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DSA C++programming~5 mins

Delete from End of Doubly Linked List in DSA C++ - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What is a doubly linked list?
A doubly linked list is a chain of nodes where each node has three parts: data, a pointer to the next node, and a pointer to the previous node. This allows traversal in both directions.
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beginner
What happens when you delete the last node from a doubly linked list?
The last node is removed, the second last node's next pointer is set to null, and if the list becomes empty, the head pointer is set to null.
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intermediate
Why do we need to update the previous node's next pointer when deleting from the end of a doubly linked list?
Because the second last node's next pointer must be set to null to disconnect the last node and prevent a dangling reference from the second last node to the deleted node. The second last node's previous pointer remains unchanged.
Click to reveal answer
beginner
Show the steps to delete the last node in a doubly linked list.
1. Check if the list is empty; if yes, do nothing.
2. If only one node, delete it and set head to null.
3. Otherwise, traverse to the last node.
4. Set the second last node's next pointer to null.
5. Delete the last node.
Click to reveal answer
intermediate
What is the time complexity of deleting the last node in a doubly linked list if no tail pointer is used?
O(n), because you need to traverse from the head to the last node to delete it.
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What pointer must be updated when deleting the last node in a doubly linked list?
AThe head pointer
BThe previous node's next pointer
CThe last node's next pointer
DThe previous node's previous pointer
If a doubly linked list has only one node, what happens after deleting that node?
AHead pointer is set to null
BTail pointer points to the node
CNext pointer points to itself
DList becomes circular
What is the best way to optimize deletion from the end of a doubly linked list?
AMaintain a tail pointer
BUse a singly linked list
CTraverse from head every time
DUse an array instead
Which of these is NOT true about deleting the last node in a doubly linked list?
AYou must update the previous node's next pointer
BIf the list is empty, no deletion occurs
CYou must update the last node's previous pointer to null
DIf only one node exists, head becomes null after deletion
What is the time complexity of deleting the last node if a tail pointer is maintained?
AO(n^2)
BO(n)
CO(log n)
DO(1)
Explain how to delete the last node from a doubly linked list step-by-step.
Think about what pointers need changing and what happens when the list has one or no nodes.
You got /5 concepts.
    Describe the difference in deleting the last node in a doubly linked list with and without a tail pointer.
    Focus on how the tail pointer helps avoid traversal.
    You got /4 concepts.

      Practice

      (1/5)
      1. What happens to the tail pointer when you delete the last node from a doubly linked list?
      easy
      A. It moves to the previous node of the deleted node
      B. It becomes null immediately
      C. It points to the head node
      D. It remains unchanged

      Solution

      1. Step 1: Understand the tail pointer role

        The tail pointer always points to the last node in the list.
      2. Step 2: Effect of deleting the last node

        When the last node is deleted, the tail must move to the previous node to remain the last node.
      3. Final Answer:

        It moves to the previous node of the deleted node -> Option A
      4. Quick Check:

        Tail updates to previous node after deletion [OK]
      Hint: Tail always points to last node, update to previous on delete [OK]
      Common Mistakes:
      • Setting tail to null without checking if list is empty
      • Not updating tail pointer after deletion
      • Pointing tail to head incorrectly
      2. Which of the following is the correct syntax to delete the last node in a doubly linked list in C++?
      easy
      A. tail->prev = tail; delete tail; tail = nullptr;
      B. delete tail; tail = tail->prev; tail->next = nullptr;
      C. tail = tail->prev; delete tail->next; tail->next = nullptr;
      D. tail->next = nullptr; delete tail; tail = tail->prev;

      Solution

      1. Step 1: Identify correct order of operations

        First, move tail pointer to previous node, then delete the old last node, and finally set new tail's next to nullptr.
      2. Step 2: Match with options

        tail = tail->prev; delete tail->next; tail->next = nullptr; correctly moves tail, deletes old node, and updates next pointer.
      3. Final Answer:

        tail = tail->prev; delete tail->next; tail->next = nullptr; -> Option C
      4. Quick Check:

        Move tail first, then delete old node [OK]
      Hint: Move tail before deleting old node to avoid dangling pointer [OK]
      Common Mistakes:
      • Deleting tail before moving pointer causes invalid access
      • Not setting tail->next to nullptr after deletion
      • Incorrect pointer assignments causing memory leaks
      3. What will be the output of the following code snippet after deleting the last node?
      struct Node {
        int data;
        Node* prev;
        Node* next;
      };
      
      Node* head = new Node{1, nullptr, nullptr};
      Node* second = new Node{2, head, nullptr};
      head->next = second;
      Node* tail = second;
      
      // Delete last node
      Node* temp = tail;
      tail = tail->prev;
      tail->next = nullptr;
      delete temp;
      
      // Print list
      Node* curr = head;
      while(curr) {
        std::cout << curr->data << " ";
        curr = curr->next;
      }
      medium
      A. 1 2
      B. No output (empty list)
      C. 2
      D. 1

      Solution

      1. Step 1: Understand list before deletion

        List has two nodes: 1 (head) -> 2 (tail).
      2. Step 2: Delete last node and update pointers

        Last node (2) is deleted, tail moves to node 1, and tail->next is set to nullptr.
      3. Step 3: Print remaining list

        Only node 1 remains, so output is "1".
      4. Final Answer:

        1 -> Option D
      5. Quick Check:

        Last node deleted, only head remains [OK]
      Hint: After deleting tail, print from head to see remaining nodes [OK]
      Common Mistakes:
      • Printing deleted node due to not updating tail->next
      • Assuming list is empty after deletion
      • Confusing head and tail pointers
      4. Identify the error in the following code that deletes the last node of a doubly linked list:
      void deleteEnd(Node*& tail) {
        delete tail;
        tail = tail->prev;
        tail->next = nullptr;
      }
      medium
      A. Not updating head pointer causes memory leak
      B. Accessing tail->prev after deleting tail causes undefined behavior
      C. tail->next should be set to tail->prev
      D. No error, code is correct

      Solution

      1. Step 1: Analyze order of operations

        The code deletes tail first, then tries to access tail->prev which is invalid after deletion.
      2. Step 2: Correct approach

        First move tail pointer to previous node, then delete the old tail node, and update pointers.
      3. Final Answer:

        Accessing tail->prev after deleting tail causes undefined behavior -> Option B
      4. Quick Check:

        Delete after pointer update to avoid invalid access [OK]
      Hint: Move pointer before delete to avoid invalid memory access [OK]
      Common Mistakes:
      • Deleting node before updating pointers
      • Not checking if tail is nullptr before access
      • Confusing order of pointer updates and deletion
      5. Given a doubly linked list with nodes containing values [10, 20, 30, 40], write the steps to delete the last node and update the list correctly. What will be the final list after deletion?
      hard
      A. [10, 20, 30]
      B. [10, 20, 30, 40]
      C. [20, 30, 40]
      D. [10, 20, 40]

      Solution

      1. Step 1: Identify the last node and tail pointer

        The last node has value 40, tail points to it.
      2. Step 2: Move tail pointer to previous node and delete last node

        Tail moves to node with value 30, delete node 40, set tail->next to nullptr.
      3. Step 3: Final list after deletion

        List nodes are now 10 -> 20 -> 30 with tail at 30.
      4. Final Answer:

        [10, 20, 30] -> Option A
      5. Quick Check:

        Last node removed, tail updated, list shortened [OK]
      Hint: Delete last node, move tail back, set tail->next null [OK]
      Common Mistakes:
      • Not updating tail->next to nullptr
      • Deleting wrong node or skipping pointer updates
      • Assuming list shrinks from head instead of tail
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