Process request and process response in Django - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to import the Django HttpResponse class.

Django

from django.http import [1]

Drag options to blanks, or click blank then click option'

AHttpRequest

BHttpResponse

CHttpServer

DHttpClient

Attempts:

3 left

💡 Hint

Common Mistakes

Importing HttpRequest instead of HttpResponse

Using HttpServer which does not exist in Django

Confusing HttpClient with HttpResponse

The HttpResponse class is used to send a response back to the client in Django.

2fill in blank

medium

Complete the code to define a Django view function that takes a request parameter.

Django

def my_view([1]):
    return HttpResponse('Hello World')

Drag options to blanks, or click blank then click option'

Arequest

Bresponse

Cself

Dcontext

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'response' as the parameter name

Using 'self' in a function-based view

Using 'context' which is usually for templates

The first parameter of a Django view function is usually request, representing the incoming HTTP request.

3fill in blank

hard

Fix the error in the code to return a plain text response with status code 404.

Django

from django.http import HttpResponse

def not_found_view(request):
    return HttpResponse('Page not found', [1]=404)

Drag options to blanks, or click blank then click option'

Acode

Bstatus

Cstatus_code

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'status' instead of 'status_code'

Using 'code' which is invalid

Using duplicate 'status_code' options

The correct keyword argument to set the HTTP status code in HttpResponse is status_code.

4fill in blank

hard

Fill both blanks to access a GET parameter named 'name' from the request.

Django

def greet_view(request):
    name = request.[1].get('[2]', 'Guest')
    return HttpResponse(f'Hello, {name}!')

Drag options to blanks, or click blank then click option'

AGET

BPOST

Cname

Duser

Attempts:

3 left

💡 Hint

Common Mistakes

Using POST instead of GET for URL parameters

Using wrong parameter name like 'user'

Forgetting to use quotes around the parameter name

GET parameters are accessed via request.GET. The parameter name here is 'name'.

5fill in blank

hard

Fill all three blanks to create a JSON response with a dictionary containing a message.

Django

from django.http import JsonResponse

def json_view(request):
    data = [1](message='Hello')
    return [2](data, safe=[3])

Drag options to blanks, or click blank then click option'

Adict

BJsonResponse

CTrue

Dlist

Attempts:

3 left

💡 Hint

Common Mistakes

Using list instead of dict for data

Returning HttpResponse instead of JsonResponse

Setting safe to False when sending a dictionary

We create a dictionary with dict, then return it with JsonResponse. The safe parameter must be True when passing a dictionary.