View base class in Django - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ component_behavior

intermediate

What is the output of this Django view?

Consider this Django view class. What will be the HTTP response content when a GET request is made?

Django

from django.http import HttpResponse
from django.views import View

class HelloView(View):
    def get(self, request):
        return HttpResponse('Hello, world!')

A The response content will be empty

B The response will be a 500 Internal Server Error

C The response will be a 404 Not Found error

D The response content will be 'Hello, world!'

💡 Hint

Look at the get method and what it returns.

The get method returns an HttpResponse with the text 'Hello, world!'. So the response content is exactly that string.

❓ lifecycle

intermediate

Which method is called first when a request hits a Django View class?

Given a Django View class, which method is called first when processing any HTTP request?

Django

from django.views import View

class SampleView(View):
    def dispatch(self, request, *args, **kwargs):
        # some code
        pass
    def get(self, request):
        # some code
        pass

A as_view

B dispatch

C __init__

D get

💡 Hint

Think about how Django routes requests to methods.

The dispatch method is called first to route the request to the correct handler like get or post.

📝 Syntax

advanced

What error does this Django View code raise?

Analyze this Django View code. What error will it raise when a GET request is made?

Django

from django.views import View
from django.http import HttpResponse

class BrokenView(View):
    def get(self, request):
        return HttpResponse('OK')
    def get(self, request, extra):
        return HttpResponse('Extra OK')

A TypeError: get() missing 1 required positional argument: 'extra'

B SyntaxError: duplicate method definition

C No error, returns 'Extra OK'

D AttributeError: 'BrokenView' object has no attribute 'get'

💡 Hint

Python does not allow two methods with the same name in a class.

The second get method overwrites the first. Django calls get with only request, but the method expects two arguments, causing TypeError.

❓ state_output

advanced

What is the value of 'self.counter' after two GET requests?

Given this Django View class, what is the value of 'self.counter' after handling two separate GET requests?

Django

from django.views import View
from django.http import HttpResponse

class CounterView(View):
    counter = 0

    def get(self, request):
        self.counter += 1
        return HttpResponse(str(self.counter))

A 1

B 2

C 0

D Raises AttributeError

💡 Hint

Think about how Django creates view instances per request.

Django creates a new instance of the view class for each request, so 'self.counter' starts at 0 each time and increments to 1.

🔧 Debug

expert

Why does this Django View raise a 405 Method Not Allowed error?

This Django View raises a 405 error on POST requests. Why?

Django

from django.views import View
from django.http import HttpResponse

class MyView(View):
    def get(self, request):
        return HttpResponse('GET OK')

A Because HttpResponse is not imported

B Because the get() method raises an exception on POST

C Because there is no post() method defined to handle POST requests

D Because the dispatch method is missing

💡 Hint

Check which HTTP methods the view supports.

Django's View class returns 405 if the HTTP method is not implemented as a method in the view class.