ListView for displaying collections in Django - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ component_behavior

intermediate

What does this Django ListView render?

Given the following ListView, what will be the name of the context variable containing the list of objects in the template?

Django

from django.views.generic import ListView
from .models import Book

class BookListView(ListView):
    model = Book
    template_name = 'books/book_list.html'

A book_list

B books

C object_list

D book_objects

💡 Hint

Think about the default context variable name when only model is specified.

When you specify only the model in a ListView, Django uses 'object_list' as the default context variable name for the list of objects.

❓ state_output

intermediate

How many items will be displayed by this ListView?

Assuming the Book model has 10 entries in the database, and the ListView is defined as below, how many books will appear on the page?

Django

from django.views.generic import ListView
from .models import Book

class BookListView(ListView):
    model = Book
    paginate_by = 3
    template_name = 'books/book_list.html'

A 10

B 3

C None (all books)

D 0

💡 Hint

Check the paginate_by attribute and how it limits items per page.

The paginate_by attribute limits the number of items per page to 3, so only 3 books will be shown on the first page.

📝 Syntax

advanced

Which option correctly overrides the queryset in a ListView?

You want to display only books published after 2020. Which code correctly overrides the queryset method in a ListView?

Django

from django.views.generic import ListView
from .models import Book

class RecentBookListView(ListView):
    model = Book
    template_name = 'books/recent_books.html'

    def get_queryset(self):
        # Your code here
        pass

A return self.model.objects.filter(published_year > 2020)

B return self.get_queryset().filter(published_year__gt=2020)

C return Book.objects.filter(published_year > 2020)

D return Book.objects.filter(published_year__gt=2020)

💡 Hint

Use Django ORM filter syntax with double underscores for field lookups.

Option D correctly uses the Django ORM filter with double underscore syntax and accesses the model manager properly.

🔧 Debug

advanced

Why does this ListView raise an AttributeError?

Consider this ListView code snippet. Why does it raise 'AttributeError: 'NoneType' object has no attribute 'filter'' when accessed?

Django

from django.views.generic import ListView
from .models import Book

class FilteredBookListView(ListView):
    queryset = None

    def get_queryset(self):
        return self.queryset.filter(author='Alice')

A Because queryset is set to None, so calling filter on None causes the error.

B Because get_queryset should not be defined when queryset is set.

C Because author='Alice' is invalid syntax in filter.

D Because ListView requires model attribute when queryset is None.

💡 Hint

Check the value of queryset before calling filter on it.

The queryset attribute is None, so calling filter on None causes the AttributeError.

🧠 Conceptual

expert

What is the effect of setting context_object_name in a ListView?

If you set context_object_name = 'books' in a ListView, what changes in the template rendering?

A The list of objects will be available in the template as 'books' instead of the default 'object_list'.

B The template name will automatically change to 'books.html'.

C The ListView will only display objects of type 'books'.

D The pagination will be disabled automatically.

💡 Hint

Think about how context variables are named in templates.

Setting context_object_name changes the variable name used in the template to access the list of objects.