pop int x = stack[top--]; // Push 30 stack[++top] = 30; // Print top element std::cout << stack[top];
Solution
Step 1: Trace stack operations step-by-step
Initially top = -1.
Push 10: top=0, stack[0]=10
Push 20: top=1, stack[1]=20
Pop: x=stack[1]=20, top=0
Push 30: top=1, stack[1]=30Step 2: Identify top element after operations
Top is 1, stack[1] = 30, so output is 30.Final Answer:
30 -> Option DQuick Check:
Last pushed after pop is 30 [OK]
- Confusing push and pop order
- Not updating top correctly
- Assuming pop removes element permanently
void push(int stack[], int &top, int size, int value) {
if (top == size) {
std::cout << "Stack Overflow";
return;
}
stack[++top] = value;
}Solution
Step 1: Understand overflow condition
Array indices go from 0 to size-1, so top can be max size-1.Step 2: Check condition in code
Condition 'top == size' is wrong; it should be 'top == size - 1' to prevent overflow.Final Answer:
The condition should be 'top == size - 1' to check overflow -> Option CQuick Check:
Overflow check uses top == size - 1 [OK]
- Checking top == size instead of size - 1
- Incrementing top incorrectly
- Ignoring overflow condition
push(5); push(10); pop(); push(15); push(20); push(25); pop();
Assume stack is initially empty and top = -1. Choose the correct stack content from bottom to top.
Solution
Step 1: Execute operations step-by-step
Start: top = -1, stack empty.
push(5): top=0, stack[0]=5
push(10): top=1, stack[1]=10
pop(): removes 10, top=0
push(15): top=1, stack[1]=15
push(20): top=2, stack[2]=20
push(25): top=3, stack[3]=25 (stack full)
pop(): removes 25, top=2Step 2: Final stack content
Stack from bottom to top: 5 (index 0), 15 (index 1), 20 (index 2). So output is 5 -> 15 -> 20 -> null.Final Answer:
5 -> 15 -> 20 -> null -> Option AQuick Check:
Track push/pop changes carefully [OK]
- Ignoring pop effects on top
- Assuming stack grows beyond size
- Confusing order of elements
Ready to prove it?
Pass the test and this pattern moves unknown
