Detect Cycle in Linked List Floyd's Algorithm in DSA C++ - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is the main idea behind Floyd's Cycle Detection Algorithm in a linked list?

It uses two pointers moving at different speeds (slow and fast). If there is a cycle, the fast pointer will eventually meet the slow pointer inside the cycle.

beginner

In Floyd's Algorithm, what speeds do the two pointers move at?

The slow pointer moves one step at a time, and the fast pointer moves two steps at a time.

intermediate

Why does the fast pointer eventually meet the slow pointer if a cycle exists?

Because the fast pointer moves faster, it will loop around and catch up to the slow pointer inside the cycle, like runners on a circular track.

beginner

What does it mean if the fast pointer reaches the end of the linked list (null)?

It means there is no cycle in the linked list because the fast pointer can move freely to the end without looping back.

intermediate

How can you find the starting node of the cycle after detecting a cycle using Floyd's Algorithm?

After the slow and fast pointers meet, reset one pointer to the head. Then move both pointers one step at a time. The node where they meet again is the start of the cycle.

In Floyd's Cycle Detection Algorithm, what happens if the linked list has no cycle?

A The slow and fast pointers meet at the head.

B The fast pointer reaches the end (null) of the list.

C The slow pointer moves faster than the fast pointer.

D The slow pointer jumps two steps at a time.

If there is no cycle, the fast pointer will reach the end (null) of the list, indicating no cycle.

What is the speed of the fast pointer in Floyd's Algorithm?

A Variable speed

B One step at a time

C Three steps at a time

D Two steps at a time

The fast pointer moves two steps at a time to catch the slow pointer if a cycle exists.

When the slow and fast pointers meet inside the linked list, what does it indicate?

A The list is empty

B The pointers are at the head

C There is a cycle in the list

D The list has only one node

Meeting of slow and fast pointers means a cycle exists in the linked list.

How do you find the start of the cycle after detecting it with Floyd's Algorithm?

A Move one pointer to head and move both one step until they meet

B Move both pointers two steps until they meet

C Reset both pointers to null

D Move slow pointer two steps and fast pointer one step

Reset one pointer to head and move both one step at a time; their meeting point is the cycle start.

Why is Floyd's Algorithm efficient for cycle detection?

A It uses two pointers without extra memory

B It uses extra memory to store visited nodes

C It sorts the linked list first

D It deletes nodes while traversing

Floyd's Algorithm uses two pointers and no extra memory, making it efficient.

Explain how Floyd's Cycle Detection Algorithm works step-by-step.

Think of two runners on a track moving at different speeds.

Describe how to find the starting node of a cycle after detecting a cycle in a linked list.

Imagine two people walking at the same speed from different points until they meet.

Practice

1. What is the main purpose of Floyd's Cycle Detection Algorithm in a linked list?

easy

A. To find the middle element of the linked list

B. To sort the linked list in ascending order

C. To reverse the linked list

D. To detect if there is a cycle (loop) in the linked list

Solution

1. Step 1: Understand Floyd's Algorithm goal

   Floyd's Cycle Detection Algorithm is designed to check if a linked list contains a cycle, meaning a node points back to a previous node.

2. Step 2: Compare with other linked list operations

   Sorting, reversing, or finding the middle element are different operations and not the purpose of this algorithm.

3. Final Answer:

   To detect if there is a cycle (loop) in the linked list -> Option D

4. Quick Check:

   Cycle detection = Detect cycle [OK]

Hint: Floyd's algorithm finds loops, not sorting or reversing [OK]

Common Mistakes:

• Confusing cycle detection with sorting
• Thinking it finds the middle node
• Assuming it reverses the list

2. Which of the following correctly initializes the two pointers used in Floyd's Cycle Detection Algorithm in C++?

easy

A. ListNode* slow = head; ListNode* fast = head;

B. ListNode* slow = head->next; ListNode* fast = head;

C. ListNode* slow = nullptr; ListNode* fast = head;

D. ListNode* slow = head; ListNode* fast = head->next;

Solution

1. Step 1: Understand pointer initialization in Floyd's algorithm

   Both slow and fast pointers start at the head node to begin traversal.

2. Step 2: Check each option

   ListNode* slow = head; ListNode* fast = head; initializes both pointers at head, which is the standard approach. Other options start pointers differently, which can cause errors or miss cycles.

3. Final Answer:

   ListNode* slow = head; ListNode* fast = head; -> Option A

4. Quick Check:

   Both pointers start at head [OK]

Hint: Start both pointers at head for Floyd's algorithm [OK]

Common Mistakes:

• Starting fast pointer at head->next causes skipping
• Initializing slow as nullptr causes null errors
• Swapping slow and fast initialization

3. What will be the output of the following code snippet detecting a cycle in a linked list?

#include <iostream>

struct Node {
  int data;
  Node* next;
};

bool hasCycle(Node* head) {
  Node* slow = head;
  Node* fast = head;
  while (fast && fast->next) {
    slow = slow->next;
    fast = fast->next->next;
    if (slow == fast) return true;
  }
  return false;
}

int main() {
  Node a{1, nullptr};
  Node b{2, nullptr};
  Node c{3, nullptr};
  a.next = &b;
  b.next = &c;
  c.next = &b; // cycle here
  bool result = hasCycle(&a);
  std::cout << (result ? "Cycle detected" : "No cycle") << std::endl;
  return 0;
}

medium

A. No cycle

B. Cycle detected

C. Compilation error

D. Runtime error

Solution

1. Step 1: Analyze linked list structure

   Nodes a, b, c are linked as a->b->c, and c points back to b, creating a cycle.

2. Step 2: Trace Floyd's algorithm behavior

   Slow and fast pointers will eventually meet inside the cycle, so hasCycle returns true.

3. Final Answer:

   Cycle detected -> Option B

4. Quick Check:

   Cycle exists, so output is "Cycle detected" [OK]

Hint: If a node points back, Floyd detects cycle [OK]

Common Mistakes:

• Ignoring the cycle created by c.next = &b
• Assuming no cycle because list looks linear
• Confusing output with compilation or runtime errors

4. Identify the bug in this Floyd's Cycle Detection code snippet:

bool detectCycle(Node* head) {
  Node* slow = head;
  Node* fast = head;
  while (fast->next && fast->next->next) {
    slow = slow->next;
    fast = fast->next->next;
    if (slow == fast) return true;
  }
  return false;
}

medium

A. The return type should be void, not bool

B. Pointers slow and fast should start at different nodes

C. The while condition should check if fast is not nullptr before fast->next

D. The comparison if (slow == fast) should be outside the loop

Solution

1. Step 1: Check while loop condition safety

   The code checks fast->next and fast->next->next but does not check if fast itself is nullptr, risking null pointer access.

2. Step 2: Correct condition order

   Proper check is to ensure fast is not nullptr before accessing fast->next to avoid runtime errors.

3. Final Answer:

   The while condition should check if fast is not nullptr before fast->next -> Option C

4. Quick Check:

   Check fast != nullptr before fast->next [OK]

Hint: Always check pointer not null before accessing members [OK]

Common Mistakes:

• Skipping null check on fast pointer
• Starting pointers at different nodes unnecessarily
• Moving comparison outside loop causing infinite loop

5. Given a linked list where a cycle exists, how can Floyd's algorithm be extended to find the exact node where the cycle begins?

hard

A. After detecting the cycle, reset one pointer to head and move both pointers one step at a time until they meet at the cycle start.

B. Count the number of nodes in the list and divide by two to find the cycle start.

C. Use a hash set to store visited nodes and find the first repeated node.

D. Reverse the linked list and check where the reversal breaks to find the cycle start.

Solution

1. Step 1: Detect cycle using Floyd's algorithm

   First, detect the cycle by moving slow and fast pointers until they meet inside the cycle.

2. Step 2: Find cycle start node

   Reset one pointer to head, then move both pointers one step at a time; their meeting point is the cycle start node.

3. Final Answer:

   After detecting the cycle, reset one pointer to head and move both pointers one step at a time until they meet at the cycle start. -> Option A

4. Quick Check:

   Reset pointer + move stepwise = cycle start [OK]

Hint: Reset pointer to head after detection, move both stepwise [OK]

Common Mistakes:

• Trying to find cycle start by counting nodes
• Using extra memory like hash sets (not Floyd's method)
• Reversing list which breaks structure