Bridges in Graph Tarjan's Algorithm in DSA C - Cheat Sheet & Quick Revision

Recall & Review

beginner

What is a bridge in a graph?

A bridge is an edge in a graph that, if removed, increases the number of connected components. It means the edge is critical for keeping the graph connected.

intermediate

What is the main idea behind Tarjan's algorithm for finding bridges?

Tarjan's algorithm uses a depth-first search (DFS) to assign discovery times and low values to each vertex. An edge is a bridge if the low value of the connected vertex is greater than the discovery time of the current vertex.

intermediate

In Tarjan's algorithm, what does the 'low' value represent?

The 'low' value of a vertex is the earliest discovery time reachable from that vertex by following the DFS tree edges and at most one back edge.

intermediate

Why do we compare low[v] > disc[u] to find a bridge in Tarjan's algorithm?

If low[v] > disc[u], it means vertex v cannot reach any ancestor of u without using the edge (u, v). So, removing (u, v) disconnects the graph, making it a bridge.

beginner

What data structures are commonly used in Tarjan's algorithm for bridges?

Arrays or lists to store discovery times (disc), low values (low), a visited set or array, and adjacency lists to represent the graph.

What happens if you remove a bridge edge from a graph?

A The graph becomes a tree

B The graph remains connected

C The graph becomes disconnected

D The graph becomes cyclic

Removing a bridge edge increases the number of connected components, so the graph becomes disconnected.

In Tarjan's algorithm, what does the discovery time represent?

A The order in which vertices are visited in DFS

B The number of edges connected to a vertex

C The shortest distance from the start vertex

D The number of connected components

Discovery time is the time when a vertex is first visited during DFS.

Which condition identifies an edge (u, v) as a bridge in Tarjan's algorithm?

A low[v] > disc[u]

B low[u] > disc[v]

C disc[u] > disc[v]

D low[u] == low[v]

If low[v] > disc[u], edge (u, v) is a bridge.

What is the role of the 'low' array in Tarjan's algorithm?

A Marks visited vertices

B Tracks the earliest visited vertex reachable

C Stores the parent of each vertex

D Counts the number of edges

The 'low' array stores the earliest discovery time reachable from a vertex.

Which graph traversal method does Tarjan's algorithm use?

A Dijkstra's Algorithm

B Breadth-First Search (BFS)

C Prim's Algorithm

D Depth-First Search (DFS)

Tarjan's algorithm uses DFS to explore the graph.

Explain how Tarjan's algorithm finds bridges in a graph using discovery and low values.

Think about how DFS helps track back edges and earliest reachable ancestors.

Describe what a bridge is in a graph and why it is important to find them.

Consider bridges as critical connections that keep parts of the graph linked.

Practice

1. What is the main purpose of Tarjan's algorithm when finding bridges in a graph?

easy

A. To detect cycles in a graph

B. To find edges that, if removed, increase the number of connected components

C. To find the shortest path between two nodes

D. To count the total number of edges in the graph

Solution

1. Step 1: Understand the definition of a bridge

   A bridge is an edge that, when removed, increases the number of connected components in a graph.

2. Step 2: Relate Tarjan's algorithm to bridges

   Tarjan's algorithm efficiently finds such edges by using DFS and low-link values.

3. Final Answer:

   To find edges that, if removed, increase the number of connected components -> Option B

4. Quick Check:

   Bridges = edges increasing components when removed [OK]

Hint: Bridges disconnect graph parts when removed [OK]

Common Mistakes:

• Confusing bridges with shortest paths
• Thinking bridges detect cycles
• Assuming bridges count edges

2. Which of the following is the correct way to declare the array that stores discovery times in C for Tarjan's algorithm?

easy

A. int disc = new int[MAX];

B. int disc[];

C. int disc[MAX];

D. int[] disc = new int[MAX];

Solution

1. Step 1: Recall C array declaration syntax

   In C, arrays are declared with type and size like int arr[size];

2. Step 2: Match with discovery time array

   So, int disc[MAX]; is correct for fixed size MAX.

3. Final Answer:

   int disc[MAX]; -> Option C

4. Quick Check:

   C arrays use type name[size] [OK]

Hint: Use type name[size] for arrays in C [OK]

Common Mistakes:

• Using Java or C++ style array declarations in C
• Not specifying array size
• Using dynamic allocation syntax incorrectly

3. Consider the following code snippet for Tarjan's algorithm to find bridges. What will be printed?

void dfs(int u, int parent) {
  disc[u] = low[u] = ++time;
  for (int v : adj[u]) {
    if (disc[v] == -1) {
      dfs(v, u);
      low[u] = min(low[u], low[v]);
      if (low[v] > disc[u])
        printf("Bridge: %d - %d\n", u, v);
    } else if (v != parent) {
      low[u] = min(low[u], disc[v]);
    }
  }
}

// Graph edges:
// 0-1, 1-2, 2-0, 1-3
// Start dfs(0, -1);

medium

A. Bridge: 1 - 3

B. Bridge: 0 - 1

C. Bridge: 2 - 0

D. No bridges

Solution

1. Step 1: Analyze the graph structure

   The graph has a triangle 0-1-2 and an edge 1-3. Triangle edges are not bridges because removing them doesn't disconnect the graph.

2. Step 2: Apply Tarjan's condition for bridges

   Edge 1-3 is a bridge because removing it disconnects node 3.

3. Final Answer:

   Bridge: 1 - 3 -> Option A

4. Quick Check:

   Only edge 1-3 disconnects graph [OK]

Hint: Bridges disconnect nodes; triangle edges are safe [OK]

Common Mistakes:

• Thinking all edges in a cycle are bridges
• Ignoring parent check in DFS
• Misinterpreting low and disc values

4. The following code snippet is intended to find bridges using Tarjan's algorithm. What is the bug?

void dfs(int u, int parent) {
  disc[u] = low[u] = ++time;
  for (int v : adj[u]) {
    if (disc[v] == -1) {
      dfs(v, u);
      low[u] = min(low[u], low[v]);
      if (low[v] >= disc[u])
        printf("Bridge: %d - %d\n", u, v);
    } else if (v != parent) {
      low[u] = min(low[u], disc[v]);
    }
  }
}

medium

A. The condition should be low[v] > disc[u], not >=.

B. The disc array is not initialized.

C. The parent parameter is not used correctly.

D. The time variable is not incremented.

Solution

1. Step 1: Understand bridge condition in Tarjan's algorithm

   Bridge condition is low[v] > disc[u], meaning no back edge from v or its descendants to u or above.

2. Step 2: Identify the bug in condition

   Using >= incorrectly marks edges that are not bridges (like parent edges in cycles).

3. Final Answer:

   The condition should be low[v] > disc[u], not >=. -> Option A

4. Quick Check:

   Bridge if low[v] > disc[u] [OK]

Hint: Use strict greater than for bridge check [OK]

Common Mistakes:

• Using >= instead of > in bridge condition
• Not initializing discovery times
• Ignoring parent node in DFS

5. Given a connected undirected graph with 5 nodes and edges: 0-1, 1-2, 2-3, 3-4, 1-4, which edges are bridges according to Tarjan's algorithm?

hard

A. [0-1, 2-3]

B. [2-3, 3-4]

C. [1-4]

D. [0-1]

Solution

1. Step 1: Visualize the graph

   Edges: 0-1, 1-2, 2-3, 3-4, 1-4. The edge 1-4 creates a cycle with 1-2-3-4.

2. Step 2: Identify bridges

   Removing 0-1 disconnects node 0, so 0-1 is a bridge. Edges 2-3 and 3-4 are in cycle with 1-4, so not bridges.

3. Final Answer:

   [0-1] -> Option D

4. Quick Check:

   Only 0-1 disconnects graph [OK]

Hint: Edges in cycles are not bridges [OK]

Common Mistakes:

• Marking cycle edges as bridges
• Ignoring connectivity after edge removal
• Confusing bridge with articulation point