Complete the code to move the pointer to the next node in the circular linked list.
current = current[1];In a circular linked list, to move to the next node, we use the pointer ->next.
Complete the condition to check if the list has only one node.
if (head != nullptr && head[1] == head) {
In a circular linked list, if the head's next pointer points to itself, it means there is only one node.
Fix the error in the loop condition to find the node before the one to delete.
while (current->next != head && current->next->data != key) { current = current[1]; }
To traverse forward in the circular linked list, use current = current->next;.
Fill both blanks to correctly update pointers when deleting a node in the circular linked list.
current->next = current->next[1]; current->next[2] = current;
To delete a node, link current's next to the node after the deleted node, and update the previous pointer of that node to current.
Fill all three blanks to correctly handle deleting the head node in a circular linked list.
if (head->data == key) { Node* temp = head; while (temp->next != head) { temp = temp[1]; } temp->next = head[2]; head[2]->prev = temp; head = head[3]; }
To delete the head, find the last node by moving forward with '->next', then link it to the new head which is head's next node.
