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DSA C++programming~20 mins

How Strings Work Differently Across Languages in DSA C++ - Debugging & Practice

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Challenge - 5 Problems
🎖️
String Mastery in C++
Get all challenges correct to earn this badge!
Test your skills under time pressure!
❓ Predict Output
intermediate
2:00remaining
Output of String Concatenation in C++
What is the output of the following C++ code snippet?
DSA C++
#include <iostream>
#include <string>

int main() {
    std::string a = "Hello";
    std::string b = "World";
    std::string c = a + b;
    std::cout << c << std::endl;
    return 0;
}
AHelloWorld
BHello World
CHelloWorld\n
DHello+World
Attempts:
2 left
💡 Hint
In C++, the + operator concatenates strings without adding spaces.
❓ Predict Output
intermediate
2:00remaining
String Immutability in C++ vs Python
What will be the output of this C++ code snippet?
DSA C++
#include <iostream>
#include <string>

int main() {
    std::string s = "abc";
    s[0] = 'z';
    std::cout << s << std::endl;
    return 0;
}
Azbc\n
Bzbc
CError: string is immutable
Dabc
Attempts:
2 left
💡 Hint
In C++, std::string characters can be changed by index.
❓ Predict Output
advanced
2:00remaining
Null Character in C++ String
What will be printed by this C++ code?
DSA C++
#include <iostream>
#include <string>

int main() {
    std::string s = "abc\0def";
    std::cout << s << std::endl;
    std::cout << s.size() << std::endl;
    return 0;
}
A
abc
7
B
abcdef
7
C
abcdef
3
D
abc
3
Attempts:
2 left
💡 Hint
std::string can contain null characters inside and counts them in size.
🧠 Conceptual
advanced
2:00remaining
Difference Between C-style Strings and std::string
Which statement correctly describes a key difference between C-style strings and std::string in C++?
Astd::string is a fixed size array; C-style strings can dynamically resize.
BC-style strings can store null characters inside; std::string cannot contain null characters.
CC-style strings are arrays of chars ending with a null character; std::string manages size internally and can contain null characters.
DBoth C-style strings and std::string are immutable and cannot be changed after creation.
Attempts:
2 left
💡 Hint
Think about how each stores and manages string length.
🔧 Debug
expert
3:00remaining
Why Does This C++ String Code Crash?
Consider this C++ code snippet. Why does it cause a runtime error?
DSA C++
#include <iostream>
#include <string>

int main() {
    const char* cstr = "hello";
    std::string s(cstr);
    s[10] = 'x';
    std::cout << s << std::endl;
    return 0;
}
AThe code has a syntax error in string initialization.
Bstd::string is immutable; modifying s[10] is not allowed.
CThe pointer cstr is null, so string initialization fails.
DAccessing s[10] is out of bounds causing undefined behavior and possible crash.
Attempts:
2 left
💡 Hint
Check the size of the string before accessing index 10.

Practice

(1/5)
1. In C++, which of the following correctly describes how strings are stored compared to Python strings?
easy
A. C++ strings are mutable sequences of characters, while Python strings are immutable.
B. Both C++ and Python strings are immutable sequences of characters.
C. C++ strings are immutable, but Python strings are mutable.
D. Both C++ and Python strings are mutable sequences of characters.

Solution

  1. Step 1: Understand C++ string mutability

    C++ std::string allows modification of characters after creation, so it is mutable.
  2. Step 2: Understand Python string mutability

    Python strings cannot be changed after creation; they are immutable.
  3. Final Answer:

    C++ strings are mutable sequences of characters, while Python strings are immutable. -> Option A
  4. Quick Check:

    Mutability difference = C++ strings are mutable sequences of characters, while Python strings are immutable. [OK]
Hint: Remember: C++ strings can change, Python strings cannot [OK]
Common Mistakes:
  • Thinking Python strings are mutable like lists
  • Assuming C++ strings are immutable like Python
  • Confusing character arrays with std::string
  • Believing both languages treat strings the same
2. Which of the following is the correct way to declare and initialize a string in C++?
easy
A. string s = 'hello';
B. std::string s = "hello";
C. char s = "hello";
D. string s = "hello";

Solution

  1. Step 1: Check correct string type and syntax

    In C++, std::string is the standard string class and strings use double quotes for literals.
  2. Step 2: Validate each option

    string s = 'hello'; uses single quotes which are for single characters, char s = "hello"; uses char for multiple characters, string s = "hello"; misses std:: namespace.
  3. Final Answer:

    std::string s = "hello"; -> Option B
  4. Quick Check:

    C++ string declaration = std::string s = "hello"; [OK]
Hint: Use std::string and double quotes for strings in C++ [OK]
Common Mistakes:
  • Using single quotes for strings
  • Forgetting std:: namespace
  • Using char type for strings
  • Mixing C-style strings with std::string syntax
3. What will be the output of the following C++ code?
std::string s = "abc";
s[1] = 'z';
std::cout << s << std::endl;
medium
A. abc
B. Compilation error
C. abcz
D. azc

Solution

  1. Step 1: Understand string indexing and mutability in C++

    std::string allows modifying characters by index, so s[1] = 'z' changes second character.
  2. Step 2: Apply the change and print

    Original string "abc" changes to "azc" after s[1] = 'z'. Output is "azc".
  3. Final Answer:

    azc -> Option D
  4. Quick Check:

    Mutable string index change = azc [OK]
Hint: C++ strings can be changed by index directly [OK]
Common Mistakes:
  • Expecting original string unchanged
  • Thinking strings are immutable like Python
  • Assuming compilation error due to indexing
  • Confusing with C-style char arrays
4. Identify the error in the following C++ code snippet:
std::string s = "hello";
s[5] = '!';
std::cout << s << std::endl;
medium
A. Compilation error: invalid assignment
B. No error, output: hello!
C. Runtime error: out of range access
D. Output: hello

Solution

  1. Step 1: Check string length and index used

    String "hello" has length 5, valid indices 0 to 4. Index 5 is out of range.
  2. Step 2: Understand behavior of out-of-range index assignment

    Accessing s[5] is undefined behavior; usually causes runtime error or silent bug.
  3. Final Answer:

    Runtime error: out of range access -> Option C
  4. Quick Check:

    Out of bounds index causes runtime error [OK]
Hint: Check string length before indexing to avoid runtime errors [OK]
Common Mistakes:
  • Assuming s[5] appends character
  • Expecting compilation error instead of runtime
  • Ignoring zero-based indexing
  • Confusing with push_back method
5. Given the following C++ code, what will be the output?
std::string s = "test";
char* p = &s[0];
p[2] = 'x';
std::cout << s << std::endl;

How does this behavior compare to Python strings?
hard
A. Output: text; C++ strings are mutable, Python strings are immutable.
B. Output: test; Both C++ and Python strings are immutable.
C. Output: text; Both C++ and Python strings are mutable.
D. Compilation error due to pointer usage.

Solution

  1. Step 1: Analyze pointer modification on std::string

    Pointer p points to first character of s. Changing p[2] modifies s[2] to 'x'.
  2. Step 2: Compare with Python string behavior

    C++ strings allow character modification; Python strings do not allow such changes (immutable).
  3. Final Answer:

    Output: text; C++ strings are mutable, Python strings are immutable. -> Option A
  4. Quick Check:

    Pointer modifies string in C++, Python strings immutable [OK]
Hint: C++ strings allow pointer edits; Python strings never do [OK]
Common Mistakes:
  • Expecting compilation error from pointer usage
  • Assuming Python strings can be changed similarly
  • Confusing pointer with string copy
  • Ignoring zero-based indexing in modification
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