Why login handling speeds up test suites in Cypress - Quick Recap

Recall & Review

beginner

What is the main reason to handle login outside of each test in Cypress?

Handling login outside each test avoids repeating the login process, which saves time and makes tests run faster.

beginner

How does caching login state improve test suite speed?

Caching login state means tests reuse the logged-in session, so they don't need to perform login steps every time.

intermediate

What Cypress feature helps to speed up tests by handling login once?

Cypress supports custom commands and session management to handle login once and reuse it across tests.

intermediate

Why is avoiding UI login steps in every test beneficial?

UI login steps are slow and can cause flakiness; avoiding them makes tests more stable and faster.

advanced

What is a common method to speed up login handling in Cypress tests?

A common method is to programmatically log in via API and set the session cookie directly, skipping UI login.

Why should you avoid logging in through the UI in every Cypress test?

A Because UI login disables caching

B Because UI login is more secure

C Because UI login is required for every test

D Because UI login is slow and repeats unnecessary steps

UI login takes time and repeating it in every test slows down the suite.

What does caching login state in Cypress tests do?

A Runs login steps multiple times

B Reuses the logged-in session to save time

C Deletes cookies after each test

D Disables test parallelization

Caching login state lets tests reuse the session, avoiding repeated login.

Which Cypress feature helps to handle login once for many tests?

A Using only UI clicks

B Disabling cookies

C Custom commands and session management

D Running tests sequentially

Custom commands and session management allow login to be done once and reused.

How can you speed up login handling in Cypress without UI steps?

A By programmatically logging in via API and setting cookies

B By manually typing credentials each time

C By disabling login

D By increasing test timeout

Programmatic login via API and setting cookies skips slow UI login.

What is a benefit of avoiding repeated UI login in tests?

A Tests become faster and more stable

B Tests become flaky

C Tests become slower

D Tests require more manual steps

Avoiding repeated UI login makes tests faster and reduces flakiness.

Explain why handling login outside of each test speeds up Cypress test suites.

Think about what happens if you log in every time versus once.

Describe a method to implement fast login handling in Cypress tests.

Consider how to skip the UI login steps.

Practice

1. Why does handling login with cy.session() speed up Cypress test suites?

easy

A. Because it skips all tests except login tests

B. Because it runs login steps twice to ensure reliability

C. Because it caches the login state and avoids repeating login steps in every test

D. Because it disables authentication for faster tests

Solution

1. Step 1: Understand what cy.session() does

   cy.session() caches the login session so Cypress does not need to perform login steps repeatedly.

2. Step 2: Identify the effect on test speed

   By caching login, tests skip slow login steps, making the suite run faster overall.

3. Final Answer:

   Because it caches the login state and avoids repeating login steps in every test -> Option C

4. Quick Check:

   Login caching = faster tests [OK]

Hint: Login caching skips repeated steps for speed [OK]

Common Mistakes:

• Thinking login steps are skipped entirely
• Believing login runs twice for reliability
• Assuming authentication is disabled

2. Which is the correct syntax to cache a login session in Cypress?

easy

A. cy.saveSession('user', () => { cy.visit('/login') })

B. cy.cacheSession('user', () => { cy.visit('/login') })

C. cy.loginCache('user', () => { cy.visit('/login') })

D. cy.session('user', () => { cy.visit('/login') })

Solution

1. Step 1: Recall Cypress API for session caching

   The correct Cypress command to cache sessions is cy.session().

2. Step 2: Match syntax with options

   Only cy.session('user', () => { cy.visit('/login') }) uses cy.session() correctly with a session name and callback.

3. Final Answer:

   cy.session('user', () => { cy.visit('/login') }) -> Option D

4. Quick Check:

   Correct command is cy.session() [OK]

Hint: Remember exact Cypress command: cy.session() [OK]

Common Mistakes:

• Using non-existent commands like cy.cacheSession()
• Confusing session caching with login commands
• Misspelling the method name

3. Given this Cypress test code, what will be the effect on test suite speed?

beforeEach(() => {
  cy.session('user', () => {
    cy.visit('/login')
    cy.get('#username').type('user')
    cy.get('#password').type('pass')
    cy.get('button[type=submit]').click()
  })
})

it('checks dashboard', () => {
  cy.visit('/dashboard')
  cy.contains('Welcome')
})

medium

A. The login steps run only once, speeding up all tests

B. The login steps run before every test, slowing down the suite

C. The login steps are skipped, causing test failures

D. The login steps run twice per test for safety

Solution

1. Step 1: Understand cy.session() behavior in beforeEach

   cy.session() caches the login session so the login steps run only once, even if called in beforeEach.

2. Step 2: Analyze impact on test speed

   Because login runs once, subsequent tests reuse the session, speeding up the suite.

3. Final Answer:

   The login steps run only once, speeding up all tests -> Option A

4. Quick Check:

   cy.session() caches login = faster tests [OK]

Hint: cy.session() runs login once, not every test [OK]

Common Mistakes:

• Assuming login runs before every test
• Thinking login steps are skipped entirely
• Believing login runs multiple times per test

4. You wrote this Cypress code to cache login but tests still run login steps every time:

beforeEach(() => {
  cy.session('user', () => {
    cy.visit('/login')
    cy.get('#username').type('user')
    cy.get('#password').type('pass')
    cy.get('button[type=submit]').click()
  })
})

What is the likely mistake?

medium

A. Using cy.session inside beforeEach instead of before

B. Not returning a value or promise inside the cy.session callback

C. Missing cy.clearCookies() before cy.session

D. Not calling cy.login() instead of cy.session()

Solution

1. Step 1: Check cy.session() callback requirements

   The callback must return a Cypress chainable or promise to signal completion for caching.

2. Step 2: Identify why login runs every time

   If the callback does not return, Cypress cannot cache the session, so login runs every test.

3. Final Answer:

   Not returning a value or promise inside the cy.session callback -> Option B

4. Quick Check:

   Return chainable in cy.session callback [OK]

Hint: Always return Cypress commands inside cy.session callback [OK]

Common Mistakes:

• Putting cy.session in beforeEach is allowed and not a mistake
• Assuming clearing cookies is required before session
• Confusing cy.login() with cy.session()

5. You want to speed up a test suite with 10 tests that require login. Which approach best uses cy.session() to optimize speed and reliability?

hard

A. Use cy.session() once in a before hook to cache login for all tests

B. Use cy.session() inside each test to cache login separately

C. Avoid cy.session() and run full login steps in every test

D. Use cy.session() in afterEach to cache login after tests

Solution

1. Step 1: Understand before vs beforeEach hooks

   before runs once before all tests, beforeEach runs before every test.

2. Step 2: Choose best place for cy.session()

   Using cy.session() in before caches login once, speeding up all 10 tests reliably.

3. Final Answer:

   Use cy.session() once in a before hook to cache login for all tests -> Option A

4. Quick Check:

   Cache login once before all tests [OK]

Hint: Place cy.session() in before hook for all tests [OK]

Common Mistakes:

• Caching login inside each test wastes time
• Running full login every test is slow
• Using afterEach is too late for caching