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Circular Queue Implementation Using Array in DSA C++ - Time & Space Complexity

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Time Complexity: Circular Queue Implementation Using Array
O(1)
Understanding Time Complexity

We want to understand how fast operations like adding or removing items work in a circular queue using an array.

How does the time to do these operations change as the queue grows?

Scenario Under Consideration

Analyze the time complexity of the following circular queue operations.


class CircularQueue {
  int front, rear, size;
  int* arr;
public:
  CircularQueue(int s) : front(-1), rear(-1), size(s) { arr = new int[s]; }
  bool enqueue(int val) {
    if ((rear + 1) % size == front) return false; // full
    if (front == -1) front = 0;
    rear = (rear + 1) % size;
    arr[rear] = val;
    return true;
  }
  bool dequeue() {
    if (front == -1) return false; // empty
    if (front == rear) front = rear = -1;
    else front = (front + 1) % size;
    return true;
  }
};
    

This code adds (enqueue) and removes (dequeue) items in a circular queue using an array.

Identify Repeating Operations

Look for loops or repeated steps inside the operations.

  • Primary operation: Simple index calculations and assignments during enqueue and dequeue.
  • How many times: Each operation runs once per call, no loops inside.
How Execution Grows With Input

Each enqueue or dequeue does a fixed number of steps regardless of queue size.

Input Size (n)Approx. Operations
105-6 steps per operation
1005-6 steps per operation
10005-6 steps per operation

Pattern observation: The number of steps stays the same no matter how big the queue is.

Final Time Complexity

Time Complexity: O(1)

This means adding or removing an item takes the same short time no matter how many items are in the queue.

Common Mistake

[X] Wrong: "Enqueue or dequeue takes longer as the queue gets bigger because the array is bigger."

[OK] Correct: The circular queue uses simple math to jump directly to the right spot, so it does not scan or move many items.

Interview Connect

Knowing that circular queue operations run in constant time shows you understand efficient data handling, a key skill in many coding challenges.

Self-Check

"What if we changed the array to a linked list? How would the time complexity of enqueue and dequeue change?"

Practice

(1/5)
1. What is the main advantage of using a circular queue over a simple linear queue when implemented using an array?
easy
A. It eliminates the need for front and rear pointers
B. It allows storing different data types in the same queue
C. It automatically sorts the elements in the queue
D. It efficiently uses the array space by reusing freed slots

Solution

  1. Step 1: Understand linear queue limitation

    In a linear queue using an array, once rear reaches the end, no more elements can be added even if there are empty slots at the front.
  2. Step 2: Circular queue advantage

    Circular queue connects the end of the array back to the front, allowing reuse of empty slots freed by dequeuing.
  3. Final Answer:

    It efficiently uses the array space by reusing freed slots -> Option D
  4. Quick Check:

    Space reuse = Advantage [OK]
Hint: Circular queue reuses space freed by dequeued elements [OK]
Common Mistakes:
  • Thinking circular queue sorts elements
  • Believing circular queue removes need for pointers
  • Assuming it supports multiple data types inherently
2. Which of the following is the correct condition to check if a circular queue is full when using an array of size n with front and rear pointers?
easy
A. front == (rear + 1) % n
B. rear == n - 1
C. front == rear
D. rear == (front + 1) % n

Solution

  1. Step 1: Understand full condition in circular queue

    In circular queue, queue is full when next position of rear is front, i.e., (rear + 1) modulo n equals front.
  2. Step 2: Match condition with options

    front == (rear + 1) % n matches this condition: front == (rear + 1) % n.
  3. Final Answer:

    front == (rear + 1) % n -> Option A
  4. Quick Check:

    Full condition = front == (rear + 1) % n [OK]
Hint: Full when front is next to rear in circular manner [OK]
Common Mistakes:
  • Using rear == n - 1 which is for linear queue
  • Confusing front == rear as full (actually empty)
  • Swapping front and rear in condition
3. Consider a circular queue of size 5 (indices 0 to 4). Initially, front = -1 and rear = -1. After the following operations:
enqueue(10); enqueue(20); enqueue(30); dequeue(); enqueue(40); enqueue(50); dequeue(); enqueue(60);
What will be the values of front and rear?
medium
A. front = 2, rear = 1
B. front = 2, rear = 0
C. front = 3, rear = 0
D. front = 1, rear = 4

Solution

  1. Step 1: Trace each operation and update pointers

    Start: front = -1, rear = -1
    enqueue(10): front=0, rear=0
    enqueue(20): rear=1
    enqueue(30): rear=2
    dequeue(): front=1
    enqueue(40): rear=3
    enqueue(50): rear=4
    dequeue(): front=2
    enqueue(60): rear=(4+1)%5=0
  2. Step 2: Final pointer values

    front = 2, rear = 0 which corresponds to front = 2, rear = 0.
  3. Final Answer:

    front = 2, rear = 0 -> Option B
  4. Quick Check:

    Trace pointers carefully [OK]
Hint: Track front and rear after each enqueue/dequeue [OK]
Common Mistakes:
  • Not updating rear circularly after last index
  • Confusing front and rear updates on dequeue
  • Ignoring initial front = -1 condition
4. The following code snippet is part of a circular queue implementation. Identify the bug:
void enqueue(int value) {
  if ((rear + 1) % size == front) {
    cout << "Queue is full" << endl;
    return;
  }
  if (front == -1) front = 0;
  rear = (rear + 1) % size;
  arr[rear] = value;
}
medium
A. No bug, code is correct
B. The front pointer should be updated after rear
C. The initial check for empty queue should be before full check
D. The condition to check full queue is incorrect

Solution

  1. Step 1: Analyze full queue condition

    The condition (rear + 1) % size == front correctly checks if queue is full in circular queue.
  2. Step 2: Check front pointer update and enqueue steps

    If queue is empty (front == -1), front is set to 0 before inserting.
    rear is updated circularly and value inserted at arr[rear].
  3. Final Answer:

    No bug, code is correct -> Option A
  4. Quick Check:

    Full check and pointers update are correct [OK]
Hint: Full check uses modulo; front updated only if empty [OK]
Common Mistakes:
  • Misplacing front update after rear
  • Incorrect full condition without modulo
  • Checking empty after full condition
5. You have a circular queue of size 6. After performing the following operations:
enqueue(5); enqueue(10); enqueue(15); dequeue(); dequeue(); enqueue(20); enqueue(25); enqueue(30); enqueue(35);
What will be the sequence of elements in the queue from front to rear?
hard
A. 20 -> 25 -> 30 -> 35
B. 10 -> 15 -> 20 -> 25 -> 30 -> 35
C. 15 -> 20 -> 25 -> 30 -> 35
D. 5 -> 10 -> 15 -> 20 -> 25 -> 30

Solution

  1. Step 1: Trace each operation and queue content

    Start empty.
    enqueue(5): queue = [5]
    enqueue(10): queue = [5,10]
    enqueue(15): queue = [5,10,15]
    dequeue(): removes 5, queue = [10,15]
    dequeue(): removes 10, queue = [15]
    enqueue(20): queue = [15,20]
    enqueue(25): queue = [15,20,25]
    enqueue(30): queue = [15,20,25,30]
    enqueue(35): queue = [15,20,25,30,35]
  2. Step 2: Check queue size and elements

    Queue size is 6, current elements are 5.
    From front to rear: 15 -> 20 -> 25 -> 30 -> 35
  3. Final Answer:

    15 -> 20 -> 25 -> 30 -> 35 -> Option C
  4. Quick Check:

    After dequeues, front moves; final elements start from 15 [OK]
Hint: Remove dequeued elements, then list remaining from front to rear [OK]
Common Mistakes:
  • Forgetting to remove dequeued elements
  • Listing elements before dequeue operations
  • Assuming queue is full and ignoring last enqueue
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