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DSA Cprogramming~5 mins

Palindrome Partitioning DP Minimum Cuts in DSA C - Cheat Sheet & Quick Revision

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Recall & Review
beginner
What is the goal of the Palindrome Partitioning problem?
To split a string into the fewest possible parts so that each part is a palindrome.
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intermediate
What does the DP array represent in Palindrome Partitioning Minimum Cuts?
It stores the minimum number of cuts needed to partition the substring from the start up to each index into palindromes.
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intermediate
How do you check if a substring is a palindrome efficiently in DP?
Use a 2D boolean table where table[i][j] is true if substring from i to j is palindrome, built using smaller substrings results.
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intermediate
Why do we add 1 to the minimum cuts when a palindrome is found in the substring?
Because cutting before the palindrome substring creates one more partition, so we add 1 to the cuts needed before that substring.
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beginner
What is the base case for the minimum cuts DP array in Palindrome Partitioning?
If the substring from start to current index is a palindrome, minimum cuts is 0 because no cut is needed.
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What does a minimum cut represent in Palindrome Partitioning?
ANumber of cuts to split string into palindromes
BLength of the longest palindrome
CNumber of palindromes in the string
DTotal characters in the string
Which data structure helps to check palindrome substrings efficiently?
AQueue
B2D boolean table
CStack
DLinked list
If substring s[0..j] is palindrome, what is the minimum cut count at j?
Aj
B1
C0
Dj-1
What is the time complexity of the DP solution for Palindrome Partitioning Minimum Cuts?
AO(log n)
BO(n)
CO(n^3)
DO(n^2)
When updating minimum cuts at index j, what do you add to the cuts at i-1?
A1
B0
Cj
Di
Explain how dynamic programming helps find the minimum cuts for palindrome partitioning.
Think about breaking the problem into smaller parts and reusing results.
You got /4 concepts.
    Describe the steps to check if a substring is palindrome using DP.
    Start from smallest substrings and build up.
    You got /4 concepts.