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DSA C++programming~30 mins

Doubly Linked List Structure and Node Design in DSA C++ - Build from Scratch

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Doubly Linked List Structure and Node Design
📖 Scenario: Imagine you are building a simple music playlist app. Each song can be played forward or backward, so you need a structure that allows moving in both directions easily.
🎯 Goal: You will create a basic doubly linked list structure with nodes that hold song names. This will help you understand how nodes connect forward and backward.
📋 What You'll Learn
Create a Node class with string data, Node* next, and Node* prev members
Create a DoublyLinkedList class with a Node* head pointer
Initialize the list with one node containing the song name "Song1"
Set the next and prev pointers of the node to nullptr
💡 Why This Matters
🌍 Real World
Doubly linked lists are used in music players, browsers (back and forward buttons), and many applications where you need to move in both directions through data.
💼 Career
Understanding doubly linked lists is fundamental for software developers working with data structures, improving problem-solving skills and preparing for technical interviews.
Progress0 / 4 steps
1
Create the Node class
Create a Node class with a public string data member, and two public pointers: Node* next and Node* prev. Add a constructor that takes a string parameter called songName and sets data to it, and initializes next and prev to nullptr.
DSA C++
Hint

Remember to include string and pointer members for next and prev. Initialize pointers to nullptr in the constructor.

2
Create the DoublyLinkedList class with head pointer
Create a DoublyLinkedList class with a public pointer Node* head. Add a constructor that initializes head to nullptr.
DSA C++
Hint

Make sure the head pointer is public and set to nullptr in the constructor.

3
Initialize the list with one node
Inside the DoublyLinkedList class, add a public method void initialize() that creates a new Node with data "Song1" and sets head to point to this new node.
DSA C++
Hint

Create a method called initialize that sets head to a new Node with "Song1".

4
Print the list starting from head
In the main() function, create a DoublyLinkedList object called playlist. Call playlist.initialize(). Then print the data of the head node using cout.
DSA C++
Hint

Create the playlist object, call initialize(), then print playlist.head->data.

Practice

(1/5)
1. What is the main advantage of a doubly linked list over a singly linked list?
easy
A. It can only be traversed forward.
B. It uses less memory than a singly linked list.
C. It requires only one pointer per node.
D. It allows traversal in both forward and backward directions.

Solution

  1. Step 1: Understand node pointers in doubly linked list

    Each node has two pointers: one to the next node and one to the previous node.
  2. Step 2: Compare traversal capabilities

    This allows moving forward and backward through the list, unlike singly linked lists which only allow forward traversal.
  3. Final Answer:

    It allows traversal in both forward and backward directions. -> Option D
  4. Quick Check:

    Doubly linked list = two-way traversal [OK]
Hint: Remember: two pointers mean two directions [OK]
Common Mistakes:
  • Thinking it uses less memory than singly linked list
  • Assuming it has only one pointer per node
  • Believing it can only traverse forward
2. Which of the following is the correct way to declare a node structure for a doubly linked list in C++?
easy
A. struct Node { int data; Node* next; Node* prev; };
B. struct Node { int data; Node next; Node prev; };
C. struct Node { int data; Node* next; int prev; };
D. struct Node { int data; int next; int prev; };

Solution

  1. Step 1: Check pointer usage for next and prev

    In a doubly linked list, next and prev must be pointers to Node, so Node* next and Node* prev are correct.
  2. Step 2: Identify incorrect declarations

    struct Node { int data; Node next; Node prev; }; uses Node next and Node prev (not pointers), C uses int prev, and D uses int for both next and prev, which is incorrect.
  3. Final Answer:

    struct Node { int data; Node* next; Node* prev; }; -> Option A
  4. Quick Check:

    Pointers for next and prev = struct Node { int data; Node* next; Node* prev; }; [OK]
Hint: Pointers to Node must use * symbol [OK]
Common Mistakes:
  • Using Node instead of Node* for next and prev
  • Using int type for pointers
  • Missing pointer symbols
3. Consider the following code snippet for a doubly linked list node insertion at the front:
struct Node {
  int data;
  Node* next;
  Node* prev;
};

Node* head = nullptr;

Node* newNode = new Node{10, nullptr, nullptr};
newNode->next = head;
if (head != nullptr) {
  head->prev = newNode;
}
head = newNode;

// What is the data in head->next after insertion?
medium
A. nullptr
B. 10
C. Undefined
D. Garbage value

Solution

  1. Step 1: Analyze initial head value

    Initially, head is nullptr, meaning the list is empty.
  2. Step 2: After insertion, newNode->next points to old head (nullptr)

    Since head was nullptr, newNode->next is set to nullptr, so head->next is nullptr after insertion.
  3. Final Answer:

    nullptr -> Option A
  4. Quick Check:

    Empty list insertion sets next to nullptr [OK]
Hint: New node next points to old head, which is nullptr here [OK]
Common Mistakes:
  • Assuming head->next has data 10
  • Thinking head->next is undefined or garbage
  • Ignoring initial nullptr head
4. Identify the error in the following code snippet for inserting a node at the end of a doubly linked list:
struct Node {
  int data;
  Node* next;
  Node* prev;
};

void insertEnd(Node*& head, int val) {
  Node* newNode = new Node{val, nullptr, nullptr};
  if (head == nullptr) {
    head = newNode;
    return;
  }
  Node* temp = head;
  while (temp->next != nullptr) {
    temp = temp->next;
  }
  temp->next = newNode;
  newNode->prev = nullptr;
}
medium
A. temp should be initialized to nullptr.
B. head should be passed by value, not reference.
C. newNode->prev should point to temp, not nullptr.
D. newNode->next should point to head.

Solution

  1. Step 1: Check newNode's prev pointer assignment

    After finding the last node (temp), newNode is added after temp, so newNode->prev must point to temp.
  2. Step 2: Identify incorrect assignment

    Code sets newNode->prev = nullptr, which breaks backward link; it should be newNode->prev = temp.
  3. Final Answer:

    newNode->prev should point to temp, not nullptr. -> Option C
  4. Quick Check:

    Prev pointer links new node to last node [OK]
Hint: Prev of new node = last node before insertion [OK]
Common Mistakes:
  • Setting newNode->prev to nullptr instead of last node
  • Passing head by value losing list updates
  • Incorrect initialization of temp pointer
5. You want to design a function to delete a node from a doubly linked list given a pointer to that node (not the head). Which pointer updates are necessary to maintain list integrity?
hard
A. No pointer updates needed; just delete the node.
B. Set node's prev->next to node's next and node's next->prev to node's prev.
C. Set node's prev to nullptr and node's next to nullptr only.
D. Set node's next->next to node's prev and node's prev->prev to node's next.

Solution

  1. Step 1: Understand node removal in doubly linked list

    To remove a node, the previous node's next pointer must skip the node and point to node's next.
  2. Step 2: Update next node's prev pointer

    Similarly, the next node's prev pointer must skip the node and point to node's prev.
  3. Final Answer:

    Set node's prev->next to node's next and node's next->prev to node's prev. -> Option B
  4. Quick Check:

    Prev and next pointers bypass deleted node [OK]
Hint: Link prev and next nodes directly to remove node [OK]
Common Mistakes:
  • Not updating both prev and next pointers
  • Setting wrong pointers to nullptr
  • Deleting node without fixing links
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