Push Operation on Stack in DSA C++ - Time & Space Complexity
We want to understand how the time needed to add an item to a stack changes as the stack grows.
How does pushing an element affect the total work done?
Analyze the time complexity of the following code snippet.
void push(int value) {
if (top == capacity - 1) {
// Stack is full, resize or error
return;
}
top++;
arr[top] = value;
}
This code adds a new value to the top of the stack if there is space.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: Assigning the new value to the top position in the array.
- How many times: Exactly once per push call.
Each push does the same small amount of work no matter how many items are already in the stack.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | 1 |
| 100 | 1 |
| 1000 | 1 |
Pattern observation: The work stays constant even as the stack grows.
Time Complexity: O(1)
This means pushing an item takes the same short time no matter how big the stack is.
[X] Wrong: "Pushing takes longer as the stack gets bigger because it has to move all the items."
[OK] Correct: The push operation only adds one item at the top without moving others, so time stays the same.
Knowing that push is a quick, constant-time operation helps you explain stack efficiency clearly in interviews.
"What if the stack needs to resize its array when full? How would the time complexity of push change then?"
Practice
push operation do in a stack?Solution
Step 1: Understand stack behavior
A stack follows Last In First Out (LIFO) principle, where elements are added or removed from the top.Step 2: Define push operation
The push operation adds a new element on top of the existing stack elements.Final Answer:
Adds an element to the top of the stack -> Option DQuick Check:
Push = Add top element [OK]
- Confusing push with pop operation
- Thinking push removes elements
- Assuming push checks stack emptiness
stk in C++ STL?Solution
Step 1: Recall C++ STL stack methods
The standard method to add an element to a stack ispush().Step 2: Match correct syntax
Usingstk.push(10);correctly pushes 10 onto the stack.Final Answer:
stk.push(10); -> Option AQuick Check:
push() is the correct method [OK]
- Using add(), insert(), or append() which are not stack methods
- Forgetting parentheses after push
- Confusing vector methods with stack
std::stack<int> stk; stk.push(5); stk.push(10); stk.push(15); int topElement = stk.top();
What is the value of
topElement?Solution
Step 1: Trace push operations
Elements pushed in order: 5, then 10, then 15. Stack top is last pushed element.Step 2: Identify top element
The top element after pushes is 15, as it was pushed last.Final Answer:
15 -> Option AQuick Check:
Last pushed = top element = 15 [OK]
- Choosing first pushed element as top
- Confusing top() with pop()
- Assuming stack is empty initially
std::stack<int> stk; stk.push 20;
Solution
Step 1: Check push syntax
The push method requires parentheses around the argument, likepush(20).Step 2: Identify syntax error
Code usesstk.push 20;missing parentheses, causing a syntax error.Final Answer:
Missing parentheses in push call -> Option CQuick Check:
push() needs parentheses [OK]
- Omitting parentheses after push
- Confusing push with pop syntax
- Assuming stack declaration is wrong
std::stack<int> stk; stk.push(1); stk.push(2); stk.push(3); stk.pop(); stk.push(4);
Choose the correct sequence of elements from top to bottom.
Solution
Step 1: Trace push and pop operations
Push 1, stack: 1
Push 2, stack: 2 -> 1
Push 3, stack: 3 -> 2 -> 1
Pop removes top (3), stack: 2 -> 1
Push 4, stack: 4 -> 2 -> 1Step 2: Write final stack state
Top to bottom: 4 -> 2 -> 1 -> nullFinal Answer:
4 -> 2 -> 1 -> null -> Option BQuick Check:
Push/pop order = 4,2,1 [OK]
- Ignoring pop effect on stack
- Assuming push adds at bottom
- Mixing order of elements after pop
Ready to prove it?
Pass the test and this pattern moves unknown
