Which of the following statements correctly describes the key structural difference between a graph and a tree?
Think about connectivity and cycles in both structures.
A tree is a special type of graph that is connected and has no cycles. Graphs can be disconnected and may contain cycles.
Consider a tree with 5 nodes and a graph with 5 nodes and 6 edges. What is the number of edges in the tree?
int tree_nodes = 5; int tree_edges = tree_nodes - 1; printf("%d", tree_edges);
Remember the property of edges in a tree.
A tree with n nodes always has n-1 edges.
What will be the output of the following C code snippet that checks if a graph with edges has a cycle?
int edges[][2] = {{0,1}, {1,2}, {2,0}};
int n = 3;
int hasCycle = 0;
// Simplified check: if edges >= nodes, cycle likely
if (sizeof(edges)/sizeof(edges[0]) >= n) hasCycle = 1;
printf("%d", hasCycle);Think about the minimum edges needed to form a cycle.
If the number of edges is equal or more than the number of nodes, a cycle is possible in a graph.
Why is it impossible for a tree to have cycles?
Consider the relationship between nodes and edges in a tree.
A tree with n nodes must have exactly n-1 edges to be connected without cycles. Adding any edge creates a cycle.
You have a data structure with 7 nodes and 7 edges. It is connected and has no cycles. What is this structure?
Recall the edge count property of trees.
A tree with 7 nodes must have exactly 6 edges. Since this structure has 7 edges, it cannot be a tree. It is a connected graph without cycles, which is contradictory, so it must be a graph with a cycle or error in data.