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DSA Cprogramming~10 mins

Pop Using Linked List Node in DSA C - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to pop the top node from the linked list stack.

DSA C
struct Node* pop(struct Node** top) {
    if (*top == NULL) {
        return NULL;
    }
    struct Node* temp = *top;
    *top = [1];
    return temp;
}
Drag options to blanks, or click blank then click option'
A(*top)->next
B(*top)->prev
Ctop->next
Dtop->prev
Attempts:
3 left
💡 Hint
Common Mistakes
Using (*top)->prev instead of (*top)->next.
Using top->next which is incorrect because top is a double pointer.
Not updating the top pointer at all.
2fill in blank
medium

Complete the code to free the popped node after removing it from the stack.

DSA C
void pop_and_free(struct Node** top) {
    if (*top == NULL) {
        return;
    }
    struct Node* temp = *top;
    *top = (*top)->next;
    [1];
}
Drag options to blanks, or click blank then click option'
Afree(temp)
Bfree(*top)
Cfree(temp->next)
Dfree(top)
Attempts:
3 left
💡 Hint
Common Mistakes
Freeing *top instead of temp.
Freeing temp->next which is still part of the stack.
Freeing the double pointer top which is incorrect.
3fill in blank
hard

Fix the error in the pop function to correctly handle empty stack and return the popped node.

DSA C
struct Node* pop(struct Node** top) {
    if ([1]) {
        return NULL;
    }
    struct Node* temp = *top;
    *top = (*top)->next;
    return temp;
}
Drag options to blanks, or click blank then click option'
Atop == NULL
B*top == NULL
C*top != NULL
Dtop != NULL
Attempts:
3 left
💡 Hint
Common Mistakes
Checking top == NULL which checks the pointer to pointer, not the node.
Using != NULL instead of == NULL.
Not checking for empty stack at all.
4fill in blank
hard

Fill both blanks to update the top pointer and detach the popped node from the list.

DSA C
struct Node* pop(struct Node** top) {
    if (*top == NULL) {
        return NULL;
    }
    struct Node* temp = *top;
    *top = [1];
    [2] = NULL;
    return temp;
}
Drag options to blanks, or click blank then click option'
A(*top)->next
B(*top)->prev
Ctemp->next
Dtemp->prev
Attempts:
3 left
💡 Hint
Common Mistakes
Setting temp->next to NULL instead of temp->prev.
Updating top to temp->next instead of (*top)->next.
Not detaching the popped node properly.
5fill in blank
hard

Fill all three blanks to pop the top node, update the top pointer, and free the popped node safely.

DSA C
void pop_and_free(struct Node** top) {
    if (*top == NULL) {
        return;
    }
    struct Node* temp = *top;
    *top = [1];
    if (*top != NULL) {
        [2] = NULL;
    }
    [3];
}
Drag options to blanks, or click blank then click option'
A(*top)->next
B(*top)->prev
Cfree(temp)
Dtemp->next
Attempts:
3 left
💡 Hint
Common Mistakes
Using (*top)->next instead of temp->next to update top.
Not checking if *top is NULL before setting prev.
Freeing *top instead of temp.

Practice

(1/5)
1. What does the pop operation do in a linked list implemented as a stack?
easy
A. Deletes the entire linked list
B. Adds a new node at the end of the linked list
C. Removes and returns the first node (top) of the linked list
D. Returns the last node without removing it

Solution

  1. Step 1: Understand pop operation in stack

    Pop removes the top element from the stack, which is the first node in a linked list stack.
  2. Step 2: Apply to linked list

    In a linked list used as a stack, the first node is removed and returned during pop.
  3. Final Answer:

    Removes and returns the first node (top) of the linked list -> Option C
  4. Quick Check:

    Pop = remove first node [OK]
Hint: Pop removes the first node in linked list stack [OK]
Common Mistakes:
  • Thinking pop removes last node
  • Confusing pop with push
  • Assuming pop deletes entire list
2. Which of the following is the correct syntax to pop a node from a linked list stack in C?
easy
A. node* pop(node** head) { node* temp = *head; *head = (*head)->next; return temp; }
B. node pop(node head) { head = head->next; return head; }
C. void pop(node* head) { head = head->next; }
D. node* pop(node* head) { head = head->next; return head; }

Solution

  1. Step 1: Check parameter passing for head pointer

    To modify the head pointer, we pass a pointer to pointer (node** head).
  2. Step 2: Verify pop logic

    Store current head in temp, move head to next node, return temp node.
  3. Final Answer:

    node* pop(node** head) { node* temp = *head; *head = (*head)->next; return temp; } -> Option A
  4. Quick Check:

    Pointer to pointer needed to update head [OK]
Hint: Use node** to update head pointer in pop [OK]
Common Mistakes:
  • Passing head by value instead of pointer to pointer
  • Returning wrong node or void
  • Not updating head pointer correctly
3. What will be the output of the following code snippet?
typedef struct node { int data; struct node* next; } node;

node* pop(node** head) {
  if (*head == NULL) return NULL;
  node* temp = *head;
  *head = (*head)->next;
  return temp;
}

int main() {
  node n3 = {3, NULL};
  node n2 = {2, &n3};
  node n1 = {1, &n2};
  node* head = &n1;
  node* popped = pop(&head);
  printf("%d -> %d -> %d -> NULL", head->data, head->next->data, head->next->next->data);
  return 0;
}
medium
A. 2 -> 3 -> 0 -> NULL
B. 2 -> 3 -> NULL -> NULL
C. 2 -> 3 -> NULL
D. 2 -> 3 -> (segmentation fault)

Solution

  1. Step 1: Trace pop operation

    Pop removes node with data 1, head now points to node with data 2.
  2. Step 2: Trace printf arguments

    head->data = 2, head->next->data = 3, head->next->next = NULL, accessing ->data causes segmentation fault after printing "2 -> 3 -> " .
  3. Final Answer:

    2 -> 3 -> (segmentation fault) -> Option D
  4. Quick Check:

    Accessing NULL->data causes crash [OK]
Hint: Accessing next of last node causes crash [OK]
Common Mistakes:
  • Assuming NULL prints as 'NULL' string
  • Ignoring segmentation fault on NULL dereference
  • Misreading linked list after pop
4. Identify the bug in this pop function and select the correct fix:
node* pop(node* head) {
  node* temp = head;
  head = head->next;
  return temp;
}
medium
A. Pass head as node** and update *head inside function
B. Return head instead of temp
C. Set temp->next = NULL before return
D. No bug, function is correct

Solution

  1. Step 1: Analyze head pointer update

    Function updates local copy of head, original head outside remains unchanged.
  2. Step 2: Fix pointer update

    Pass pointer to pointer (node**) to modify original head pointer.
  3. Final Answer:

    Pass head as node** and update *head inside function -> Option A
  4. Quick Check:

    Use node** to update head pointer [OK]
Hint: Use node** to update head pointer in pop [OK]
Common Mistakes:
  • Updating local copy of head only
  • Not passing pointer to pointer
  • Returning wrong node
5. Given a linked list stack with nodes containing integers, write the logic to pop all nodes and print their data in order. Which approach is correct?
hard
A. Traverse list without popping and print data
B. Use a loop: while head != NULL, pop node, print data, free node
C. Pop once, print data, then stop
D. Recursively call pop until head is NULL, then print all data after recursion

Solution

  1. Step 1: Understand popping all nodes

    Pop removes top node each time, so loop until list is empty.
  2. Step 2: Print and free nodes in loop

    Print data of popped node immediately, then free memory to avoid leaks.
  3. Final Answer:

    Use a loop: while head != NULL, pop node, print data, free node -> Option B
  4. Quick Check:

    Loop pop-print-free until empty [OK]
Hint: Loop pop until head NULL, print and free each node [OK]
Common Mistakes:
  • Recursing without printing in correct order
  • Not freeing nodes causing memory leaks
  • Stopping after one pop
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10 questions~5 mineasy hard