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DSA Cprogramming~10 mins

Find the Only Non Repeating Element Using XOR in DSA C - Interactive Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to initialize the variable that will hold the XOR result.

DSA C
int unique = [1];
Drag options to blanks, or click blank then click option'
A-1
B1
C0
DNULL
Attempts:
3 left
💡 Hint
Common Mistakes
Initializing unique with 1 or -1 causes wrong results.
2fill in blank
medium

Complete the for loop to iterate over the array elements.

DSA C
for (int i = 0; i [1] n; i++) {
    unique ^= arr[i];
}
Drag options to blanks, or click blank then click option'
A<=
B>=
C>
D<
Attempts:
3 left
💡 Hint
Common Mistakes
Using <= causes out-of-bounds access.
3fill in blank
hard

Fix the error in the XOR operation inside the loop.

DSA C
unique [1] arr[i];
Drag options to blanks, or click blank then click option'
A^=
B-=
C+=
D*=
Attempts:
3 left
💡 Hint
Common Mistakes
Using + or - instead of XOR.
4fill in blank
hard

Fill both blanks to complete the function signature and return statement.

DSA C
int findUnique(int [1][], int [2]) {
    int unique = 0;
    for (int i = 0; i < n; i++) {
        unique ^= arr[i];
    }
    return unique;
}
Drag options to blanks, or click blank then click option'
Aarr
Barray
Cn
Dsize
Attempts:
3 left
💡 Hint
Common Mistakes
Using inconsistent variable names causes errors.
5fill in blank
hard

Fill all three blanks to complete the main function that calls findUnique and prints the result.

DSA C
#include <stdio.h>

int findUnique(int arr[], int n);

int main() {
    int arr[] = {2, 3, 5, 4, 5, 3, 4};
    int n = sizeof(arr) / sizeof([1]);
    int unique = findUnique(arr, [2]);
    printf("Unique element is %[3]d\n", unique);
    return 0;
}
Drag options to blanks, or click blank then click option'
Aarr[0]
Bn
Cd
Di
Attempts:
3 left
💡 Hint
Common Mistakes
Using wrong format specifier or wrong size calculation.

Practice

(1/5)
1. What does the XOR operation help find in an array where every element except one repeats exactly twice?
easy
A. The smallest element
B. The sum of all elements
C. The largest element
D. The only element that does not repeat

Solution

  1. Step 1: Understand XOR properties

    XOR of a number with itself is 0, and XOR with 0 is the number itself.
  2. Step 2: Apply XOR on all elements

    XORing all elements cancels out duplicates, leaving only the unique element.
  3. Final Answer:

    The only element that does not repeat -> Option D
  4. Quick Check:

    XOR cancels duplicates = unique element [OK]
Hint: XOR all elements; duplicates vanish, unique remains [OK]
Common Mistakes:
  • Thinking XOR sums elements
  • Assuming XOR finds max or min
  • Confusing XOR with addition
2. Which of the following is the correct syntax to XOR two integers a and b in C?
easy
A. a | b
B. a & b
C. a ^ b
D. a + b

Solution

  1. Step 1: Identify XOR operator in C

    The caret symbol (^) is the XOR operator in C.
  2. Step 2: Confirm correct usage

    Using a ^ b performs bitwise XOR between integers a and b.
  3. Final Answer:

    a ^ b -> Option C
  4. Quick Check:

    ^ is XOR operator in C [OK]
Hint: Use ^ for XOR in C, not & or | [OK]
Common Mistakes:
  • Using & instead of ^
  • Using | instead of ^
  • Using + instead of ^
3. What is the output of the following C code?
int arr[] = {2, 3, 5, 4, 5, 3, 4};
int result = 0;
for(int i = 0; i < 7; i++) {
    result ^= arr[i];
}
printf("%d", result);
medium
A. 2
B. 5
C. 3
D. 4

Solution

  1. Step 1: XOR all elements in the array

    Calculate XOR stepwise: 0^2=2, 2^3=1, 1^5=4, 4^4=0, 0^5=5, 5^3=6, 6^4=2.
  2. Step 2: Final XOR result is 2

    After XORing all elements, duplicates cancel out, leaving 2.
  3. Final Answer:

    2 -> Option A
  4. Quick Check:

    XOR cancels duplicates = 2 [OK]
Hint: XOR all; duplicates vanish, unique stays [OK]
Common Mistakes:
  • Not XORing all elements
  • Miscomputing XOR steps
  • Assuming sum or max instead
4. Identify the error in this C code snippet that tries to find the unique element using XOR:
int arr[] = {1, 2, 1, 3, 2};
int result = arr[0];
for(int i = 1; i <= 5; i++) {
    result ^= arr[i];
}
printf("%d", result);
medium
A. Loop condition should be < 5, not <= 5
B. Initialize result to 0 instead of arr[0]
C. Use & operator instead of ^
D. Array size is incorrect

Solution

  1. Step 1: Check loop bounds

    Array has 5 elements indexed 0 to 4; loop runs i from 1 to 5 inclusive, causing out-of-bounds access at i=5.
  2. Step 2: Correct loop condition

    Change loop to i < 5 to avoid accessing arr[5] which is invalid.
  3. Final Answer:

    Loop condition should be < 5, not <= 5 -> Option A
  4. Quick Check:

    Array index out of bounds fixed by i < 5 [OK]
Hint: Loop till i < array size, not <= [OK]
Common Mistakes:
  • Using <= instead of < in loop
  • Ignoring array bounds
  • Wrong operator used
5. Given an array where every element repeats twice except one element which repeats thrice, can XOR alone find the unique element? If not, what is the correct approach?
hard
A. Yes; XOR works for any repetition count
B. No; use bit counting and modulo 3 to find the unique element
C. No; use sum of elements minus sum of unique elements
D. Yes; XOR twice and then XOR thrice elements

Solution

  1. Step 1: Understand XOR limitation

    XOR works only when duplicates appear exactly twice; it fails if duplicates appear thrice.
  2. Step 2: Use bit counting method

    Count bits in all numbers, take modulo 3 of each bit count to isolate the unique element's bits.
  3. Final Answer:

    No; use bit counting and modulo 3 to find the unique element -> Option B
  4. Quick Check:

    XOR fails if duplicates appear thrice; bit count works [OK]
Hint: XOR only works for duplicates twice; use bit count mod 3 otherwise [OK]
Common Mistakes:
  • Assuming XOR works for any duplicate count
  • Trying to XOR thrice duplicates
  • Ignoring bit counting approach
Recommended

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10 questions~5 mineasy hard