Insert at End of Circular Linked List in DSA C++ - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is a circular linked list?

A circular linked list is a linked list where the last node points back to the first node, forming a circle with no null end.

beginner

Why do we need to update the last node's next pointer when inserting at the end of a circular linked list?

Because the last node's next pointer must always point to the first node to maintain the circular structure.

beginner

Inserting a new node at the end of an empty circular linked list results in what?

The new node points to itself, becoming both the first and last node in the list.

intermediate

What is the time complexity of inserting at the end of a circular linked list if you only have a pointer to the last node?

O(1) because you can directly access the last node and update pointers without traversal.

intermediate

Explain the steps to insert a new node at the end of a circular linked list.

1. Create a new node. 2. If list is empty, point new node to itself and update last pointer. 3. Else, set new node's next to last's next (first node). 4. Update last's next to new node. 5. Update last pointer to new node.

What does the last node's next pointer point to in a circular linked list?

A The first node

B Null

C Itself

D The previous node

In a circular linked list, the last node's next pointer always points to the first node to form a circle.

When inserting at the end of an empty circular linked list, what should the new node's next pointer point to?

A Null

B The first node

C Itself

D The last node

For an empty circular linked list, the new node points to itself to maintain the circular structure.

If you have a pointer to the last node, what is the time complexity to insert a new node at the end?

A O(1)

B O(log n)

C O(n)

D O(n^2)

Insertion at the end with a pointer to the last node is O(1) because no traversal is needed.

Which pointer must be updated to insert a new node at the end of a circular linked list?

A First node's next pointer

B Last node's next pointer only

C New node's next pointer only

D Both new node's next and last node's next pointers

Both the new node's next pointer and the last node's next pointer must be updated to maintain the circle.

After inserting a new node at the end, which node becomes the new last node?

A The old first node

B The new node inserted

C The old last node

D The node before the old last node

The newly inserted node at the end becomes the new last node.

Describe how to insert a new node at the end of a circular linked list when the list is empty and when it is not empty.

Think about how the circular link is maintained in both cases.

Explain why having a pointer to the last node makes insertion at the end of a circular linked list efficient.

Consider what would happen if you only had a pointer to the first node.

Practice

1. What happens when you insert a new node at the end of an empty circular linked list?

easy

A. The new node points to itself, becoming the only node in the list.

B. The new node points to null, ending the list.

C. The new node is discarded because the list is empty.

D. The new node points to the head, but the list remains empty.

Solution

1. Step 1: Understand circular linked list empty state

   When the list is empty, there is no node, so the new node must point to itself to form a circle.

2. Step 2: Insert new node and update pointers

   The new node's next pointer is set to itself, making it the only node and the head of the list.

3. Final Answer:

   The new node points to itself, becoming the only node in the list. -> Option A

4. Quick Check:

   Empty list insertion creates a self-pointing node [OK]

Hint: New node points to itself if list is empty [OK]

Common Mistakes:

• Setting next pointer to null instead of itself
• Not updating the head pointer
• Assuming list remains empty after insertion

2. Which of the following is the correct syntax to insert a new node at the end of a circular linked list in C++?

easy

A. newNode->next = head; tail->next = newNode; tail = newNode;

B. newNode->next = nullptr; tail->next = newNode; tail = newNode;

C. newNode->next = tail; head->next = newNode; tail = newNode;

D. newNode->next = head; head->next = newNode; tail = newNode;

Solution

1. Step 1: Set new node's next to head

   In a circular linked list, the last node points to the head, so newNode->next = head.

2. Step 2: Update current tail's next and tail pointer

   Set tail->next to newNode to link the last node to new node, then update tail to newNode.

3. Final Answer:

   newNode->next = head; tail->next = newNode; tail = newNode; -> Option A

4. Quick Check:

   New node points to head, tail updated [OK]

Hint: Tail's next must point to new node, new node points to head [OK]

Common Mistakes:

• Setting newNode->next to nullptr instead of head
• Updating head->next instead of tail->next
• Not updating tail pointer after insertion

3. Given the circular linked list with nodes 10 -> 20 -> 30 -> (back to 10), what will be the list after inserting 40 at the end?

medium

A. 40 -> 10 -> 20 -> 30 -> (back to 40)

B. 10 -> 20 -> 30 -> (back to 40)

C. 10 -> 20 -> 30 -> 40 -> null

D. 10 -> 20 -> 30 -> 40 -> (back to 10)

Solution

1. Step 1: Identify current circular list structure

   The list is 10 -> 20 -> 30, and 30 points back to 10 forming a circle.

2. Step 2: Insert 40 at end and update pointers

   New node 40 points to head (10), old tail (30) points to 40, making list 10 -> 20 -> 30 -> 40 -> back to 10.

3. Final Answer:

   10 -> 20 -> 30 -> 40 -> (back to 10) -> Option D

4. Quick Check:

   New node added at end, circle maintained [OK]

Hint: New node points to head, old tail points to new node [OK]

Common Mistakes:

• Breaking the circle by pointing last node to null
• Inserting new node at start instead of end
• Not updating tail pointer

4. What is wrong with this code snippet for inserting at the end of a circular linked list?

void insertEnd(Node*& tail, int data) {
  Node* newNode = new Node(data);
  newNode->next = tail->next;
  tail = newNode;
}

medium

A. It sets newNode->next to null instead of head.

B. It deletes the old tail node accidentally.

C. It does not update the old tail's next pointer to newNode.

D. It inserts the new node at the beginning instead of the end.

Solution

1. Step 1: Check pointer updates in code

   The code sets newNode->next to tail->next (head), but does not update tail->next to newNode.

2. Step 2: Identify missing link update

   Without updating old tail's next pointer, the list breaks the circle and newNode is not linked properly.

3. Final Answer:

   It does not update the old tail's next pointer to newNode. -> Option C

4. Quick Check:

   Old tail's next must point to new node [OK]

Hint: Always update old tail's next to new node [OK]

Common Mistakes:

• Forgetting to update old tail's next pointer
• Setting newNode->next incorrectly
• Not updating tail pointer after insertion

5. You have a circular linked list with nodes 5 -> 15 -> 25 -> (back to 5). You want to insert a new node with value 35 at the end. After insertion, you mistakenly forget to update the tail pointer to the new node. What will be the effect on the list?

hard

A. The list will have 5 -> 15 -> 25 -> (back to 5) without 35.

B. The list will have 5 -> 15 -> 25 -> 35 -> (back to 5), but tail still points to 25.

C. The new node 35 will not be linked and will be lost.

D. The list will break and become linear ending at 25.

Solution

1. Step 1: Insert new node and link old tail

   New node 35 is linked after 25, and points back to head (5), so list is 5 -> 15 -> 25 -> 35 -> back to 5.

2. Step 2: Tail pointer not updated

   Tail still points to 25, so operations relying on tail may behave incorrectly, but list structure is intact.

3. Final Answer:

   The list will have 5 -> 15 -> 25 -> 35 -> (back to 5), but tail still points to 25. -> Option B

4. Quick Check:

   Tail pointer must update, else points to old last node [OK]

Hint: Tail pointer must update to new node after insertion [OK]

Common Mistakes:

• Assuming list breaks without tail update
• Thinking new node is lost if tail not updated
• Confusing tail pointer with node links