Generate All Combinations Sum K in DSA C - Time & Space Complexity
We want to understand how the time needed to find all combinations that add up to a target grows as the input size changes.
Specifically, how does the number of operations increase when we try to generate all possible combinations?
Analyze the time complexity of the following code snippet.
void backtrack(int start, int k, int target, int* candidates, int candidatesSize, int* combination, int combSize) {
if (target == 0 && combSize == k) {
// store combination
return;
}
if (target < 0 || combSize > k) return;
for (int i = start; i < candidatesSize; i++) {
combination[combSize] = candidates[i];
backtrack(i + 1, k, target - candidates[i], candidates, candidatesSize, combination, combSize + 1);
}
}
This code tries all combinations of numbers from candidates to find those with length k that sum to target.
Identify the loops, recursion, array traversals that repeat.
- Primary operation: Recursive calls exploring combinations by looping through candidates starting from current index.
- How many times: Potentially explores all subsets of size k, which can be many depending on input size.
As input size n grows, the number of combinations of size k grows quickly.
| Input Size (n) | Approx. Operations |
|---|---|
| 10 | About 252 combinations (if k=5) |
| 20 | About 15,504 combinations (if k=5) |
| 30 | About 142,506 combinations (if k=5) |
Pattern observation: The number of combinations grows very fast, roughly like n choose k, which increases sharply as n increases.
Time Complexity: O(n choose k * k)
This means the time grows roughly with the number of k-sized combinations from n elements, and each combination takes up to k steps to build.
[X] Wrong: "The time complexity is just O(n) because we loop through the array once."
[OK] Correct: The code uses recursion to explore many combinations, not just a single pass, so the time grows much faster than linear.
Understanding how recursive combination generation scales helps you explain your approach clearly and shows you grasp the cost of exploring many possibilities.
"What if we allowed repeated elements in combinations? How would the time complexity change?"
Practice
Generate All Combinations Sum K problem?Solution
Step 1: Understand the problem statement
The problem asks to find all unique sets of numbers that add up exactly to a given sum K.Step 2: Identify the goal
The goal is to generate all possible combinations, not just one or count elements.Final Answer:
Find all unique combinations of numbers that add up to a target sum K -> Option DQuick Check:
Combination sum = find all sets adding to K [OK]
- Confusing combination sum with sorting
- Looking for maximum instead of combinations
- Counting elements instead of sums
arr of size n?Solution
Step 1: Check parameter types for array and function return
In C, arrays are passed asint arr[]and recursive functions for generating combinations usually return void.Step 2: Verify function signature correctness
void generate(int arr[], int n, int target, int start, int currentSum, int combination[], int combSize) correctly usesvoidreturn type andint arr[]for the array parameter.Final Answer:
void generate(int arr[], int n, int target, int start, int currentSum, int combination[], int combSize) -> Option AQuick Check:
Correct C syntax for recursive combination function [OK]
- Using int instead of int[] for array parameter
- Returning int instead of void for recursive function
- Missing array brackets in parameter
[2, 3, 6, 7] and target sum 7 using combination sum logic?Solution
Step 1: Identify valid combinations summing to 7
From the array, 7 alone is valid. Also, 2+2+3 = 7 is valid. 3+4 is invalid as 4 is not in array. 6+1 invalid as 1 not in array.Step 2: Confirm combinations
Valid combinations are [7] and [2, 2, 3].Final Answer:
[[7], [2, 2, 3]] -> Option AQuick Check:
Sum 7 from array = [7], [2,2,3] [OK]
- Including numbers not in the array
- Ignoring repeated elements allowed
- Mixing invalid sums
void generate(int arr[], int n, int target, int start, int currentSum, int combination[], int combSize) {
if (currentSum == target) {
// print combination
return;
}
for (int i = start; i < n; i++) {
if (currentSum + arr[i] <= target) {
combination[combSize] = arr[i];
generate(arr, n, target, i, currentSum + arr[i], combination, combSize + 1);
}
}
}Solution
Step 1: Analyze recursion and combination building
The function adds elements to combination but never removes them after recursion, causing incorrect combinations.Step 2: Identify missing backtracking
Backtracking requires removing last added element after recursive call to explore other paths.Final Answer:
Missing backtracking step to remove last element after recursion -> Option CQuick Check:
Backtracking needs element removal after recursion [OK]
- Not removing last element after recursion
- Wrong base case check
- Loop starting index error
[1, 2, 3] that sum to 4. Which of the following modifications ensures no duplicate combinations appear when numbers can be reused multiple times?Solution
Step 1: Understand reuse and duplicates in combinations
Allowing reuse means next recursion starts from current indexi, not 0, to avoid duplicate sets in different orders.Step 2: Identify correct start index usage
Passingias start index allows reuse and prevents duplicates by not revisiting earlier elements.Final Answer:
In recursive calls, passias start index to allow reuse and avoid duplicates -> Option BQuick Check:
Start index = i to reuse and avoid duplicates [OK]
- Restarting from 0 causing duplicates
- Using visited array unnecessarily
- Not sorting or skipping duplicates properly
Ready to prove it?
Pass the test and this pattern moves unknown
