First, 10 is pushed, then 20 is pushed on top. Stack top is now 20.
Step 2: Apply pop and check top
pop() removes the top element (20), so top becomes 10. Printing top outputs 10.
Final Answer:
10 -> Option C
Quick Check:
After pop, top is 10 [OK]
Hint: Pop removes last pushed, top shows new top [OK]
Common Mistakes:
Assuming top remains 20 after pop
Confusing pop with peek
Expecting 0 or error output
4. Identify the error in the following code snippet that uses a stack:
std::stack<int> stk;
stk.pop();
stk.push(5);
medium
A. No error, code runs fine
B. Push should be called before pop
C. Stack declaration is incorrect
D. Pop called on empty stack causes runtime error
Solution
Step 1: Analyze stack state before pop
The stack is empty initially. Calling pop() on empty stack is invalid and causes runtime error.
Step 2: Check order of operations
Pop is called before any push, so no element exists to remove, causing error.
Final Answer:
Pop called on empty stack causes runtime error -> Option D
Quick Check:
Pop on empty stack causes error [OK]
Hint: Never pop from empty stack [OK]
Common Mistakes:
Ignoring empty stack before pop
Thinking push order fixes error
Assuming pop on empty is safe
5. Given a stack with elements 1, 2, 3, 4 pushed in that order (1 at bottom, 4 at top), what will be the stack content after performing two pop() operations?
hard
A. 1 -> 2 -> null
B. 3 -> 4 -> null
C. 1 -> 2 -> 3 -> null
D. 4 -> 3 -> 2 -> 1 -> null
Solution
Step 1: Understand initial stack order
Elements pushed in order: 1 (bottom), 2, 3, 4 (top). Stack looks like 1 -> 2 -> 3 -> 4 -> null.
Step 2: Apply two pop operations
First pop removes 4 (top), second pop removes 3 (new top). Remaining stack is 1 -> 2 -> null.
Final Answer:
1 -> 2 -> null -> Option A
Quick Check:
Two pops remove top two elements [OK]
Hint: Pop removes top elements one by one [OK]
Common Mistakes:
Confusing order of elements after pop
Listing popped elements instead of remaining
Reversing stack order incorrectly
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