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DSA Cprogramming~15 mins

Find the Only Non Repeating Element Using XOR in DSA C - Build from Scratch

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Find the Only Non Repeating Element Using XOR
📖 Scenario: Imagine you have a list of numbers where every number appears twice except for one number that appears only once. You want to find that unique number quickly.
🎯 Goal: Build a C program that finds the only number in an array that does not repeat, using the XOR operation.
📋 What You'll Learn
Create an integer array called numbers with the exact values: 4, 1, 2, 1, 2
Create an integer variable called result and initialize it to 0
Use a for loop with variable i to iterate over the array numbers
Inside the loop, update result by XORing it with numbers[i]
Print the value of result which is the only non-repeating element
💡 Why This Matters
🌍 Real World
Finding unique elements quickly is useful in error detection, data cleaning, and network packet analysis.
💼 Career
Understanding bitwise operations like XOR is important for roles in embedded systems, security, and performance-critical software.
Progress0 / 4 steps
1
Create the array of numbers
Create an integer array called numbers with the exact values 4, 1, 2, 1, 2.
DSA C
Hint

Use curly braces to list the numbers inside the array.

2
Initialize the result variable
Create an integer variable called result and set it to 0.
DSA C
Hint

Set result to zero before starting the XOR operations.

3
Use a for loop to XOR all elements
Use a for loop with variable i to iterate over the array numbers. Inside the loop, update result by XORing it with numbers[i].
DSA C
Hint

Use result ^= numbers[i]; inside the loop to XOR each element.

4
Print the only non-repeating element
Write a printf statement to print the value of result.
DSA C
Hint

Use printf("%d\n", result); to print the unique number.