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C++programming~10 mins

Switch statement in C++ - Step-by-Step Execution

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Concept Flow - Switch statement
Start
Evaluate expression
Match case?
NoDefault case?
Execute case
Break?
NoContinue to next case
Yes
Exit switch
The switch statement evaluates an expression, matches it to a case, executes that case's code, and exits or continues based on break statements.
Execution Sample
C++
#include <iostream>
using namespace std;

int day = 3;
switch(day) {
  case 1: cout << "Monday"; break;
  case 2: cout << "Tuesday"; break;
  case 3: cout << "Wednesday"; break;
  default: cout << "Invalid day";
}
This code prints the name of the day based on the integer value of 'day'.
Execution Table
StepExpression ValueCase CheckedMatch?ActionOutput
13case 1NoSkip
23case 2NoSkip
33case 3YesExecute and breakWednesday
4---Exit switch
💡 Break after case 3 causes exit from switch.
Variable Tracker
VariableStartAfter switch
day33
Key Moments - 3 Insights
Why does the switch stop after printing "Wednesday"?
Because the 'break' statement after case 3 stops further case checks and exits the switch (see execution_table step 3).
What happens if there is no 'break' after a case?
Execution continues to the next case's code until a break or the switch ends, causing multiple outputs (not shown here but important).
When is the 'default' case executed?
Only if no case matches the expression value, then the default code runs (not triggered in this example).
Visual Quiz - 3 Questions
Test your understanding
Look at the execution table, which case matches the expression value?
Acase 3
Bcase 2
Ccase 1
Ddefault
💡 Hint
Check the 'Match?' column in the execution_table rows.
At which step does the switch statement exit?
AStep 2
BStep 4
CStep 3
DAfter default case
💡 Hint
Look at the 'Action' column for when 'Exit switch' happens.
If the 'break' after case 3 was removed, what would happen?
AOnly case 3 executes
BSwitch exits immediately
CExecution continues to default case
DCompilation error
💡 Hint
Recall that without break, execution falls through to next cases.
Concept Snapshot
switch(expression) {
  case value1: 
    // code
    break;
  case value2:
    // code
    break;
  default:
    // code
}

- Evaluates expression once
- Matches cases in order
- Executes matched case
- 'break' exits switch
- 'default' runs if no match
Full Transcript
A switch statement evaluates an expression and compares it to multiple cases. It runs the code for the matching case and stops if it finds a break statement. If no case matches, it runs the default case if present. In the example, the variable 'day' is 3, so the switch matches case 3 and prints 'Wednesday'. The break after case 3 stops the switch from running other cases. Without break, the switch would continue running the next cases until it finds a break or ends. This helps choose between many options clearly and efficiently.