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C++programming~10 mins

Why operators are needed in C++ - Test Your Understanding

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to add two integers and print the result.

C++
#include <iostream>
int main() {
    int a = 5, b = 3;
    int sum = a [1] b;
    std::cout << sum << std::endl;
    return 0;
}
Drag options to blanks, or click blank then click option'
A-
B+
C*
D/
Attempts:
3 left
💡 Hint
Common Mistakes
Using subtraction - instead of addition.
Using multiplication * or division / by mistake.
2fill in blank
medium

Complete the code to compare if two numbers are equal.

C++
#include <iostream>
int main() {
    int x = 10, y = 10;
    if (x [1] y) {
        std::cout << "Equal" << std::endl;
    } else {
        std::cout << "Not equal" << std::endl;
    }
    return 0;
}
Drag options to blanks, or click blank then click option'
A==
B<
C>
D!=
Attempts:
3 left
💡 Hint
Common Mistakes
Using assignment = instead of comparison ==.
Using inequality != by mistake.
3fill in blank
hard

Fix the error in the code to multiply two numbers correctly.

C++
#include <iostream>
int main() {
    int a = 4, b = 5;
    int product = a [1] b;
    std::cout << product << std::endl;
    return 0;
}
Drag options to blanks, or click blank then click option'
A-
B+
C*
D/
Attempts:
3 left
💡 Hint
Common Mistakes
Using addition + or subtraction - instead of multiplication.
Using division / by mistake.
4fill in blank
hard

Fill both blanks to create a dictionary-like structure using a map and check if a key exists.

C++
#include <iostream>
#include <string>
#include <map>
int main() {
    std::map<std::string, int> scores;
    scores["Alice"] = 90;
    if (scores.[1]("Alice") [2] scores.end()) {
        std::cout << "Alice's score is " << scores["Alice"] << std::endl;
    }
    return 0;
}
Drag options to blanks, or click blank then click option'
Afind
B==
C!=
Dcount
Attempts:
3 left
💡 Hint
Common Mistakes
Using count method incorrectly here.
Using equality == instead of not equal !=.
5fill in blank
hard

Fill all three blanks to create a conditional expression that checks if a number is positive, negative, or zero.

C++
#include <iostream>
#include <string>
int main() {
    int num = -5;
    std::string result = (num [1] 0) ? "Positive" : ((num [2] 0) ? "Negative" : (num [3] 0 ? "Zero" : "Error"));
    std::cout << result << std::endl;
    return 0;
}
Drag options to blanks, or click blank then click option'
A>
B<
C==
D!=
Attempts:
3 left
💡 Hint
Common Mistakes
Mixing up greater than and less than operators.
Using not equal != instead of equal == for zero check.

Practice

(1/5)
1. Why do we need operators like + and - in C++?
easy
A. To perform calculations like addition and subtraction
B. To write comments in the code
C. To define new functions
D. To create variables

Solution

  1. Step 1: Understand the role of operators

    Operators like + and - are symbols that perform mathematical operations.
  2. Step 2: Identify what these operators do

    The + operator adds numbers, and - subtracts numbers, enabling calculations in code.
  3. Final Answer:

    To perform calculations like addition and subtraction -> Option A
  4. Quick Check:

    Operators do math = To perform calculations like addition and subtraction [OK]
Hint: Operators do math and comparisons in code [OK]
Common Mistakes:
  • Thinking operators create variables
  • Confusing operators with comments
  • Believing operators define functions
2. Which of the following is the correct way to use the multiplication operator in C++?
easy
A. int result = 5 * 3;
B. int result = 5 + 3;
C. int result = 5 . 3;
D. int result = 5 x 3;

Solution

  1. Step 1: Recall the multiplication operator symbol

    In C++, the multiplication operator is *, not x or ..
  2. Step 2: Check the syntax of each option

    int result = 5 * 3; uses * correctly between two numbers, making it valid syntax.
  3. Final Answer:

    int result = 5 * 3; -> Option A
  4. Quick Check:

    Multiplication uses * symbol = int result = 5 * 3; [OK]
Hint: Use * for multiplication, not x or dot [OK]
Common Mistakes:
  • Using 'x' instead of '*' for multiplication
  • Using '.' as operator
  • Confusing addition '+' with multiplication
3. What is the output of this C++ code?
int a = 10;
int b = 3;
int c = a % b;
std::cout << c;
medium
A. Syntax error
B. 3
C. 0
D. 1

Solution

  1. Step 1: Understand the modulus operator

    The % operator gives the remainder of division. Here, 10 divided by 3 leaves remainder 1.
  2. Step 2: Calculate the remainder

    10 % 3 = 1, so c is assigned 1, which is printed.
  3. Final Answer:

    1 -> Option D
  4. Quick Check:

    10 % 3 = 1 [OK]
Hint: Modulus % gives remainder after division [OK]
Common Mistakes:
  • Confusing % with division
  • Expecting quotient instead of remainder
  • Thinking output is syntax error
4. Identify the error in this C++ code snippet:
int x = 5;
int y = 10;
int z = x + y - ;
std::cout << z;
medium
A. Wrong use of semicolon
B. Missing operand after '-' operator
C. Incorrect variable declaration
D. No error, code runs fine

Solution

  1. Step 1: Check the expression after assignment

    The expression x + y - ; ends with a minus operator but no number or variable after it.
  2. Step 2: Understand operator requirements

    Operators like - need two operands. Missing the second operand causes a syntax error.
  3. Final Answer:

    Missing operand after '-' operator -> Option B
  4. Quick Check:

    Operator needs two values = Missing operand after '-' operator [OK]
Hint: Operators need two values; check for missing operands [OK]
Common Mistakes:
  • Ignoring missing operand errors
  • Thinking semicolon causes error
  • Assuming variable declaration is wrong
5. You want to check if a number n is even or odd in C++. Which operator helps you do this efficiently?
hard
A. The multiplication operator *
B. The addition operator +
C. The modulus operator %
D. The assignment operator =

Solution

  1. Step 1: Understand the problem of checking even or odd

    A number is even if it divides by 2 with zero remainder, odd otherwise.
  2. Step 2: Identify the operator that gives remainder

    The modulus operator % returns the remainder after division, so n % 2 tells if n is even or odd.
  3. Final Answer:

    The modulus operator % -> Option C
  4. Quick Check:

    Use % 2 to check even/odd = The modulus operator % [OK]
Hint: Use % 2 to test even or odd numbers quickly [OK]
Common Mistakes:
  • Using + or * instead of %
  • Confusing assignment with comparison
  • Not understanding remainder concept
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