Challenge - 5 Problems
Deque Mastery
Get all challenges correct to earn this badge!
Test your skills under time pressure!
❓ Predict Output
intermediateOutput of Dequeue Push and Pop Operations
What is the printed state of the deque after executing the following C++ code?
DSA C++
#include <iostream> #include <deque> int main() { std::deque<int> dq; dq.push_back(10); dq.push_front(20); dq.push_back(30); dq.pop_front(); for (int val : dq) { std::cout << val << " -> "; } std::cout << "null" << std::endl; return 0; }
Attempts:
2 left
💡 Hint
Remember that push_front adds to the front and pop_front removes from the front.
✗ Incorrect
Initially, 10 is added at the back, then 20 at the front, making deque: 20, 10. Then 30 is added at the back: 20, 10, 30. pop_front removes 20, leaving 10, 30.
❓ Predict Output
intermediateResult of Dequeue Pop Back and Push Front
What will be the output after running this C++ code snippet?
DSA C++
#include <iostream> #include <deque> int main() { std::deque<int> dq = {5, 15, 25}; dq.pop_back(); dq.push_front(35); for (auto x : dq) { std::cout << x << " -> "; } std::cout << "null" << std::endl; return 0; }
Attempts:
2 left
💡 Hint
pop_back removes the last element, push_front adds at the front.
✗ Incorrect
Starting deque: 5, 15, 25. pop_back removes 25, leaving 5, 15. push_front adds 35 at front: 35, 5, 15.
🔧 Debug
advancedIdentify the Error in Deque Pop Operation
What error will this C++ code produce when executed?
DSA C++
#include <iostream> #include <deque> int main() { std::deque<int> dq; dq.pop_front(); std::cout << "Deque size: " << dq.size() << std::endl; return 0; }
Attempts:
2 left
💡 Hint
Consider what happens when you pop from an empty deque.
✗ Incorrect
Calling pop_front on an empty deque causes undefined behavior and typically a runtime error or crash.
❓ Predict Output
advancedFinal Deque State After Mixed Operations
What is the final printed state of the deque after this code runs?
DSA C++
#include <iostream> #include <deque> int main() { std::deque<int> dq = {1, 2, 3, 4}; dq.pop_back(); dq.pop_front(); dq.push_back(5); dq.push_front(6); for (int x : dq) { std::cout << x << " -> "; } std::cout << "null" << std::endl; return 0; }
Attempts:
2 left
💡 Hint
Track each operation step-by-step on the deque.
✗ Incorrect
Start: 1,2,3,4
pop_back removes 4: 1,2,3
pop_front removes 1: 2,3
push_back 5: 2,3,5
push_front 6: 6,2,3,5
🧠 Conceptual
expertDeque Operation Complexity
Which statement correctly describes the time complexity of push_front and pop_back operations on a std::deque in C++?
Attempts:
2 left
💡 Hint
Consider how std::deque is implemented internally with blocks.
✗ Incorrect
std::deque provides O(1) amortized time for push_front and pop_back because it uses a segmented array allowing efficient insertions/removals at both ends.
