Count Set Bits Brian Kernighan Algorithm in DSA C++ - Interactive Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to initialize the count variable to zero.

DSA C++

int countSetBits(int n) {
    int count = [1];
    while (n) {
        n = n & (n - 1);
        count++;
    }
    return count;
}

Drag options to blanks, or click blank then click option'

A-1

B1

Cn

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Initializing count to 1 causes off-by-one errors.

Using n as initial count leads to wrong counts.

The count variable must start at zero to count the number of set bits correctly.

2fill in blank

medium

Complete the code to update n by removing the rightmost set bit.

DSA C++

while (n) {
    n = n [1] (n - 1);
    count++;
}

Drag options to blanks, or click blank then click option'

A&

B|

C^

D<<

Attempts:

3 left

💡 Hint

Common Mistakes

Using | instead of & causes incorrect bit manipulation.

Using ^ does not remove the rightmost set bit.

Using bitwise AND with (n - 1) removes the rightmost set bit from n.

3fill in blank

hard

Fix the error in the loop condition to correctly count set bits.

DSA C++

while ([1]) {
    n = n & (n - 1);
    count++;
}

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Acount > 0

Bcount

Cn

Dn > 0

Attempts:

3 left

💡 Hint

Common Mistakes

Using count in the loop condition causes infinite or no loops.

Using n > 0 or n is better than other variables.

The loop should continue while n is not zero to count all set bits.

4fill in blank

hard

Fill both blanks to create a function that counts set bits using Brian Kernighan's algorithm.

DSA C++

int [1](int n) {
    int count = 0;
    while (n [2] 0) {
        n = n & (n - 1);
        count++;
    }
    return count;
}

Drag options to blanks, or click blank then click option'

AcountSetBits

BcountBits

C>

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>' instead of '!=' in loop condition may fail for negative numbers.

Using wrong function names causes confusion.

The function name is countSetBits and the loop continues while n is not zero (n != 0).

5fill in blank

hard

Fill all three blanks to create a main function that reads an integer, counts its set bits, and prints the result.

DSA C++

#include <iostream>

int countSetBits(int n) {
    int count = 0;
    while (n != 0) {
        n = n & (n - 1);
        count++;
    }
    return count;
}

int main() {
    int [1];
    std::cin >> [2];
    int result = [3](num);
    std::cout << result << std::endl;
    return 0;
}

Drag options to blanks, or click blank then click option'

Anum

BcountSetBits

Dinput

Attempts:

3 left

💡 Hint

Common Mistakes

Using different variable names causes compilation errors.

Calling a wrong function name causes errors.

Variable 'num' is declared and used for input and passed to countSetBits function.

Practice

1. What does the Brian Kernighan algorithm do when counting set bits in an integer?

easy

A. It repeatedly clears the least significant set bit until the number becomes zero.

B. It counts the total number of digits in the integer.

C. It shifts the bits to the right one by one and counts all bits.

D. It converts the number to a string and counts '1' characters.

Solution

1. Step 1: Understand the algorithm's main operation

   The Brian Kernighan algorithm works by clearing the least significant set bit in each iteration.

2. Step 2: Effect of clearing bits

   Each clearing reduces the number of set bits by one until the number becomes zero.

3. Final Answer:

   It repeatedly clears the least significant set bit until the number becomes zero. -> Option A

4. Quick Check:

   Clearing bits one by one counts set bits [OK]

Hint: Clear least significant set bit repeatedly to count bits [OK]

Common Mistakes:

• Counting all bits instead of only set bits
• Using string conversion unnecessarily
• Shifting bits without checking if set

2. Which of the following is the correct syntax for the main loop in Brian Kernighan's algorithm in C++?

easy

A. while (n > 0) { count += n % 2; n /= 2; }

B. for (int i = 0; i < n; i++) { count += n & 1; n >>= 1; }

C. while (n != 0) { n = n & (n - 1); count++; }

D. for (int i = 0; i < 32; i++) { count += (n >> i) & 1; }

Solution

1. Step 1: Identify Brian Kernighan's loop

   The algorithm uses while (n != 0) and clears the least significant set bit by n = n & (n - 1).

2. Step 2: Confirm increment of count

   Each iteration increments count by one for each cleared set bit.

3. Final Answer:

   while (n != 0) { n = n & (n - 1); count++; } -> Option C

4. Quick Check:

   Loop clears bits and counts [OK]

Hint: Use while with n = n & (n-1) to clear bits [OK]

Common Mistakes:

• Using for loop instead of while
• Counting bits by shifting instead of clearing
• Using modulo instead of bitwise operations

3. What is the output of the following C++ code snippet using Brian Kernighan's algorithm?

int countSetBits(int n) {
  int count = 0;
  while (n) {
    n = n & (n - 1);
    count++;
  }
  return count;
}

int main() {
  int x = 13;
  std::cout << countSetBits(x);
  return 0;
}

medium

A. 5

B. 3

C. 2

D. 4

Solution

1. Step 1: Convert 13 to binary

   13 in binary is 1101, which has three set bits (1s).

2. Step 2: Apply Brian Kernighan's algorithm

   Each iteration clears one set bit, so count increments 3 times before n becomes 0.

3. Final Answer:

   3 -> Option B

4. Quick Check:

   Number of 1s in 1101 = 3 [OK]

Hint: Count 1s in binary of number for quick answer [OK]

Common Mistakes:

• Counting total bits instead of set bits
• Miscounting binary 1s
• Confusing bitwise AND with OR

4. Identify the error in this Brian Kernighan algorithm implementation:

int countSetBits(int n) {
  int count = 0;
  while (n > 0) {
    n = n & (n + 1);
    count++;
  }
  return count;
}

medium

A. Missing return statement.

B. Not initializing count to zero.

C. Using while (n > 0) instead of while (n != 0).

D. Using n + 1 instead of n - 1 in bit clearing step.

Solution

1. Step 1: Check bit clearing operation

   The correct operation to clear the least significant set bit is n = n & (n - 1), not n + 1.

2. Step 2: Effect of wrong operation

   Using n + 1 does not clear bits properly and causes incorrect count or infinite loop.

3. Final Answer:

   Using n + 1 instead of n - 1 in bit clearing step. -> Option D

4. Quick Check:

   Correct bit clearing uses n & (n - 1) [OK]

Hint: Use n & (n - 1) to clear bits, not n + 1 [OK]

Common Mistakes:

• Replacing n - 1 with n + 1
• Confusing loop condition syntax
• Forgetting to increment count

5. Given an array of integers, how can you use Brian Kernighan's algorithm to find the total number of set bits in all elements? Choose the best approach.

hard

A. Iterate over each element, apply Brian Kernighan's algorithm to count set bits, and sum all counts.

B. Convert all integers to strings and count '1's in each string, then sum.

C. Use a single Brian Kernighan's algorithm call on the sum of all integers.

D. Count set bits only in the first element and multiply by array size.

Solution

1. Step 1: Understand counting set bits per element

   Brian Kernighan's algorithm counts set bits in one integer at a time.

2. Step 2: Apply algorithm to each array element

   Iterate through the array, count set bits for each element, and sum these counts for total.

3. Final Answer:

   Iterate over each element, apply Brian Kernighan's algorithm to count set bits, and sum all counts. -> Option A

4. Quick Check:

   Sum of individual counts gives total set bits [OK]

Hint: Count bits per element, then sum for total [OK]

Common Mistakes:

• Counting bits of sum instead of each element
• Using string conversion unnecessarily
• Assuming uniform bit count per element